Chapter 5, Problem 9P

2. Jojoba oil is flowing through a ¾-nom stainless steel pipe at a flow rate of 1,850 lbm/h. After the velocity profile in the pipe is fully developed, the oil enters a heater, as shown in Figure P5.7. The length of the heater section is 5 ft. The properties of the jojoba oil at the average temperature in the heater section are given in Table P5.7. Determine the convective heat transfer coefficient inside the heater section of the pipe. ¾ nom stainless steel pipe Heater section L=5ft Fig. P5.7 TABLE P5.7 Thermophysical Properties of Jojoba Oil at the Average Temperature in the Heater P (lbm/ft³) 68.671 (Btu/lbm-R) 0.30339 μ (lbm/ft-s) 0.012095 k (Btu/h-ft-°F) 0.077424

1. Water is flowing inside of a 3-std type K copper tube at a flow rate of 1.2 kg/s. The average temperature of the water is 50°C. Cold, dry air at a temperature of 5°C and atmospheric pressure flows outside of the tube in cross flow with a velocity of 85 m/s. Determine the UA product for this tube under clean conditions.

Hints: Find the closed loop transfer function and then plot the step response for diFerentvalues of K in MATLAB. Show step response plot for different values of K.   Auto Controls Show solutions and provide matlab code NO COPIED ANSWERS OR WILL REPORT!!!!

37. The vertical shaft shown in Figure P12-37 is driven at a speed of 600 rpm with 4.0 hp entering through the bevel gear. Each of the two chain sprockets delivers 2.0 hp to the side to drive mixer blades in a chemical reactor vessel. The bevel gear has a diametral pitch of 5, a pitch diameter of 9.000 in, a face width of 1.31 in, and a pressure angle of 20°. Use SAE 4140 OQT 1000 steel for the shaft. See Chapter 10 for the methods for computing the forces on the bevel gear. Figure P12-37: P37-Bevel gear drive with two chain sprockets Each problem includes the following details: ■Design the complete shaft, including the specification of the overall geometry and the consideration of stress con- centration factors. The analysis would show the minimum acceptable diameter at each point on the shaft to be safe from the standpoint of strength. Homework Problems 12-24, 12-35, and 12-37 from textbook, done in spreadsheet form. Place drawings of the load, shear, and bending moment body diagrams…

35. The double-reduction, helical gear reducer shown in Figure P12-35 transmits 5.0 hp. Shaft 1 is the input, rotating at 1800 rpm and receiving power directly from an electric motor through a flexible coupling. Shaft 2 rotates at 900 rpm. Shaft 3 is the output, rotating at 300 rpm. A chain sprocket is mounted on the output shaft as shown and delivers the power upward. The data for the gears are given in Table 12-5. Each gear has a 1412° normal pressure angle and a 45° helix angle. The combinations of left- and right-hand helixes are arranged so that the axial forces oppose each other on shaft 2 as shown. Use SAE 4140 OQT 1200 for the shafts. Figure P12-35: P35-Double-reduction helical drive Each problem includes the following details: ■Design the complete shaft, including the specification of the overall geometry and the consideration of stress con- centration factors. The analysis would show the minimum acceptable diameter at each point on the shaft to be safe from the standpoint of…

Consider 0.65 kg of N2 at 300 K, 1 bar contained in a rigid tank connected by a valve to another rigid tank holding 0.3 kg of CO2 at 300 K, 1 bar. The valve is opened and gases are allowed to mix, achieving an equilibrium state at 290 K. Determine: (a) the volume of each tank, in m³. (b) the final pressure, in bar. (c) the magnitude of the heat transfer to or from the gases during the process, in kJ. (d) the entropy change of each gas and of the overall system, in kJ/K.

Bài 1. Cho cơ hệ như hình 1. Hình biểu diễn lược đổ cơ hệ tại vị trí cân bằng tĩnh. Trục tọa độ Oy hướng theo phương chuyển động của vật 1, gốc O đặt tại vị trí cân bằng của vật 1(tức khi lò xo biến dạng tĩnh). Bỏ qua khối lượng của thanh số 3. Vật rắn 2 là pulley 2 tầng đồng chất có bán kính ngoài 21, bán kính trong I, bán kính quán tính đối với trục qua tâm P-1.5, khối lượng m:. Vật rắn 4 là thanh thắng đồng chất có khối lượng m, chiều dài 1. Cho các số liệu: m = 2kg, m= = 5kg, m = 4kg, k=40(N/cm), ! – 0.8(m),r=0.1(m). Điều kiện đầu y; =0.5 cm );j = 10 cm/s) . Giả sử hệ dao động bé, Vật rắn 2 chuyển động lăn không trượt trên mặt phẳng ngang. 1. Viết phương trình chuyển động của hệ. 2. Xác định tần số dao động tự do của hệ. 3. Xác định đáp ứng dao động tự do của hệ. dây dây 1 2r Hình 1 y 3 -2 I k www. -2

Hints: Find the closed loop transfer function and then plot the step response for diFerentvalues of K in MATLAB. Show step response plot for different values of K.   Auto Controls Show solutions and provide matlab code NO COPIED ANSWERS OR WILL REPORT

Obtain the response of the system shown below for a parabolic or acceleration input r(t);where Auto Controls Show full solution