Find the percentage of time needed to arrive at school inless than 22 minutes.

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Answer 1

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Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 5.3, Problem 5JC

a.

To determine

Find the percentage of time needed to arrive at school inless than 22 minutes.

b.

To determine

Find the percentage of time needed to arrive at school inmore than 24 minutes.

c.

To determine

Explain whether the distribution of driving times is unimodal and symmetric.

d.

To determine

What does the result says about the accuracy of the prediction.

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You are planning an experiment to determine the effect of the brand of gasoline and the weight of a car on gas mileage measured in miles per gallon. You will use a single test car, adding weights so that its total weight is 3000, 3500, or 4000 pounds. The car will drive on a test track at each weight using each of Amoco, Marathon, and Speedway gasoline. Which is the best way to organize the study? Start with 3000 pounds and Amoco and run the car on the test track. Then do 3500 and 4000 pounds. Change to Marathon and go through the three weights in order. Then change to Speedway and do the three weights in order once more. Start with 3000 pounds and Amoco and run the car on the test track. Then change to Marathon and then to Speedway without changing the weight. Then add weights to get 3500 pounds and go through the three gasolines in the same order.Then change to 4000 pounds and do the three gasolines in order again. Choose a gasoline at random, and run the car with this gasoline at…

AP1.2 A child is 40 inches tall, which places her at the 90th percentile of all children of similar age. The heights for children of this age form an approximately Normal distribution with a mean of 38 inches. Based on this information, what is the standard deviation of the heights of all children of this age? 0.20 inches (c) 0.65 inches (e) 1.56 inches 0.31 inches (d) 1.21 inches

Answer 2

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Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 5.3, Problem 5JC

a.

To determine

Find the percentage of time needed to arrive at school inless than 22 minutes.

b.

To determine

Find the percentage of time needed to arrive at school inmore than 24 minutes.

c.

To determine

Explain whether the distribution of driving times is unimodal and symmetric.

d.

To determine

What does the result says about the accuracy of the prediction.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 5.3, Problem 5JC

a.

To determine

Find the percentage of time needed to arrive at school inless than 22 minutes.

b.

To determine

Find the percentage of time needed to arrive at school inmore than 24 minutes.

c.

To determine

Explain whether the distribution of driving times is unimodal and symmetric.

d.

To determine

What does the result says about the accuracy of the prediction.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 5.3, Problem 5JC

a.

To determine

Find the percentage of time needed to arrive at school inless than 22 minutes.

b.

To determine

Find the percentage of time needed to arrive at school inmore than 24 minutes.

c.

To determine

Explain whether the distribution of driving times is unimodal and symmetric.

d.

To determine

What does the result says about the accuracy of the prediction.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 5.3, Problem 5JC

a.

To determine

Find the percentage of time needed to arrive at school inless than 22 minutes.

b.

To determine

Find the percentage of time needed to arrive at school inmore than 24 minutes.

c.

To determine

Explain whether the distribution of driving times is unimodal and symmetric.

d.

To determine

What does the result says about the accuracy of the prediction.

Answer 6

Chapter 5.3, Problem 5JC

a.

To determine

Find the percentage of time needed to arrive at school inless than 22 minutes.

Answer 7

Chapter 5.3, Problem 5JC

a.

To determine

Find the percentage of time needed to arrive at school inless than 22 minutes.

Answer 8

b.

To determine

Find the percentage of time needed to arrive at school inmore than 24 minutes.

Answer 9

b.

To determine

Find the percentage of time needed to arrive at school inmore than 24 minutes.

Answer 10

c.

To determine

Explain whether the distribution of driving times is unimodal and symmetric.

Answer 11

c.

To determine

Explain whether the distribution of driving times is unimodal and symmetric.

Answer 12

d.

To determine

What does the result says about the accuracy of the prediction.

Answer 13

d.

To determine

What does the result says about the accuracy of the prediction.

Answer 14

Expert Solution & Answer

Answer 15

Expert Solution & Answer

Answer 16

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Answer 17

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Find the percentage of time needed to arrive at school inless than 22 minutes.

Solution Summary: The author explains the 68-95-99.7 rule for the distribution of driving time.

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Find the percentage of time needed to arrive at school inless than 22 minutes.

Find the percentage of time needed to arrive at school inmore than 24 minutes.

Explain whether the distribution of driving times is unimodal and symmetric.

What does the result says about the accuracy of the prediction.

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