Chapter 6, Problem 145QP

Interpretation Introduction

Interpretation:

The heat change when $36.0\text{ g}$ sample of water $\left(C=4.184\text{g}/°\text{C}\right)$ cooled from $80.0°\text{C}$ to $25.0°\text{C}$ is to be determined. Whether the heat is released or absorbed by water is to be determined.

Introduction:

The calculation of the heat change can be expressed as follows:

$\Delta q=mC\Delta T$

Here, $\Delta q$ is the heat change, $C$ is the specific heat capacity, and $\Delta T$ is the temperature difference.