Exponential Growth. a. Use separation of variables to solve the differential equation model of uninhibited growth, d P d t = k P . b. Rewrite the solution of part (a) in terms of the condition P 0 = P ( 0 ) .
Exponential Growth. a. Use separation of variables to solve the differential equation model of uninhibited growth, d P d t = k P . b. Rewrite the solution of part (a) in terms of the condition P 0 = P ( 0 ) .
Solution Summary: The author explains how to calculate the general solution of the differential equation dPt=kP by using separation of variables.
a. Use separation of variables to solve the differential equation model of uninhibited growth,
d
P
d
t
=
k
P
.
b. Rewrite the solution of part (a) in terms of the condition
P
0
=
P
(
0
)
.
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
Determine whether the lines
L₁ (t) = (-2,3, −1)t + (0,2,-3) and
L2 p(s) = (2, −3, 1)s + (-10, 17, -8)
intersect. If they do, find the point of intersection.
Convert the line given by the parametric equations y(t)
Enter the symmetric equations in alphabetic order.
(x(t)
= -4+6t
= 3-t
(z(t)
=
5-7t
to symmetric equations.
Find the point at which the line (t) = (4, -5,-4)+t(-2, -1,5) intersects the xy plane.
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