Explanation Given: ∫ − 2 3 | x 3 | d x Formula Used: A r e a = ∫ a b f ( x ) d x , [ a , b ] = F ( b ) − F ( a ) Calculation: f ( x ) = | x 3 | = { x 3 , x > 0 − x 3 , x < 0 } I ( x ) = ∫ − 2 0 − x 3 d x + ∫ 0 3 x 3 d x Let G ( x ) = ∫ − 2 0 − x 3 d x and H ( x ) = ∫ 0 3 x 3 d x

4th Edition

ISBN: 9781319323394

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 5.4, Problem 33E

To determine

We need to write the integrals as a sum of the integrals without the absolute values and evaluate $\int_{- 2}^{3} | x^{3} | d x$ .

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Chapter 5.4, Problem 32E

Chapter 5.4, Problem 34E

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CALCULUS W/SAPLING ACCESS >IC<

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We need to write the integrals as a sum of the integrals without the absolute values and evaluate ∫ − 2 3 | x 3 | d x .

Solution Summary: The author explains how to write the integrals as a sum without the absolute values.

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We need to write the integrals as a sum of the integrals without the absolute values and evaluate $\int_{- 2}^{3} | x^{3} | d x$ .

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Chapter 5 Solutions

We need to write the integrals as a sum of the integrals without the absolute values and evaluate ∫ − 2 3 | x 3 | d x .

Solution Summary: The author explains how to write the integrals as a sum without the absolute values.

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We need to write the integrals as a sum of the integrals without the absolute values and evaluate ∫−23|x3|dx.

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Chapter 5 Solutions

We need to write the integrals as a sum of the integrals without the absolute values and evaluate $\int_{- 2}^{3} | x^{3} | d x$ .