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Concept explainers
Find the
a. n = 100, p = 0.75
b. n = 300, p = 0.3
c. n = 20, p = 0.5
d. n = 10, p = 0.8
a.
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The mean, variance and standard deviation.
Answer to Problem 17E
The mean is 75.
The variance is 18.8.
The standard deviation is 4.3.
Explanation of Solution
Given info:
The number of trials n is 100 and probability of success is 0.75
Calculation:
Mean of Binomial distribution:
Where, n is the number of trials and p is the probability of success for each trial and q is the probability of failure for each trial.
Substitute n as 100 and p as 0.75.
Thus, the mean is 75.
Variance of Binomial distribution:
Substitute n as 100, p as 0.75 and q as
Thus, the variance is 18.75.
Standard deviation of Binomial distribution:
Substitute n as 100, p as 0.75 and q as
Thus, the standard deviation is 4.33.
b.
![Check Mark](/static/check-mark.png)
The mean, variance and standard deviation.
Answer to Problem 17E
The mean is 90.
The variance is 63.
The standard deviation is 7.9.
Explanation of Solution
Given info:
The number of trials n is 300 and probability of success is 0.3
Calculation:
Mean of Binomial distribution:
Substitute n as 300 and p as 0.3.
Thus, the mean is 90.
Variance of Binomial distribution:
Substitute n as 300, p as 0.3 and q as
Thus, the variance is 63.
Standard deviation of Binomial distribution:
Substitute n as 100, p as 0.3 and q as
Thus, the standard deviation is 7.9.
c.
![Check Mark](/static/check-mark.png)
The mean, variance and standard deviation.
Answer to Problem 17E
The mean is 10.
The variance is 5.
The standard deviation is 2.2.
Explanation of Solution
Given info:
The number of trials n is 20 and probability of success is 0.5
Calculation:
Mean of Binomial distribution:
Substitute n as 20 and p as 0.5.
Thus, the mean is 10.
Variance of Binomial distribution:
Substitute n as 20, p as 0.5 and q as
Thus, the variance is 5.
Standard deviation of Binomial distribution:
Substitute n as 20, p as 0.5 and q as
Thus, the standard deviation is 2.2.
d.
![Check Mark](/static/check-mark.png)
The mean, variance and standard deviation.
Answer to Problem 17E
The mean is 8.
The variance is 1.6.
The standard deviation is 1.3.
Explanation of Solution
Given info:
The number of trials n is 10 and probability of success is 0.8
Calculation:
Mean of Binomial distribution:
Substitute n as 10 and p as 0.8.
Thus, the mean is 8.
Variance of Binomial distribution:
Substitute n as 10, p as 0.8 and q as
Thus, the variance is 1.6.
Standard deviation of Binomial distribution:
Substitute n as 10, p as 0.8 and q as
Thus, the standard deviation is 1.3.
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Chapter 5 Solutions
Connect Plus Statistics Hosted by ALEKS Access Card 52 Weeks for Elementary Statistics: A Step-By-St
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- Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw Hill
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