Algebra and Trigonometry: Structure and Method, Book 2

2000th Edition

ISBN: 9780395977255

Author: MCDOUGAL LITTEL

Publisher: McDougal Littell

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Question

Chapter 5.6, Problem 36WE

To determine

To simplify the given expression.

Expert Solution & Answer

Answer to Problem 36WE

2(x−y)y(2x−3y)2

Explanation of Solution

Given:

Expression: 14x2−12xy+9y2+12xy−3y2

Calculation:

Consider the given expression 14x2−12xy+9y2+12xy−3y2 ,

Since the denominators of both the fractions are different, find the least common denominator for both the fractions.

Here, least common denominator is y(2x−3y)2 , so

14x2−12xy+9y2+12xy−3y2

=1(2x−3y)2+1y(2x−3y)

[Factorizing the denominators]

=1⋅y(2x−3y)2⋅y+1⋅(2x−3y)y(2x−3y)⋅(2x−3y)

=yy(2x−3y)2+(2x−3y)y(2x−3y)2

Now, as the denominators of the two fractions are same, simply add the numerators and put the result on the same denominator.

=y+(2x−3y)y(2x−3y)2

=y+2x−3yy(2x−3y)2=2x−2yy(2x−3y)2=2(x−y)y(2x−3y)2

Conclusion:

Therefore, after simplification, the answer is 2(x−y)y(2x−3y)2 .

Chapter 5.6, Problem 35WE

Chapter 5.6, Problem 37WE

Chapter 5 Solutions

Algebra and Trigonometry: Structure and Method, Book 2

Ch. 5.1 - Prob. 1OE Ch. 5.1 - Prob. 2OE Ch. 5.1 - Prob. 3OE Ch. 5.1 - Prob. 4OE Ch. 5.1 - Prob. 5OE Ch. 5.1 - Prob. 6OE Ch. 5.1 - Prob. 7OE Ch. 5.1 - Prob. 8OE Ch. 5.1 - Prob. 9OE Ch. 5.1 - Prob. 10OE

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