Electric Motor Control
10th Edition
ISBN: 9781133702818
Author: Herman
Publisher: CENGAGE L
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Chapter 58, Problem 5SQ
What is the major advantage of the lighted “on” or “off” program entered into the program terminal?
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A 60hp,3-phase motor absorbs 50 kW from a 600 V,3-phase line. If the line current is 60 A, calculate the following: a. The efficiency of the motor b. The apparent power absorbed by the motor c. The reactive power absorbed by the motor and the power factor of the motor
Three 15Ω resistors and three 8Ω reactors are connected as shown in Fig. 18. If the line voltage is 530 V, calculate the following: a. The active, reactive, and apparent power supplied to the 3 -phase load b. The voltage across each resistor
Three resistors are connected in delta. If the line voltage is 13.2kV and the line current is 1202 A, calculate the following:
A) the current in and the voltage acroos each resistor
B) The power supplied to each resistor and the 3 phase load
C) The ohmic value of each resistor
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Electric Motor Control
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- With the aid of a phasor diagram show that the active power and power factor of a balanced three-phase load can be measured by two wattmeters. For a certain load, one wattmeter indicated 20 kW and the other 5 kW after the voltage circuit of this wattmeter had been reversed. Calculate the active power and the power factor of the load. ANS: 15 kW, 0.327arrow_forwardState the advantages to be gained by raising the power factor of industrial loads. A 400 V, 50 Hz, three-phase motor takes a line current of 15.0 A when operating at a lagging power factor of 0.65. When a capacitor bank is connected across the motor terminals, the line current is reduced to 11.5 A. Calculate the rating (in kVA) and the capa citance per phase of the capacitor bank for: (a) star connection; (b) delta connection. Find also the new overall power factor. ANS: 3.81 kvar, 70.5 µF, 23.5 µF, 0.848 laggingarrow_forwardA single wattmeter is used to measure the total active power taken by a 400 V, three-phase induction motor. When the output power of the motor is 15 kW, the efficiency is 88 per cent and the power factor is 0.84 lagging. The current coil of the wattmeter is connected in the yellow line. With the aid of a phasor diagram, calculate the wattmeter indication when the voltage circuit is connected between the yellow line and (a) the red line, (b) the blue line. Show that the sum of the two wattmeter indications gives the total active power taken by the motor. Assume the phase sequence to be R–Y–B. ANS: 11.7 kW, 5.33 kWarrow_forward
- If Req = 60 Ω in the circuit shown, (a) solve for the value of R. (b) If a voltage source of 10V is connected to the terminals in the given circuit, determine the current and voltage foreach resistor. Please show the complete solution.arrow_forwardDon't use ai to answer I will report you answerarrow_forwardIn the given circuit, calculate for (a) the value of the overall voltage V; (b) the powerdelivered by the given current source; (c) the current and voltage in the resistor encircled. Please show the complete solution.arrow_forward
- For the circuit shown, determine the equivalentresistance and the current and voltage for eachresistor. Please show the complete solution.arrow_forwardDon't use ai to answer I will report you answerarrow_forwardOnly expert tutors should solve the question, don't use any Ai or it's screen shot. Use your knowledge skillsarrow_forward
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