Solve each system in Exercises 5–18.
18.
Want to see the full answer?
Check out a sample textbook solutionChapter 5 Solutions
College Algebra Essentials (5th Edition)
- Exercises 71–74: The intercept form of a line is + = 1. Determine the x- and y-intercepts on the graph of the equa- tion. Draw a conclusion about what the constants a and b represent in this form. += 1 72- 71. 73. 4y 5x 74. 5arrow_forwardExercises 43–52: Complete the following. (a) Solve the equation symbolically. (b) Classify the equation as a contradiction, an identity, or a conditional equation. 43. 5x - 1 = 5x + 4 44. 7- 9: = 2(3 – 42) – z 45. 3(x - 1) = 5 46. 22 = -2(2x + 1.4) 47. 0.5(x – 2) + 5 = 0.5x + 4 48. 눈x-2(x-1)3-x + 2 2x + 1 2x 49. 50. x – 1.5 2- 3r - 1.5 51. -6 52. 0.5 (3x - 1) + 0.5x = 2x – 0.5arrow_forwardSolve 11-13arrow_forward
- Exercises 98–100 will help you prepare for the material covered in the first section of the next chapter. 98. a. Does (-5, –6) satisfy 2x – y = -4? b. Does (-5, -6) satisfy 3x – 5y = 15? 99. Graph y = -x – 1 and 4x – 3y = 24 in the same rectangular coordinate system. At what point do the graphs intersect? 100. Solve: 7x – 2(-2x + 4) = 3.arrow_forwardExercises 25–28: Solve by completing the square. 25. x² + 2x = 5 26. x² - 3x = 3 27. 2:2 – 62 - 1 = 0 28. - - r + 1 = 0arrow_forwardIn Exercises 43–54, solve each absolute value equation or indicate the equation has no solution. 43. |x – 2| = 7 45. |2x – 1| = 5 47. 2|3x – 2| = 14 44. |x + 1| = 5 46. |2r – 3| = 11 48. 3|2x – 1| = 21 %3D %3D 5 24 - + 6 = 18 50. 4 1 x + 7 = 10 51. |x + 1| + 5 = 3 53. |2x – 1| + 3 = 3 52. |x + 1| + 6 = 2 54. |3x – 2| + 4 = 4arrow_forward
- In Exercises 49–55, solve each rational equation. If an equation has no solution, so state. 3 1 + 3 49. 3 50. Зх + 4 2x - 8 1 3 6. 51. x + 5 x² 25 x + 5 52. x + 1 4x + 1 x + 2 x2 + 3x + 2 2 53. 3 - 3x .2 2 7 54. 4 x + 2 2x + 7 55. x + 5 8. x + 18 x - 4 x + x - 20arrow_forwardSolve 4.arrow_forwardExercises 105-120: Complete the following. (a) Write the equation as ax² + bx + e = 0 with a > 0. (b) Calculate the discriminant b² – 4ac and determine the number of real solutions. (c) Solve the equation. 105. 3x² = 12 106. 8x - 2 = 14 107. x² – 2x = -1 108. 6x² = 4x 109. 4x = x? 110. 16x + 9 = 24x 111. x² + 1 = x 112. 2x² + x = 2 113. 2x² + 3x = 12 – 2x 114. 3x² + 3 = 5x 115. x(x – 4) = -4 116. + 3x = x – 4 117. x(x + 2) = -13 118. 4x = 6 + x? 119. 3x = 1- x 120. x(5x – 3) = 1arrow_forward
- Algebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:CengageAlgebra: Structure And Method, Book 1AlgebraISBN:9780395977224Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. ColePublisher:McDougal Littell