Essentials of Statistics for Business and Economics (with XLSTAT Printed Access Card)
8th Edition
ISBN: 9781337114172
Author: David R. Anderson, Dennis J. Sweeney, Thomas A. Williams, Jeffrey D. Camm, James J. Cochran
Publisher: Cengage Learning
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Chapter 5.7, Problem 53E
Suppose N = 15 and r = 4. What is the
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The average miles per gallon for a sample of 40 cars of model SX last year was 32.1, with a population standard deviation of 3.8. A sample of 40 cars from this year’s model SX has an average of 35.2 mpg, with a population standard deviation of 5.4.
Find a 99 percent confidence interval for the difference in average mpg for this car brand (this year’s model minus last year’s).Find a 99 percent confidence interval for the difference in average mpg for last year’s model minus this year’s. What does the negative difference mean?
A special interest group reports a tiny margin of error (plus or minus 0.04 percent) for its online survey based on 50,000 responses. Is the margin of error legitimate? (Assume that the group’s math is correct.)
Suppose that 73 percent of a sample of 1,000 U.S. college students drive a used car as opposed to a new car or no car at all.
Find an 80 percent confidence interval for the percentage of all U.S. college students who drive a used car.What sample size would cut this margin of error in half?
Chapter 5 Solutions
Essentials of Statistics for Business and Economics (with XLSTAT Printed Access Card)
Ch. 5.1 - Consider the experiment of tossing a coin twice....Ch. 5.1 - Consider the experiment of a worker assembling a...Ch. 5.1 - 3. Three students scheduled interviews for summer...Ch. 5.1 - In January the U.S. unemployment rate dropped to...Ch. 5.1 - To perform a certain type of blood analysis, lab...Ch. 5.1 - Listed is a series of experiments and associated...Ch. 5.2 - 7. The probability distribution for the random...Ch. 5.2 - 8. The following data were collected by counting...Ch. 5.2 - Prob. 9ECh. 5.2 - The percent frequency distributions of job...
Ch. 5.2 - A technician services mailing machines at...Ch. 5.2 - 12. Time Warner Cable provides television and...Ch. 5.2 - A psychologist determined that the number of...Ch. 5.2 - 14. The following table is a partial probability...Ch. 5.3 - The following table provides a probability...Ch. 5.3 - The following table provides a probability...Ch. 5.3 - 17. During the summer of 2014, Coldstream Country...Ch. 5.3 - 18. The American Housing Survey reported the...Ch. 5.3 - 19. West Virginia has one of the highest divorce...Ch. 5.3 - The probability distribution for damage claims...Ch. 5.3 - The following probability distributions of job...Ch. 5.3 - 22. The demand for a product of Carolina...Ch. 5.3 - 23. In Gallup’s Annual Consumption Habits Poll,...Ch. 5.3 - 24. The J. R. Ryland Computer Company is...Ch. 5.4 - Given below is a bivariate distribution for the...Ch. 5.4 - A person is interested in constructing a...Ch. 5.4 - The Chamber of Commerce in a Canadian city has...Ch. 5.4 - PortaCom has developed a design for a high-quality...Ch. 5.4 - J.P. Morgan Asset Management publishes information...Ch. 5.4 - In addition to the information in exercise 29 on...Ch. 5.5 - Consider a binomial experiment with two trials and...Ch. 5.5 - 32. Consider a binomial experiment with n = 10 and...Ch. 5.5 - 33. Consider a binomial experiment with n = 20 and...Ch. 5.5 - 34. For its Music 360 survey, Nielsen Co. asked...Ch. 5.5 - The Center for Medicare and Medical Services...Ch. 5.5 - 36. When a new machine is functioning properly,...Ch. 5.5 - According to a 2013 study by the Pew Research...Ch. 5.5 - Military radar and missile detection systems are...Ch. 5.5 - Market-share-analysis company Net Applications...Ch. 5.5 - A study conducted by the Pew Research Center...Ch. 5.5 - 42. A Gallup Poll showed that 30% of Americans are...Ch. 5.5 - Prob. 43ECh. 5.6 - 44. Consider a Poisson distribution with μ =...Ch. 5.6 - 45. Consider a Poisson distribution with a mean of...Ch. 5.6 - 46. Phone calls arrive at the rate of 48 per hour...Ch. 5.6 - 47. During the period of time that a local...Ch. 5.6 - 48. In 2011, New York City had a total of 11,232...Ch. 5.6 - Airline passengers arrive randomly and...Ch. 5.6 - According to the National Oceanic and Atmospheric...Ch. 5.6 - Prob. 51ECh. 5.7 - Suppose N = 10 and r = 3. Compute the...Ch. 5.7 - 53. Suppose N = 15 and r = 4. What is the...Ch. 5.7 - Online Holiday Shopping. More and more shoppers...Ch. 5.7 - Prob. 55ECh. 5.7 - 56. Axline Computers manufactures personal...Ch. 5.7 - The Zagat Restaurant Survey provides food, decor,...Ch. 5.7 - Prob. 58ECh. 5 - 59. The U.S. Coast Guard (USCG) provides a wide...Ch. 5 - 60. The Car Repair Ratings website provides...Ch. 5 - 61. The budgeting process for a midwestern college...Ch. 5 - 62. A bookstore at the Hartsfield-Jackson Airport...Ch. 5 - The Knowles/Armitage (KA) group at Merrill Lynch...Ch. 5 - 64. The Pew Research Center surveyed adults who...Ch. 5 - 65. The following table shows the percentage of...Ch. 5 - Many companies use a quality control technique...Ch. 5 - 67. PBS News Hour reported that 39.4% of Americans...Ch. 5 - 68. Mahoney Custom Home Builders, Inc. of Canyon...Ch. 5 - Arrivals to a Car Wash. Cars arrive at a car wash...Ch. 5 - 70. A new automated production process averages...Ch. 5 - A regional director responsible for business...Ch. 5 - Customer arrivals at a bank are random and...Ch. 5 - 73. A deck of playing cards contains 52 cards,...Ch. 5 - 74. U.S. News & World Report’s ranking of...Ch. 5 - Great Grasslands Grains, Inc. (GGG) manufactures...
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- You want to compare the average number of tines on the antlers of male deer in two nearby metro parks. A sample of 30 deer from the first park shows an average of 5 tines with a population standard deviation of 3. A sample of 35 deer from the second park shows an average of 6 tines with a population standard deviation of 3.2. Find a 95 percent confidence interval for the difference in average number of tines for all male deer in the two metro parks (second park minus first park).Do the parks’ deer populations differ in average size of deer antlers?arrow_forwardSuppose that you want to increase the confidence level of a particular confidence interval from 80 percent to 95 percent without changing the width of the confidence interval. Can you do it?arrow_forwardA random sample of 1,117 U.S. college students finds that 729 go home at least once each term. Find a 98 percent confidence interval for the proportion of all U.S. college students who go home at least once each term.arrow_forward
- Suppose that you make two confidence intervals with the same data set — one with a 95 percent confidence level and the other with a 99.7 percent confidence level. Which interval is wider?Is a wide confidence interval a good thing?arrow_forwardIs it true that a 95 percent confidence interval means you’re 95 percent confident that the sample statistic is in the interval?arrow_forwardTines can range from 2 to upwards of 50 or more on a male deer. You want to estimate the average number of tines on the antlers of male deer in a nearby metro park. A sample of 30 deer has an average of 5 tines, with a population standard deviation of 3. Find a 95 percent confidence interval for the average number of tines for all male deer in this metro park.Find a 98 percent confidence interval for the average number of tines for all male deer in this metro park.arrow_forward
- Based on a sample of 100 participants, the average weight loss the first month under a new (competing) weight-loss plan is 11.4 pounds with a population standard deviation of 5.1 pounds. The average weight loss for the first month for 100 people on the old (standard) weight-loss plan is 12.8 pounds, with population standard deviation of 4.8 pounds. Find a 90 percent confidence interval for the difference in weight loss for the two plans( old minus new) Whats the margin of error for your calculated confidence interval?arrow_forwardA 95 percent confidence interval for the average miles per gallon for all cars of a certain type is 32.1, plus or minus 1.8. The interval is based on a sample of 40 randomly selected cars. What units represent the margin of error?Suppose that you want to decrease the margin of error, but you want to keep 95 percent confidence. What should you do?arrow_forward3. (i) Below is the R code for performing a X2 test on a 2×3 matrix of categorical variables called TestMatrix: chisq.test(Test Matrix) (a) Assuming we have a significant result for this procedure, provide the R code (including any required packages) for an appropriate post hoc test. (b) If we were to apply this technique to a 2 × 2 case, how would we adapt the code in order to perform the correct test? (ii) What procedure can we use if we want to test for association when we have ordinal variables? What code do we use in R to do this? What package does this command belong to? (iii) The following code contains the initial steps for a scenario where we are looking to investigate the relationship between age and whether someone owns a car by using frequencies. There are two issues with the code - please state these. Row3<-c(75,15) Row4<-c(50,-10) MortgageMatrix<-matrix(c(Row1, Row4), byrow=T, nrow=2, MortgageMatrix dimnames=list(c("Yes", "No"), c("40 or older","<40")))…arrow_forward
- Describe the situation in which Fisher’s exact test would be used?(ii) When do we use Yates’ continuity correction (with respect to contingencytables)?[2 Marks] 2. Investigate, checking the relevant assumptions, whether there is an associationbetween age group and home ownership based on the sample dataset for atown below:Home Owner: Yes NoUnder 40 39 12140 and over 181 59Calculate and evaluate the effect size.arrow_forwardNot use ai pleasearrow_forwardNeed help with the following statistic problems.arrow_forward
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