EBK ELECTRIC MOTOR CONTROL
10th Edition
ISBN: 9780100784598
Author: Herman
Publisher: YUZU
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Textbook Question
Chapter 59, Problem 2SQ
Why should the motor be run for a period of time following checkout?
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Chapter 59 Solutions
EBK ELECTRIC MOTOR CONTROL
Ch. 59 - Prob. 1SQCh. 59 - Why should the motor be run for a period of time...Ch. 59 - What may occur if a jumper is placed across coil M...Ch. 59 - In what position do ball-bearing motors function?Ch. 59 - Motors will operate satisfactorily at what percent...Ch. 59 - What basic sensory faculties should a...Ch. 59 - What is an orderly step-by-step procedure in...Ch. 59 - What might be a hazard if a motor is started in...Ch. 59 - Prob. 9SQCh. 59 - What are the probable causes of a noisy magnet?
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- 5. Find the Transfer Function of the following circuit. Prove that it’s a low pass filter, show all steps.arrow_forward2. Find the transfer function, show all steps.arrow_forwardI have this fsk function code: function [x]=fsk_encode(b,s,f0,f1,N,Fs,K) % b= bit sequence vector % s(1)= output level for 0 % s(2)= output level for 1 % N= length of bit sequence % Fs= Sampling frequency y=zeros(1,N*K); %Setup output vector %for each bit calculatee the rando samples for n=1:N for k=1:K t = (k - 1) / Fs; if(b(n)==0) y((n-1)*K+k)=cos(2*pi*f0*t); % pulse=0 else y((n-1)*K+k)=cos(2*pi*f1*t); % pulse=1 end end x=y; %set output end And this is another code that calls the function in order to get the power density spectrum: clc;clear; % EE 382 Communication Systems- Lab 8 % Plots the power spectrum of the ASK modulation % First specify some parameters N=256; % number of bits per realization M=100; % number of realizations in the ensemble T=0.001; % bit duration in seconds delf =2e+3; fc=10e+3; f0=fc-delf; f1=fc+delf; Fs=8*f1; % sampling frequency (this is needed to calibrate the frequency axis) K=(T/(1/Fs)); % Define arrays for bit sequences and sampled waveforms…arrow_forward
- Calculate the parameters in the figurearrow_forwardWrite the angle expression form of first null beam width FNBW) for 2/2 dipole. for 즐, 꽃 3arrow_forwardThe circuit is in the DC steady state, So all transients are passed. What are the values of 1 and V, under those conditions. P 24v + + √2 АЛАД 42 4F 3.H ww 22 eee + 203 Varrow_forward
- Find the value of Vc (t) for all I That is, the complete response including natural and forced responses.) АДДА 422 OV ДААД t = 0 3F + V(t) -arrow_forward1.0 Half-power point (left) 0.5 Minor lobes Main lobe maximum direction Main lobe Half-power point (right) Half-power beamwidth (HP) Beamwidth between first nulls (BWFN) *Which of the following Lobes of an antenna Pattern 180 out of Phase the main Lobe ? And where are the ch other gems ?arrow_forwardThe normalized radiation intensity of an antenna is represented by U(0) = cos² (0) cos² (30), w/sr Find the a. half-power beamwidth HPBW (in radians and degrees) b. first-null beamwidth FNBW (in radians and degrees)arrow_forward
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