For u = ( 0 , 3 , 1 3 ) and v = ( 4 3 , 1 , − 3 ) , (a) find the inner product represented by 〈 u , v 〉 = 2 u 1 v 1 + u 2 v 2 + 2 u 3 v 3 and (b) use this inner product to find the distance between u and v .
For u = ( 0 , 3 , 1 3 ) and v = ( 4 3 , 1 , − 3 ) , (a) find the inner product represented by 〈 u , v 〉 = 2 u 1 v 1 + u 2 v 2 + 2 u 3 v 3 and (b) use this inner product to find the distance between u and v .
Solution Summary: The author explains the method to find the inner product of the given vectors, langle u,vrangle =2u_1.
For
u
=
(
0
,
3
,
1
3
)
and
v
=
(
4
3
,
1
,
−
3
)
, (a) find the inner product represented by
〈
u
,
v
〉
=
2
u
1
v
1
+
u
2
v
2
+
2
u
3
v
3
and (b) use this inner product to find the distance between
u
and
v
.
Find the cross product a × b.
a = j + 6k, b = 3i − j + 5k
Verify that it is orthogonal to both a and b.
(a × b) · a
=
(a × b) · b
=
Calculate the triple scalar products w. (v × u) and u ⋅ (w × v), where u = (7, 2, −1), v =
w. (vx u) = 330
= (2, 8, -3), and w =
u. (w x v) = 350
= (9, 8, -10).
Chapter 5 Solutions
Bundle: Elementary Linear Algebra, Loose-leaf Version, 8th + WebAssign Printed Access Card for Larson's Elementary Linear Algebra, 8th Edition, Single-Term
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.