BIO 1406/07 W/CONNECT/LM NEW >IC<
16th Edition
ISBN: 9781260075762
Author: Raven
Publisher: MCG CUSTOM
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Chapter 56, Problem 3S
Summary Introduction
To determine:
How would you test the mechanism hypothesized in the fig. 56.22 that are there alternative hypothesis that might explain the increase followed by the decrease in ant colony numbers subsequent to rodent removal in the experiment.
Introduction:
The competition is carried out in a biological system among species for use of
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Chapter 56 Solutions
BIO 1406/07 W/CONNECT/LM NEW >IC<
Ch. 56 - Studies that demonstrate that species living in an...Ch. 56 - Prob. 2UCh. 56 - According to the idea of coevolution between...Ch. 56 - In order for mimicry to be effective in protecting...Ch. 56 - Which of the following is an example of...Ch. 56 - A species whose effect on the composition of a...Ch. 56 - When a predator preferentially eats the superior...Ch. 56 - Prob. 8UCh. 56 - Prob. 1ACh. 56 - The presence of a predatory species a. always...
Ch. 56 - Resource partitioning by sympatric species a....Ch. 56 - Parasitism differs from predation because a. the...Ch. 56 - The presence of one species (A) in a community may...Ch. 56 - Competition is traditionally indicated by...Ch. 56 - Refer to figure 56.9. If the single prey species...Ch. 56 - Prob. 3SCh. 56 - Refer to figure 56.7. Examine the pattern of beak...Ch. 56 - Is it possible that some species function together...
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- A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation? The cell membranes are more resistant than normal. An isotonic solution had been added instead of water. A solution of 0.1 M NaCl had been added instead of water. Not enough water had been added to the red blood cell pellet. The man had sickle-cell anaemia.arrow_forwardWith reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forwardWith reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forward
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