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a)
Interpretation:
The ranking of the substituent is to done from the following sets of substituent.
Concept introduction:
Rule 1:
a) Higher
b) An atom node duplicated closer to the root ranks higher than one duplicated further.
Rule 2: Higher
Rule 3: Z precedes E and this precedes nonstereogenic (nst) double bonds.
Rule 4:
a) Chiral stereogenic units precede pseudoasymmetric stereogenic units and these precede nonstereogenic units (R = S > r = s > nst).
b) When two ligards have different descriptor pairs, the one with the first chosen like descriptor pairs has priority over the one with a corresponding unlike descriptor pairs.
c) r precedes s.
Rule 5: An atom or group with descriptor R has priority over its enantiomorph S.
b)
Interpretation:
The ranking of the substituent is to done from the following sets of substituent.
Concept introduction:
Rule 1:
a) Higher atomic number precedes lower.
b) An atom node duplicated closer to the root ranks higher than one duplicated further.
Rule 2: Higher atomic mass number precedes lower.
Rule 3: Z precedes E and this precedes nonstereogenic (nst) double bonds.
Rule 4:
a) Chiral stereogenic units precede pseudoasymmetric stereogenic units and these precede nonstereogenic units (R = S > r = s > nst).
b) When two ligards have different descriptor pairs, the one with the first chosen like descriptor pairs has priority over the one with a corresponding unlike descriptor pairs.
c) r precedes s.
Rule 5: An atom or group with descriptor R has priority over its enantiomorph S.
c)
Interpretation:
The ranking of the substituent is to done from the following sets of substituent.
Concept introduction:
Rule 1:
a) Higher atomic number precedes lower.
b) An atom node duplicated closer to the root ranks higher than one duplicated further.
Rule 2: Higher atomic mass number precedes lower.
Rule 3: Z precedes E and this precedes nonstereogenic (nst) double bonds.
Rule 4:
a) Chiral stereogenic units precede pseudoasymmetric stereogenic units and these precede nonstereogenic units (R = S > r = s > nst).
b) When two ligards have different descriptor pairs, the one with the first chosen like descriptor pairs has priority over the one with a corresponding unlike descriptor pairs.
c) r precedes s.
Rule 5: An atom or group with descriptor R has priority over its enantiomorph S.
d)
Interpretation:
The ranking of the substituent is to done from the following sets of substituent.
Concept introduction:
Rule 1:
a) Higher atomic number precedes lower.
b) An atom node duplicated closer to the root ranks higher than one duplicated further.
Rule 2: Higher atomic mass number precedes lower.
Rule 3: Z precedes E and this precedes nonstereogenic (nst) double bonds.
Rule 4:
a) Chiral stereogenic units precede pseudoasymmetric stereogenic units and these precede nonstereogenic units (R = S > r = s > nst).
b) When two ligards have different descriptor pairs, the one with the first chosen like descriptor pairs has priority over the one with a corresponding unlike descriptor pairs.
c) r precedes s.
Rule 5: An atom or group with descriptor R has priority over its enantiomorph S.
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Chapter 5 Solutions
OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card for McMurry's Organic Chemistry, 9th
- Predict the major organic product(s), if any, of the following reactions. Assume all reagents are in excess unless otherwise indicated.arrow_forwardHow many signals would you expect to find in the 1 H NMR spectrum of each given compound? Part 1 of 2 2 Part 2 of 2 HO 5 ☑ Х IIIIII***** §arrow_forwardA carbonyl compound has a molecular ion with a m/z of 86. The mass spectra of this compound also has a base peak with a m/z of 57. Draw the correct structure of this molecule. Drawingarrow_forward
- Can you draw this using Lewis dot structures and full structures in the same way they are so that I can better visualize them and then determine resonance?arrow_forwardSynthesize the following compound from cyclohexanol, ethanol, and any other needed reagentsarrow_forwardFor a titration of 20.00 mL of 0.0500 M H2SO4 with 0.100 M KOH, calculate the pH at each of the following volume of KOH used in the titration: 1) before the titration begin; 2) 10.00 mL; 3) 20.00 mL; 4) 30.00 mL. Ka2 = 1.20×10-2 for H2SO4.arrow_forward
- Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s) Be sure to account for all bond-breaking and bond-making steps Problem 73 of 10 Drawing Amows ro HO Donearrow_forward12. Synthesize the following target molecules (TMs) using the specified starting materials. .CI a) HO3S SM TM b) HO- SMarrow_forwardFor a titration of 20.00 mL of 0.0500 M H2SO4 with 0.100 M KOH, calculate the pH at each of the following volume of KOH used in the titration: 1) before the titration begin; 2) 10.00 mL; 3) 20.00 mL; 4) 30.00 mL. Ka2 = 1.20×10-2 for H2SO4.arrow_forward
- Write the systematic name of each organic molecule: structure name show work. don't give Ai generated solutionarrow_forwardShow work with explanation needed. Don't give Ai generated solutionarrow_forwardA Elschboard Part of SpeechT-D Alt Leaming App app.aktiv.com Curved arrows are used to illustrate the flow of electrons. Using the provided resonance structures, draw the curved electron- pushing arrows to show the interconversion between resonance hybrid contributors. Be sure to account for all bond-breaking and bond-making steps. Include all lone pairs and formal charges in the structures. Problem 45 of 10 I Select to Add Arrows N Please selarrow_forward
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning
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