EBK ORGANIC CHEMISTRY
8th Edition
ISBN: 9781319188962
Author: VOLLHARDT
Publisher: VST
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Question
Chapter 5.2, Problem 5.6E
(a)
Interpretation Introduction
Interpretation:The observed specific rotation of table sugar should be calculated and whether any information about the optical rotation for the enantiomer of natural sucrose is obtained from this calculation or not is to be determined.
Concept introduction:The formula to calculate specific rotation is given as follows:
Where,
The enantiomers are identical chemical compounds that have a mirror-image relationship to each other. The two enantiomers rotate the plane-polarized in opposite direction. This indicates one is dextrorotatory and one is levorotatory.
(b)
Interpretation Introduction
Interpretation: The observed specific rotation of
Concept introduction:The formula to calculate observed rotation from specific rotation is given as follows:
Where,
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1) The isoamyl acetate report requires eight paragraphs - four for comparison of isoamyl alcohol and isoamyl acetate (one paragraph each devoted to MS, HNMR, CNMR and IR) and four for comparison of acetic acid and isoamyl acetate ((one paragraph each devoted to MS, HNMR, CNMR and IR.
2) For MS, the differing masses of molecular ions are a popular starting point. Including a unique fragmentation is important, too.
3) For HNMR, CNMR and IR state the peaks that are different and what makes them different (usually the presence or absence of certain groups). See if you can find two differences (in each set of IR, HNMR and CNMR spectra) due to the presence or absence of a functional group. Include peak locations. Alternatively, you can state a shift of a peak due to a change near a given functional group. Including peak locations for shifted peaks, as well as what these peaks are due to. Ideally, your focus should be on not just identifying the differences but explaining them in terms of…
№3
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HN
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Chapter 5 Solutions
EBK ORGANIC CHEMISTRY
Ch. 5.1 - Prob. 5.3ECh. 5.1 - Prob. 5.4ECh. 5.1 - Prob. 5.5ECh. 5.2 - Prob. 5.6ECh. 5.2 - Prob. 5.8TIYCh. 5.3 - Prob. 5.9ECh. 5.3 - Prob. 5.11TIYCh. 5.3 - Prob. 5.12ECh. 5.4 - Prob. 5.13ECh. 5.4 - Prob. 5.14E
Ch. 5.4 - Prob. 5.16TIYCh. 5.4 - Prob. 5.17ECh. 5.5 - Prob. 5.18ECh. 5.5 - Prob. 5.19ECh. 5.5 - Prob. 5.20ECh. 5.6 - Prob. 5.21ECh. 5.6 - Prob. 5.22ECh. 5.6 - Prob. 5.23ECh. 5.7 - Prob. 5.24ECh. 5.7 - Prob. 5.26TIYCh. 5.7 - Prob. 5.27ECh. 5 - Prob. 5.1ECh. 5 - Prob. 5.2ECh. 5 - Prob. 30PCh. 5 - Prob. 31PCh. 5 - Prob. 32PCh. 5 - Prob. 33PCh. 5 - Prob. 34PCh. 5 - Prob. 35PCh. 5 - Prob. 36PCh. 5 - Prob. 37PCh. 5 - Prob. 38PCh. 5 - Prob. 39PCh. 5 - Prob. 40PCh. 5 - Prob. 41PCh. 5 - Prob. 42PCh. 5 - Prob. 43PCh. 5 - Prob. 44PCh. 5 - Prob. 45PCh. 5 - Prob. 46PCh. 5 - Prob. 47PCh. 5 - Prob. 48PCh. 5 - Prob. 49PCh. 5 - Prob. 50PCh. 5 - Prob. 51PCh. 5 - Prob. 52PCh. 5 - Prob. 53PCh. 5 - Prob. 54PCh. 5 - Prob. 55PCh. 5 - Prob. 56PCh. 5 - Prob. 57PCh. 5 - Prob. 58PCh. 5 - Prob. 59PCh. 5 - Prob. 60PCh. 5 - Prob. 61PCh. 5 - Prob. 62PCh. 5 - Prob. 63PCh. 5 - Prob. 64PCh. 5 - Prob. 65PCh. 5 - Prob. 66PCh. 5 - Prob. 67PCh. 5 - Prob. 68PCh. 5 - Prob. 69PCh. 5 - Prob. 70PCh. 5 - Prob. 71P
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