a.
Find the possible values of X.
a.

Answer to Problem 61E
The possible values of X are 0, 1, 2 and 3.
Explanation of Solution
From a large lot, three components are sampled, one at a time. The component is tested at that time it self and if the component passes the test it is denoted as success (S) and if the component fails the test it is considered as a failure (F). The random variable X denotes the number of success among the three components. It was found that 80% of the components succeed in passing the test.
Here, the random variable X represents the number of success among the three components. That is, the number of component that passes the test. Thus, the random variable X can take values 0, 1, 2 and 3.
b.
Find the
b.

Answer to Problem 61E
The probability
Explanation of Solution
Calculation:
Multiplication rule:
If the events A and B are independent, then
Here, a random sample of 3 components is taken. Each component is independent of the other. It was found that 80% of the components in the lot will pass the test. Thus, the probability of success (p) is 0.80.
The probability that all 3 components pass the test,
Thus, the probability
c.
Find the probability,
c.

Answer to Problem 61E
The probability
Explanation of Solution
Calculation:
The
The probability
Thus, the probability
d.
Find the probability,
d.

Answer to Problem 61E
The probability
The probability
Explanation of Solution
Calculation:
The event that the second component fails and the first and third succeed is denoted by SFS.
That is, the probability
Thus, the probability
The event that the first and second succeed and the third component fails is denoted by SSF.
That is, the probability
Thus, the probability
e.
Find the probability,
e.

Answer to Problem 61E
The probability
Explanation of Solution
Calculation:
The probability
Substitute the values from part (c) and (d).
Then the required probability is,
Thus, the probability
f.
Find the probability,
f.

Answer to Problem 61E
The probability
Explanation of Solution
Calculation:
The probability
The probability that a component will pass the test is 0.80, the probability that a component will fail the test is
Thus, the probability
g.
Find the probability,
g.

Answer to Problem 61E
The probability
Explanation of Solution
Calculation:
The probability
The probability that a component will fail the test is
Thus, the probability
h.
Find the mean
h.

Answer to Problem 61E
The mean value is 2.4.
Explanation of Solution
Calculation:
The formula for the mean of a discrete random variable is,
The values of the random variable X and the corresponding probabilities obtained from parts (b), (e), (f) and (g) are given in the following table:
x | P(x) |
0 | 0.008 |
1 | 0.096 |
2 | 0.384 |
3 | 0.512 |
The mean of the random variable is obtained as given below:
x | P(x) | |
0 | 0.008 | 0.000 |
1 | 0.096 | 0.096 |
2 | 0.384 | 0.768 |
3 | 0.512 | 1.536 |
Total | 1.000 | 2.400 |
Thus, the mean value
i.
Find the standard deviation
i.

Answer to Problem 61E
The standard deviation
Explanation of Solution
Calculation:
The standard deviation of the random variable X is obtained by taking the square root of variance.
The formula for the variance of the discrete random variable X is,
Where
The variance of the random variable X is obtained using the following table:
x | P(x) | |||
0 | 0.008 | –2.4 | 5.76 | 0.04608 |
1 | 0.096 | –1.4 | 1.96 | 0.18816 |
2 | 0.384 | –0.4 | 0.16 | 0.06144 |
3 | 0.512 | 0.6 | 0.36 | 0.18432 |
Total | 1.000 | –3.6 | 8.24 | 0.48 |
Therefore,
Thus, the variance is 0.48.
The standard deviation is,
That is, the standard deviation is 0.6928.
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Chapter 5 Solutions
ALEKS 360 ESSENT. STAT ACCESS CARD
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