PUTNAM EXAM CHALLENGE Prove or disprove: there is at least one straight line normal to the graph of y = cosh x at a point (a, cosh a) and also normal to the graph of y = sinh x at a point (c, sinh c). [ At a point on a graph, the normal line is the perpendicular to the tangent at that point. Also, cosh x = ( e x + e − x ) / 2 and sinh x = ( e x − e − x ) / 2 .]
PUTNAM EXAM CHALLENGE Prove or disprove: there is at least one straight line normal to the graph of y = cosh x at a point (a, cosh a) and also normal to the graph of y = sinh x at a point (c, sinh c). [ At a point on a graph, the normal line is the perpendicular to the tangent at that point. Also, cosh x = ( e x + e − x ) / 2 and sinh x = ( e x − e − x ) / 2 .]
Solution Summary: The author proves or disproves that there is at least a straight-line which is normal to the graph of y=mathrmcoshx.
Prove or disprove: there is at least one straight line normal to the graph of
y
=
cosh
x
at a point (a, cosh a) and also normal to the graph of
y
=
sinh
x
at a point (c, sinh c).
[ At a point on a graph, the normal line is the perpendicular to the tangent at that point. Also,
cosh
x
=
(
e
x
+
e
−
x
)
/
2
and
sinh
x
=
(
e
x
−
e
−
x
)
/
2
.]
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Fundamental Theorem of Calculus 1 | Geometric Idea + Chain Rule Example; Author: Dr. Trefor Bazett;https://www.youtube.com/watch?v=hAfpl8jLFOs;License: Standard YouTube License, CC-BY