Pre-Algebra
Pre-Algebra
1st Edition
ISBN: 9780618800766
Author: Ron Larson, Lee Stiff, Laurie Boswell, Timothy Kanold
Publisher: Houghton Mifflin-High School
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Equations and inequalities describe the relationship between two mathematical expressions.
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A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.
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Chapter 5.6, Problem 13E
To determine

To calculate:solve the equation −512x=25 .

Expert Solution & Answer
Check Mark

Answer to Problem 13E

The value of equation −512x=25 is −60 .

Explanation of Solution

Given information : consider, the equationprovided in the question,

  −512x=25 .

Calculation : to solve the equation multiply each side by multiplicative inverse of 512 then multiply.

  −512x=25−512(125)x=25(125)−x=5·12x=−60

For check solution put x=−60 .

  −512x=25−512·(−60)=2525=25

Hence,

Thus,Thevalue of equation −512x=25 is −60 .

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Chapter 5.6, Problem 12E
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Chapter 5.6, Problem 14E

Chapter 5 Solutions

Pre-Algebra

Ch. 5.1 - Prob. 1CCh. 5.1 - Prob. 2CCh. 5.1 - Prob. 3CCh. 5.1 - Prob. 4CCh. 5.1 - Prob. 5CCh. 5.1 - Prob. 1ECh. 5.1 - Prob. 2ECh. 5.1 - Prob. 3ECh. 5.1 - Prob. 4ECh. 5.1 - Prob. 5E
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