Chapter 5.4, Problem 46E

To determine

To show:

${\sec }^{-1}x={\cos }^{-1}\left(\frac{1}{x}\right)$

${\csc }^{-1}x={\sin }^{-1}\left(\frac{1}{x}\right)$

${\cot }^{-1}x={\tan }^{-1}\left(\frac{1}{x}\right)$

and the values of ${\sec }^{-1}2,{\csc }^{-1}3,$ and ${\cot }^{-1}4.$