Explanation Given Information: The provided matrices are A = [ 0 − 1 1 0 − 1 2 ] , B = [ 0.25 − 1 0 0.5 − 1 3 ] and C = [ 1 − 1 1 1 − 1 − 1 ] . Formula used: A matrix with m rows and n columns is of dimension m × n , where, m and n are positive integers. For two matrices A and B with equal dimensions, A + B and A − B is the sum and difference of the corresponding entries of the matrices respectively as, ( A + B ) i j = A i j + B i j ( A − B ) i j = A i j − B i j Calculation: Consider the matrices, A = [ 0 − 1 1 0 − 1 2 ] , B = [ 0.25 − 1 0 0.5 − 1 3 ] and C = [ 1 − 1 1 1 − 1 − 1 ] Recall that, a matrix with m rows and n columns is of dimension m × n , where, m and n are positive integers. Here, number of rows in A = [ 0 − 1 1 0 − 1 2 ] is 3 and number of columns is 2 . Substitute 3 for m and 2 for n in m × n , Thus, dimension of A = [ 0 − 1 1 0 − 1 2 ] is 3 × 2 . Now, number of rows in B = [ 0.25 − 1 0 0.5 − 1 3 ] is 3 and number of columns is 2 . Substitute 3 for m and 2 for n in m × n , Thus, dimension of B = [ 0.25 − 1 0 0.5 − 1 3 ] is 3 × 2

Finite Mathematics and Applied Calculus (MindTap Course List)

7th Edition

ISBN: 9781337274203

Author: Stefan Waner, Steven Costenoble

Publisher: Cengage Learning

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Chapter 5.1, Problem 15E

To determine

To calculate: The value of A+B−C, where, A=[0−110−12], B=[0.25−100.5−13] and C=[1−111−1−1].

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Chapter 5.1, Problem 14E

Chapter 5.1, Problem 16E

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Chapter 5 Solutions

Finite Mathematics and Applied Calculus (MindTap Course List)

Ch. 5.1 - In Exercises 110, find the dimensions of the given...Ch. 5.1 - Prob. 2E Ch. 5.1 - Prob. 3E Ch. 5.1 - Prob. 4E Ch. 5.1 - Prob. 5E Ch. 5.1 - In Exercises 110, find the dimensions of the given...Ch. 5.1 - Prob. 7E Ch. 5.1 - Prob. 8E Ch. 5.1 - Prob. 9E Ch. 5.1 - Prob. 10E

Ch. 5.1 - Solve for x,y,z,andw. [HINT: See Example 1.]...Ch. 5.1 - Prob. 12E Ch. 5.1 - Prob. 13E Ch. 5.1 - Prob. 14E Ch. 5.1 - Prob. 15E Ch. 5.1 - In Exercises 1320, evaluate the given expression....Ch. 5.1 - Prob. 17E Ch. 5.1 - Prob. 18E Ch. 5.1 - Prob. 19E Ch. 5.1 - Prob. 20E Ch. 5.1 - Prob. 21E Ch. 5.1 - Prob. 22E Ch. 5.1 - In Exercises 2128, evaluate the given expression....Ch. 5.1 - Prob. 24E Ch. 5.1 - Prob. 25E Ch. 5.1 - In Exercises 2128, evaluate the given expression....Ch. 5.1 - Prob. 27E Ch. 5.1 - Prob. 28E Ch. 5.1 - In Exercises 2936, use technology to evaluate the...Ch. 5.1 - Prob. 30E Ch. 5.1 - Prob. 31E Ch. 5.1 - Prob. 32E Ch. 5.1 - Prob. 33E Ch. 5.1 - Prob. 34E Ch. 5.1 - Prob. 35E Ch. 5.1 - Prob. 36E Ch. 5.1 - Sales The following table shows the number of Mac...Ch. 5.1 - Home Prices The following table shows median home...Ch. 5.1 - Inventory The Left Coast Bookstore chain has two...Ch. 5.1 - Inventory The Left Coast Bookstore chain discussed...Ch. 5.1 - Prob. 41E Ch. 5.1 - Revenue The following spreadsheet gives annual...Ch. 5.1 - 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The value of A + B − C , where, A = [ 0 − 1 1 0 − 1 2 ] , B = [ 0.25 − 1 0 0.5 − 1 3 ] and C = [ 1 − 1 1 1 − 1 − 1 ] .

Solution Summary: The author calculates the value of A+B-C based on m, B, and C.

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To calculate: The value of A+B−C, where, A=[0−110−12], B=[0.25−100.5−13] and C=[1−111−1−1].

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Chapter 5 Solutions