In Exercises 17-20, θ is an acute angle and sin θ and cos θ are given. Use identities to find tan θ , csc θ , sec θ , and cot θ . Where necessary, rationalize denominators sin θ = 8 17 , cos θ 15 17
In Exercises 17-20, θ is an acute angle and sin θ and cos θ are given. Use identities to find tan θ , csc θ , sec θ , and cot θ . Where necessary, rationalize denominators sin θ = 8 17 , cos θ 15 17
Solution Summary: The author explains how to calculate the trigonometric functions mathrmtantheta ,
In Exercises 17-20,
θ
is an acute angle and
sin
θ
and
cos
θ
are given. Use identities to find
tan
θ
,
csc
θ
,
sec
θ
,
and
cot
θ
. Where necessary, rationalize denominators
I want to learn this topic l dont know anything about it
Solve the linear system of equations attached using Gaussian elimination (not Gauss-Jordan) and back subsitution.
Remember that:
A matrix is in row echelon form if
Any row that consists only of zeros is at the bottom of the matrix.
The first non-zero entry in each other row is 1. This entry is called aleading 1.
The leading 1 of each row, after the first row, lies to the right of the leading 1 of the previous row.
PRIMERA EVALUACIÓN SUMATIVA
10. Determina la medida de los ángulos in-
teriores coloreados en cada poligono.
⚫ Octágono regular
A
11. Calcula es número de lados qu
poligono regular, si la medida
quiera de sus ángulos internos
• a=156°
A= (-2x+80
2
156 180-
360
0 = 24-360
360=24°
• a = 162°
1620-180-360
6=18-360
360=19
2=360=
18
12. Calcula las medida
ternos del cuadrilá
B
X+5
x+10
A
X+X+
Sx+6
5x=3
x=30
0
лаб
• Cuadrilátero
120°
110°
• α = 166° 40'
200=180-360
0 =
26-360
360=20
ひ=360
20
18 J
60°
⚫a=169° 42' 51.43"
169.4143180-340
0 = 10.29 54-360
360 10.2857
2=360
10.2857
@Sa
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.
Fundamental Trigonometric Identities: Reciprocal, Quotient, and Pythagorean Identities; Author: Mathispower4u;https://www.youtube.com/watch?v=OmJ5fxyXrfg;License: Standard YouTube License, CC-BY