Explanation Given information: c ' ( n ) < 0 , ∫ 0 15 c ( n ) d n = 7.5 , c ( 15 ) = 0.7 , c ( 24 ) = 0.4 , c ( 15 ) = 8 , c ( 24 ) = 13 Concept used: If F ' ( t ) is continuous for a ≤ t ≤ b , then ∫ a b F ' ( t ) d t = F ( b ) − F ( a ) . Calculation: The expression ∫ 15 24 c ' ( n ) d n can be written as c ( 24 ) − c ( 15 ) because ∫ a b F ' ( t ) d t = F ( b ) − F ( a ) The known values are c ( 15 ) = 0.7 , c ( 24 ) = 0

6th Edition

ISBN: 9781119275565

Author: Hughes-Hallett

Publisher: WILEY

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Chapter 5.5, Problem 22P

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To find the value of c(15)+∫1524c'(n)dn.

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Chapter 5.5, Problem 21P

Chapter 5.5, Problem 23P

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APPLIED CALCULUS-PRINT COMPANION (LL)

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To find the value of c ( 15 ) + ∫ 15 24 c ' ( n ) d n .

Solution Summary: The author calculates the value of c(15)+displaystyle underset15

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To find the value of c(15)+∫1524c'(n)dn.

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Chapter 5 Solutions