The conditional probability function for the random variables X and Y is 0 P(Y/X) = x0 [0.9 10.1 y 1 2 0.1 0 0.8 0.1 2 0 0.1 0.9. With P(x=0)=0.2, P(x-1)=0.4. Find P(X,Y), Hx, My, E(XY), OXY.
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- The velocity of a particle in a gas is a random variable X with probability distribution fx(x) = 32x²e-4x The kinetic energy of the particle is Y = 1/mX². Suppose that the mass of the particle is 64 yg. Find the probability distribution of Y. (Do not convert any units.) x >0.Let X be a random variable with mean E[X] = 20 and variance Var(X) = 3. Define Y = 3 – 6X. Calculate the mean and variance of Y.Suppose Y - Uniform(01,02) where the parameters and 02 take the values -4 and 6 respectively. Compute the probability P(Y < y) when y=0.00.
- For what values of k canf(x) = (1 − k)kx serve as the values of the probability distribution of arandom variable with the countably infinite range x =0, 1, 2, ...?Solve it correctly please. I will rate accordingly.Suppose that 40% of fruit flies possess a certain gene. We will randomly select fruit flies until we have found 3 flies with the gene. Let Y = 0, 1, 2, 3, 4, 5, be the random variable defined as the number of flies we must be select so that we obtain three flies with the gene. If f(y) denotes the probability function for Y, find f(8).
- Suppose that X and Y are independent random variables with probability densities and and g(x): = x > 2 elsewhere 2y, 0 < y < 1 elsewhere h(y) - Find the expected value of Z = XY. 10,Suppose that the probability that a patient admitted in a hospital is diagnosed with a certain type of cancer is 0.03. Suppose that on a given day io patients are admitted and X denotes the number of patients diagnosed with this type of cancer. The mean and the variance of X are: E(X)=0.4 and V(X)=0.384 O None of these O E(X)=0.5 and V(X)=0.475 O E(X)=0.3 and V(X)=0.291How were the correct answers of 8.0000 and 1.0000 attained?