Using Properties of Definite Integrals In Exercises 37-44, evaluate the definite integral using the values below. ∫ 2 6 x 3 d x = 320 , ∫ 2 6 x d x = 16 , ∫ 2 6 d x = 4 ∫ 2 6 ( 2 x 3 − 10 + 7 ) d x
Using Properties of Definite Integrals In Exercises 37-44, evaluate the definite integral using the values below. ∫ 2 6 x 3 d x = 320 , ∫ 2 6 x d x = 16 , ∫ 2 6 d x = 4 ∫ 2 6 ( 2 x 3 − 10 + 7 ) d x
Solution Summary: The author explains how to calculate a definite integral displaystyle, using the provided values.
Using Properties of Definite Integrals In Exercises 37-44, evaluate the definite integral using the values below.
∫
2
6
x
3
d
x
=
320
,
∫
2
6
x
d
x
=
16
,
∫
2
6
d
x
=
4
∫
2
6
(
2
x
3
−
10
+
7
)
d
x
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
3. Consider the polynomial equation 6-iz+7z² - iz³ +z = 0 for which the roots are 3i, -2i, -i,
and i.
(a) Verify the relations between this roots and the coefficients of the polynomial.
(b) Find the annulus region in which the roots lie.
Force with 800 N and 400 N are acting on a machine part at 30° and 60°, respectively with the positive x axis
Find the accumulated amount A, if the principal P is invested at an interest rate of r per year for t years. (Round your answer to the nearest cent.)
P = $13,000, r = 6%, t = 10, compounded quarterly
A = $ 31902
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Find the accumulated amount A, if the principal P is invested at an interest rate of r per year for t years. (Round your answer to the nearest cent.)
P = $140,000, r = 8%, t = 8, compounded monthly
A = $259130.20 X
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Definite Integral Calculus Examples, Integration - Basic Introduction, Practice Problems; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=rCWOdfQ3cwQ;License: Standard YouTube License, CC-BY