Explanation Given Information: The provided options are, (A): Must be solved using the techniques of Section 5.4 (B): Must be solved using the techniques of Section 5.3. (C): can be solved using the techniques of either section. Consider the problem. Maximize p = x + y Subject to x − 2 y ≥ 0 2 x + y ≤ 10 x ≥ 0 , y ≥ 0 The given problem is not a maximization problem as the constraint x − 2 y ≥ 0 has ≥ inequality. Thus, convert the given problem to maximisation problem, the greater than inequality is changed to less than inequality. Multiply the inequality by − 1 . Since, on multiplication with − 1 , the sign of inequality is reversed. Thus, − ( x − 2 y ) ≤ − ( 0 ) − x + 2 y ≤ 0 Substitute − x + 2 y ≤ 0 for x − 2 y ≥ 0 in the constraints

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Chapter 5.4, Problem 57E

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The technique from which the problem can be solved from the provided techniques, for the problem maximize p=x+y subject to

x−2y≥02x+y≤10x≥0,y≥0

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Chapter 5.4, Problem 56E

Chapter 5.4, Problem 58E

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The technique from which the problem can be solved from the provided techniques, for the problem maximize p = x + y subject to x − 2 y ≥ 0 2 x + y ≤ 10 x ≥ 0 , y ≥ 0

Solution Summary: The author explains that the given problem is not a maximization problem, since the constraint x-2yge 0 has -ge inequality.

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The technique from which the problem can be solved from the provided techniques, for the problem maximize p=x+y subject to

x−2y≥02x+y≤10x≥0,y≥0

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Chapter 5 Solutions

The technique from which the problem can be solved from the provided techniques, for the problem maximize p = x + y subject to x − 2 y ≥ 0 2 x + y ≤ 10 x ≥ 0 , y ≥ 0

Solution Summary: The author explains that the given problem is not a maximization problem, since the constraint x-2yge 0 has -ge inequality.

Videos

The technique from which the problem can be solved from the provided techniques, for the problem maximize p=x+y subject to x−2y≥02x+y≤10x≥0,y≥0

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Chapter 5 Solutions

The technique from which the problem can be solved from the provided techniques, for the problem maximize p=x+y subject to

x−2y≥02x+y≤10x≥0,y≥0