
To proof: weather the quad

Answer to Problem 8CE
The quad
Explanation of Solution
Given information:
System figure:
Calculation:
The figure shows a quadrilateral
Find the sum of the above two
As per Theorem
For quadrilateral EFGH, HG and EF are cut by transversal HE and same-side interior angles are supplementary.
Therefore,
However, nothing more can be determined about quad
Therefore, quad
Chapter 5 Solutions
McDougal Littell Jurgensen Geometry: Student Edition Geometry
Additional Math Textbook Solutions
College Algebra with Modeling & Visualization (5th Edition)
Pre-Algebra Student Edition
Calculus: Early Transcendentals (2nd Edition)
College Algebra (7th Edition)
Algebra and Trigonometry (6th Edition)
Basic Business Statistics, Student Value Edition
- 5. 156 m/WXY = 59° 63 E 7. B E 101 C mFE = 6. 68° 8. C 17arrow_forward1/6/25, 3:55 PM Question: 14 Similar right triangles EFG and HIJ are shown. re of 120 √65 adjacent E hypotenuse adjaca H hypotenuse Item Bank | DnA Er:nollesup .es/prist Sisupe ed 12um jerit out i al F 4 G I oppe J 18009 90 ODPO ysma brs & eaus ps sd jon yem What is the value of tan J? ed on yem O broppo 4 ○ A. √65 Qx oppoEF Adj art saused taupe ed for yem 4 ○ B. √65 29 asipnisht riod 916 zelprisht rad √65 4 O ○ C. 4 √65 O D. VIS 9 OD elimiz 916 aelonsider saused supsarrow_forwardFind all anglesarrow_forward
- Find U V . 10 U V T 64° Write your answer as an integer or as a decimal rounded to the nearest tenth. U V = Entregararrow_forwardFind the area of a square whose diagonal is 10arrow_forwardDecomposition geometry: Mary is making a decorative yard space with dimensions as shaded in green (ΔOAB).Mary would like to cover the yard space with artificial turf (plastic grass-like rug). Mary reasoned that she could draw a rectangle around the figure so that the point O was at a vertex of the rectangle and that points A and B were on sides of the rectangle. Then she reasoned that the three smaller triangles resulting could be subtracted from the area of the rectangle. Mary determined that she would need 28 square meters of artificial turf to cover the green shaded yard space pictured exactly.arrow_forward
- 7. 11 m 12.7 m 14 m S V=B₁+ B2(h) 9.5 m 16 m h+s 2 na 62-19 = 37 +, M h² = Bu-29arrow_forwardwhat would a of a interscribed angle be with an arc of 93 degrees and inside abgles of 111 and 98arrow_forwardPlease complete through GeoGebra and present the screenshots of the results. Thanks! (This supports on how to submit it.)arrow_forward
- Elementary Geometry For College Students, 7eGeometryISBN:9781337614085Author:Alexander, Daniel C.; Koeberlein, Geralyn M.Publisher:Cengage,Elementary Geometry for College StudentsGeometryISBN:9781285195698Author:Daniel C. Alexander, Geralyn M. KoeberleinPublisher:Cengage Learning

