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Nonlinear Dynamics and Chaos
2nd Edition
ISBN: 9780813349107
Author: Steven H. Strogatz
Publisher: PERSEUS D
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Question
Chapter 5.1, Problem 12E
Interpretation Introduction
Interpretation:
To prove that orbits are closed for a simple harmonic oscillator using only symmetry properties of the
Concept Introduction:
Express the state of the system using current position and velocity.
Represent the system equation in vector field on the phase plane.
Visualize the vector field.
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Students have asked these similar questions
(i) For a given constant a > 0, let an investor's preference be represented by the
Gaussian utility function
U(w)=1-e-aw²
For what range of wealth level w will the investor be non-satiated and risk-averse?
Explain your answer.
(ii) Give an example of a utility function that exhibits DARA and verify it.
(iii) Determine the class of utility functions with relative risk aversion coefficient
R(w)= w², w> 0.
Sara (a 23 year old college graduate) is starting her first career. She met with a financial planner and has determined that she wants $1,000,000 when she retires at the age of 63. She has found an annuity that pays 4.25%, compounded quarterly.
What will she need to save each month, if Sara waits 20 years to start saving?
N:
P/Y:
I%:
C/Y:
PMT:
FV:
End or Begin
$4158.98
$4,115.26
$2645.83
$6,707.40
Sara (a 23 year old college graduate) is starting her first career. She met with a financial planner and has determined that she wants $1,000,000 when she retires at the age of 63. She has found an annuity that pays 4.25%, compounded quarterly.
What will she need to save each month, if
a) Sara begins saving now?
N:
P/Y:
I%:
C/Y:
PMT:
FV:
End or Begin
$1,323.80
$1,376.59
$794.74
$1,000,000
Chapter 5 Solutions
Nonlinear Dynamics and Chaos
Ch. 5.1 - Prob. 1ECh. 5.1 - Prob. 2ECh. 5.1 - Prob. 3ECh. 5.1 - Prob. 4ECh. 5.1 - Prob. 5ECh. 5.1 - Prob. 6ECh. 5.1 - Prob. 7ECh. 5.1 - Prob. 8ECh. 5.1 - Prob. 9ECh. 5.1 - Prob. 10E
Ch. 5.1 - Prob. 11ECh. 5.1 - Prob. 12ECh. 5.1 - Prob. 13ECh. 5.2 - Prob. 1ECh. 5.2 - Prob. 2ECh. 5.2 - Prob. 3ECh. 5.2 - Prob. 4ECh. 5.2 - Prob. 5ECh. 5.2 - Prob. 6ECh. 5.2 - Prob. 7ECh. 5.2 - Prob. 8ECh. 5.2 - Prob. 9ECh. 5.2 - Prob. 10ECh. 5.2 - Prob. 11ECh. 5.2 - Prob. 12ECh. 5.2 - Prob. 13ECh. 5.2 - Prob. 14ECh. 5.3 - Prob. 1ECh. 5.3 - Prob. 2ECh. 5.3 - Prob. 3ECh. 5.3 - Prob. 4ECh. 5.3 - Prob. 5ECh. 5.3 - Prob. 6E
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