In Exercises 23-34, (a) find the particular solution of each differential equation as determined by the initial condition, and (b) check the solution by substituting into the differential equation. f ′ ( x ) = x 2 / 3 − x ; f ( 1 ) = − 6
In Exercises 23-34, (a) find the particular solution of each differential equation as determined by the initial condition, and (b) check the solution by substituting into the differential equation. f ′ ( x ) = x 2 / 3 − x ; f ( 1 ) = − 6
Solution Summary: The author explains how to calculate the particular solution of the provided differential equation.
In Exercises 23-34, (a) find the particular solution of each differential equation as determined by the initial condition, and (b) check the solution by substituting into the differential equation.
f
′
(
x
)
=
x
2
/
3
−
x
;
f
(
1
)
=
−
6
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
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