Explanation Given information: g ( p ) = 5 / ( 2 p + 3 ) , p = 1 and p = 11 . Explanation: Let g ( p ) = 5 / ( 2 p + 3 ) , Differentiate with respect to p , g ' ( p ) = d d p 5 ( 2 p + 3 ) − 1 = − 5 ( 2 p + 3 ) − 2 ( 2 ) = − 10 ( 2 p + 3 ) 2 By using the definition of logarithmic derivative, d d p [ ln g ( p ) ] = g ' ( p ) g ( p ) ⇒ d d p [ ln ( 5 / ( 2 p + 3 ) ) ] = − 10 / ( 2 p + 3 ) 2 5 / ( 2 p + 3 ) ⇒ d d p [ ln ( 5 / ( 2 p + 3 ) ) ] = − 2 ( 2 p + 3 ) . Thus, the logarithmic derivative of g ( p ) = 5 / ( 2 p + 3 ) is − 2 ( 2 p + 3 )

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Chapter 5.3, Problem 8E

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The logarithmic derivative of g(p)=5/ (2p+3) at p=1 and p=11. Also the percentage rate of change of the functions at the points p=2 and p=8.

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Chapter 5.3, Problem 7E

Chapter 5.3, Problem 9E

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The logarithmic derivative of g ( p ) = 5 / ( 2 p + 3 ) at p = 1 and p = 11 . Also the percentage rate of change of the functions at the points p = 2 and p = 8 .

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The logarithmic derivative of g(p)=5/ (2p+3) at p=1 and p=11. Also the percentage rate of change of the functions at the points p=2 and p=8.

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