Business Math (11th Edition)
11th Edition
ISBN: 9780134496436
Author: Cheryl Cleaves, Margie Hobbs, Jeffrey Noble
Publisher: PEARSON
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Chapter 5.2, Problem 14SE
To determine
To calculate: The cost of
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2. [15] Let X and Y be two discrete RVs whose joint PMF is given by the following table:
y
Px,y(x, y)
-1
1
3
0
0.1
0.04
0.02
I
2
0.08
0.2
0.06
4
0.06
0.14
0.30
(a) Find P(X ≥ 2, Y < 1).
(b) Find P(X ≤Y - 1).
(c) Find the marginal PMFs of X and Y.
(d) Are X and Y independent? Explain
(e) Find E(XY) and Cov(X, Y).
Let sinθ = 2√2/5 and π/2 < θ < πPart A: Determine the exact value of cos 2θ.Part B: Determine the exact value of sin(θ/2)
The joint pdf of random variables X=1, 2 and Y=1, 2, 3 is
P(X,Y)= X 10.05
Find (a) The value of k.
(c) P(X>1, Y <2).
Y
0.2
0.18
0.15]
(b) the marginal probability function of X and Y.
(d) Ex, Hy
Chapter 5 Solutions
Business Math (11th Edition)
Ch. 5.1 - Prob. 1-1SCCh. 5.1 - Prob. 1-2SCCh. 5.1 - Prob. 1-3SCCh. 5.1 - Prob. 1-4SCCh. 5.1 - Prob. 1-5SCCh. 5.1 - Prob. 1-6SCCh. 5.1 - Prob. 2-1SCCh. 5.1 - Prob. 2-2SCCh. 5.1 - Prob. 2-3SCCh. 5.1 - Prob. 2-4SC
Ch. 5.1 - Prob. 2-5SCCh. 5.1 - Prob. 2-6SCCh. 5.1 - Prob. 3-1SCCh. 5.1 - Prob. 3-2SCCh. 5.1 - Prob. 3-3SCCh. 5.1 - Prob. 3-4SCCh. 5.1 - Prob. 3-5SCCh. 5.1 - Prob. 3-6SCCh. 5.1 - Prob. 4-1SCCh. 5.1 - Prob. 4-2SCCh. 5.1 - Prob. 4-3SCCh. 5.1 - Prob. 4-4SCCh. 5.1 - Prob. 4-5SCCh. 5.1 - Prob. 4-6SCCh. 5.1 - Prob. 5-1SCCh. 5.1 - Prob. 5-2SCCh. 5.1 - Prob. 5-3SCCh. 5.1 - Prob. 5-4SCCh. 5.1 - Prob. 5-5SCCh. 5.1 - Prob. 5-6SCCh. 5.1 - Prob. 6-1SCCh. 5.1 - Prob. 6-2SCCh. 5.1 - Prob. 6-3SCCh. 5.1 - Prob. 6-4SCCh. 5.1 - Prob. 6-5SCCh. 5.1 - Prob. 6-6SCCh. 5.1 - Prob. 1SECh. 5.1 - Prob. 2SECh. 5.1 - Prob. 3SECh. 5.1 - Prob. 4SECh. 5.1 - Prob. 5SECh. 5.1 - Prob. 6SECh. 5.1 - Prob. 7SECh. 5.1 - Prob. 8SECh. 5.1 - Prob. 9SECh. 5.1 - Prob. 10SECh. 5.1 - Prob. 11SECh. 5.1 - Prob. 12SECh. 5.1 - Prob. 13SECh. 5.1 - Prob. 14SECh. 5.1 - Prob. 15SECh. 5.1 - Prob. 16SECh. 5.1 - Prob. 17SECh. 5.1 - Prob. 18SECh. 5.1 - Prob. 19SECh. 5.1 - Prob. 20SECh. 5.1 - Prob. 21SECh. 5.1 - Prob. 22SECh. 5.1 - Prob. 23SECh. 5.1 - Prob. 24SECh. 5.1 - Prob. 25SECh. 5.1 - Prob. 26SECh. 5.1 - Prob. 27SECh. 5.1 - Prob. 28SECh. 5.1 - Prob. 29SECh. 5.1 - Prob. 30SECh. 5.1 - Prob. 31SECh. 5.1 - Prob. 32SECh. 5.1 - Prob. 33SECh. 5.1 - Prob. 34SECh. 5.1 - Prob. 35SECh. 5.1 - Prob. 36SECh. 5.1 - Prob. 37SECh. 5.1 - Prob. 38SECh. 5.2 - Prob. 1-1SCCh. 5.2 - Prob. 1-2SCCh. 5.2 - Prob. 1-3SCCh. 5.2 - Prob. 1-4SCCh. 5.2 - Prob. 1-5SCCh. 5.2 - Prob. 1-6SCCh. 5.2 - Prob. 1SECh. 5.2 - Prob. 2SECh. 5.2 - Prob. 3SECh. 5.2 - Prob. 4SECh. 5.2 - Prob. 5SECh. 5.2 - Prob. 6SECh. 5.2 - Prob. 7SECh. 5.2 - Prob. 8SECh. 5.2 - Prob. 9SECh. 5.2 - Prob. 10SECh. 5.2 - Prob. 11SECh. 5.2 - Prob. 12SECh. 5.2 - Prob. 13SECh. 5.2 - Prob. 14SECh. 5.2 - Prob. 15SECh. 5.2 - Prob. 16SECh. 5.2 - Prob. 17SECh. 5.2 - Prob. 18SECh. 5.3 - Prob. 1-1SCCh. 5.3 - Prob. 1-2SCCh. 5.3 - Prob. 1-3SCCh. 5.3 - Prob. 1-4SCCh. 5.3 - Prob. 2-1SCCh. 5.3 - Prob. 2-2SCCh. 5.3 - Prob. 2-3SCCh. 5.3 - Prob. 2-4SCCh. 5.3 - Prob. 1SECh. 5.3 - Prob. 2SECh. 5.3 - Prob. 3SECh. 5.3 - Prob. 4SECh. 5.3 - Prob. 5SECh. 5.3 - Prob. 6SECh. 5.3 - Prob. 7SECh. 5.3 - Prob. 8SECh. 5.3 - Prob. 9SECh. 5.3 - Prob. 10SECh. 5.3 - Prob. 11SECh. 5.3 - Prob. 12SECh. 5.3 - Prob. 13SECh. 5.3 - Prob. 14SECh. 5.3 - Prob. 15SECh. 5.3 - Prob. 16SECh. 5 - Prob. 1ESCh. 5 - Prob. 2ESCh. 5 - Prob. 3ESCh. 5 - Prob. 4ESCh. 5 - Prob. 5ESCh. 5 - Prob. 6ESCh. 5 - Prob. 7ESCh. 5 - Prob. 8ESCh. 5 - Prob. 9ESCh. 5 - Prob. 10ESCh. 5 - Prob. 11ESCh. 5 - Prob. 12ESCh. 5 - Prob. 13ESCh. 5 - Prob. 14ESCh. 5 - Prob. 15ESCh. 5 - Prob. 16ESCh. 5 - Prob. 17ESCh. 5 - Prob. 18ESCh. 5 - Prob. 19ESCh. 5 - Prob. 20ESCh. 5 - Prob. 21ESCh. 5 - Prob. 22ESCh. 5 - Prob. 23ESCh. 5 - Prob. 24ESCh. 5 - Prob. 25ESCh. 5 - Prob. 26ESCh. 5 - Prob. 27ESCh. 5 - Prob. 28ESCh. 5 - Prob. 29ESCh. 5 - Prob. 30ESCh. 5 - Prob. 31ESCh. 5 - Prob. 32ESCh. 5 - Prob. 33ESCh. 5 - Prob. 34ESCh. 5 - Prob. 35ESCh. 5 - Prob. 36ESCh. 5 - Prob. 37ESCh. 5 - Prob. 38ESCh. 5 - Prob. 39ESCh. 5 - Prob. 40ESCh. 5 - Prob. 41ESCh. 5 - Prob. 42ESCh. 5 - Prob. 43ESCh. 5 - Prob. 44ESCh. 5 - Prob. 45ESCh. 5 - Prob. 46ESCh. 5 - Prob. 47ESCh. 5 - Prob. 48ESCh. 5 - Prob. 49ESCh. 5 - Prob. 50ESCh. 5 - Prob. 1PTCh. 5 - Prob. 2PTCh. 5 - Prob. 3PTCh. 5 - Prob. 4PTCh. 5 - Prob. 5PTCh. 5 - Prob. 6PTCh. 5 - Prob. 7PTCh. 5 - Prob. 8PTCh. 5 - Prob. 9PTCh. 5 - Prob. 10PTCh. 5 - Prob. 11PTCh. 5 - Prob. 12PTCh. 5 - Prob. 13PTCh. 5 - Prob. 14PTCh. 5 - Prob. 15PTCh. 5 - Prob. 16PTCh. 5 - Prob. 17PTCh. 5 - Prob. 18PTCh. 5 - Prob. 19PTCh. 5 - Prob. 20PTCh. 5 - Prob. 21PTCh. 5 - Prob. 1CTCh. 5 - Prob. 2CTCh. 5 - Prob. 3CTCh. 5 - Prob. 4CTCh. 5 - Prob. 5CTCh. 5 - Prob. 6CTCh. 5 - Prob. 7CTCh. 5 - Prob. 8CTCh. 5 - Prob. 1CPCh. 5 - Prob. 2CPCh. 5 - Prob. 1CS1Ch. 5 - Prob. 2CS1Ch. 5 - Prob. 3CS1Ch. 5 - Prob. 1CS2Ch. 5 - Prob. 2CS2Ch. 5 - Prob. 3CS2Ch. 5 - Prob. 4CS2Ch. 5 - Prob. 1CS3Ch. 5 - Prob. 2CS3Ch. 5 - Prob. 3CS3Ch. 5 - Prob. 4CS3
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- Calculus lll May I please have an explanation about how to calculate the derivative of the surface (the dS) on the surface integral, and then explain the essentials of the surface integral?arrow_forwardFor the Big-M tableau (of a maximization LP and row0 at bottom and M=1000), Z Ꮖ 1 x2 x3 81 82 83 e4 a4 RHS 0 7 0 0 1 0 4 3 -3 20 0 -4.5 0 0 0 1 -8 -2.5 2.5 6 0 7 0 1 0 0 8 3 -3 4 0 -1 50 1 0 0 0-2 -1 1 4 0000 0 30 970 200 If the original value of c₁ is increased by 60, what is the updated value of c₁ (meaning keeping the same set for BV. -10? Having made that change, what is the new optimal value for ž?arrow_forward32. Consider a normally distributed population with mean μ = 80 and standard deviation σ = 14. a. Construct the centerline and the upper and lower control limits for the chart if samples of size 5 are used. b. Repeat the analysis with samples of size 10. 2080 101 c. Discuss the effect of the sample size on the control limits.arrow_forward
- Consider the following hypothesis test. The following results are for two independent samples taken from the two populations. Sample 1 Sample 2 n 1 = 80 n 2 = 70 x 1 = 104 x 2 = 106 σ 1 = 8.4 σ 2 = 7.6 What is the value of the test statistic? If required enter negative values as negative numbers (to 2 decimals). What is the p-value (to 4 decimals)? Use z-table. With = .05, what is your hypothesis testing conclusion?arrow_forwardPeriodically, Merrill Lynch customers are asked to evaluate Merrill Lynch financial consultants and services (2000 Merrill Lynch Client Satisfaction Survey). Higher ratings on the client satisfaction survey indicate better service with 7 the maximum service rating. Independent samples of service ratings for two financial consultants are summarized here. Consultant A has 10 years of experience, whereas consultant B has 1 year of experience. Use = .05 and test to see whether the consultant with more experience has the higher population mean service rating. Consultant A Consultant B = 16 = 10 = 6.82 = 6.25 = .64 = .75 State the null and alternative hypotheses.H0: 1 - 2 Ha: 1 - 2 Compute the value of the test statistic (to 2 decimals). What is the p-value?The p-value is What is your conclusion?arrow_forwardA firm paid its first annual dividend yesterday in the amount of $.15 per share. The company plans to double the dividend in each of the next 3 years. Starting in Year 4, the firm plans to pay $1.50 per share indefinitely. What is one share of this stock worth today if the market rate of return on similar securities is 13.8 percent? Multiple Choice $11.79 $8.92 $10.77 $11.02 $10.26arrow_forward
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