a. Solve the differential equation P ' ( t ) = − 0.6 P ( t ) , P ( 0 ) = 50 . b. Solve the differential equation P ' ( t ) = k P ( t ) , P ( 0 ) = 4000 , where k is some constant. c. Interpret the meaning of P ( 2 ) = 100 P ( 0 ) , where t is in hours. d. Find the value of k in part ( b ) for which P ( 2 ) = 100 P ( 0 ) .
a. Solve the differential equation P ' ( t ) = − 0.6 P ( t ) , P ( 0 ) = 50 . b. Solve the differential equation P ' ( t ) = k P ( t ) , P ( 0 ) = 4000 , where k is some constant. c. Interpret the meaning of P ( 2 ) = 100 P ( 0 ) , where t is in hours. d. Find the value of k in part ( b ) for which P ( 2 ) = 100 P ( 0 ) .
a. Solve the differential equation
P
'
(
t
)
=
−
0.6
P
(
t
)
,
P
(
0
)
=
50
.
b. Solve the differential equation
P
'
(
t
)
=
k
P
(
t
)
,
P
(
0
)
=
4000
, where
k
is some constant.
c. Interpret the meaning of
P
(
2
)
=
100
P
(
0
)
, where
t
is in hours.
d. Find the value of
k
in part
(
b
)
for which
P
(
2
)
=
100
P
(
0
)
.
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
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