The Essentials of Computer Organization and Architecture
4th Edition
ISBN: 9781284045611
Author: Linda Null, Julia Lobur
Publisher: Jones & Bartlett Learning
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Chapter 5, Problem 9RETC
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Zero-address architecture:
It is a stack-based machine and all the operations are performed using values that are stored on the operand stack. Its Instruction set architecture allows the operations mentioned below:
- PUSH M: this instruction pushes the value stored at memory location M onto the operand stack.
- POP M: this instruction pops the operand stack and stores the value into the memory location M.
- OP: this instruction pops two values off the operand stack, performs the binary operation OP on the two values, and pushes the result back onto the operand stack.
One-address architecture:
An accumulator is used in this architecture in order to perform computations. Its Instruction set architecture allows the operations mentioned below:
- LOAD M: this instruction loads the value stored at memory location M into the accumulator.
- STORE M: this instruction stores the value in the accumulator into memory location M...
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using r language
I need help to solve a simple problem using Grover’s algorithm, where the solution is not necessarily known beforehand. The problem is a 2×2 binary sudoku with two rules:
• No column may contain the same value twice.
• No row may contain the same value twice.
Each square in the sudoku is assigned to a variable as follows:
We want to design a quantum circuit that outputs a valid solution to this sudoku. While using Grover’s algorithm for this task is not necessarily practical, the goal is to demonstrate how classical decision problems can be converted into oracles for Grover’s algorithm.
Turning the Problem into a Circuit
To solve this, an oracle needs to be created that helps identify valid solutions. The first step is to construct a classical function within a quantum circuit that checks whether a given state satisfies the sudoku rules.
Since we need to check both columns and rows, there are four conditions to verify:
v0 ≠ v1 # Check top row
v2 ≠ v3 # Check bottom row…
using r language
Chapter 5 Solutions
The Essentials of Computer Organization and Architecture
Ch. 5 - Prob. 1RETCCh. 5 - Prob. 2RETCCh. 5 - Prob. 3RETCCh. 5 - Prob. 4RETCCh. 5 - Prob. 5RETCCh. 5 - Prob. 6RETCCh. 5 - Prob. 7RETCCh. 5 - Prob. 8RETCCh. 5 - Prob. 9RETCCh. 5 - Prob. 10RETC
Ch. 5 - Prob. 11RETCCh. 5 - Prob. 12RETCCh. 5 - Prob. 13RETCCh. 5 - Prob. 14RETCCh. 5 - Prob. 15RETCCh. 5 - Prob. 16RETCCh. 5 - Prob. 17RETCCh. 5 - Prob. 18RETCCh. 5 - Prob. 19RETCCh. 5 - Prob. 20RETCCh. 5 - Prob. 21RETCCh. 5 - Prob. 22RETCCh. 5 - Prob. 23RETCCh. 5 - Prob. 24RETCCh. 5 - Prob. 25RETCCh. 5 - Prob. 1ECh. 5 - Prob. 2ECh. 5 - Prob. 3ECh. 5 - Prob. 4ECh. 5 - Prob. 5ECh. 5 - Prob. 6ECh. 5 - Prob. 7ECh. 5 - Prob. 8ECh. 5 - Prob. 9ECh. 5 - Prob. 10ECh. 5 - Prob. 11ECh. 5 - Prob. 12ECh. 5 - Prob. 13ECh. 5 - Prob. 14ECh. 5 - Prob. 15ECh. 5 - Prob. 16ECh. 5 - Prob. 17ECh. 5 - Prob. 18ECh. 5 - Prob. 19ECh. 5 - Prob. 20ECh. 5 - Prob. 21ECh. 5 - Prob. 22ECh. 5 - Prob. 23ECh. 5 - Prob. 24ECh. 5 - Prob. 25ECh. 5 - Prob. 26ECh. 5 - Prob. 27ECh. 5 - Prob. 28ECh. 5 - Prob. 29E
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