EBK ACTIVITIES MANUAL FOR PROGRAMMABLE
EBK ACTIVITIES MANUAL FOR PROGRAMMABLE
5th Edition
ISBN: 8220102795983
Author: Petruzella
Publisher: YUZU
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Chapter 5, Problem 8P

Explanation of Solution

a.

Required instruction:

The required instruction for accomplishing the desired task is “Examine If Open (XIO)”.

Because of the following reasons

  • When the conveyor mot...

Explanation of Solution

b.

Required instruction:

The required instruction for accomplishing the desired task is “XIC”.

Because of the following reasons

  • In this case, the pushbutton is normally open switch...

Explanation of Solution

c.

Required instruction:

The required instruction for accomplishing the desired task is “XIC”.

Because of the following reasons

  • In this case, the pushbutton is normally closed switch.
  • While at rest, the push button applies power to the input module and the data table bit is ON...

Explanation of Solution

d.

Required instruction:

The required instruction for accomplishing the desired task is “XIC”.

Because of the following reasons

  • In this case, the limit switch is normally closed...

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Objective Implement Bottom-Up Iterative MergeSort and analyze its efficiency compared to recursive MergeSort. Unlike the recursive approach, which involves multiple function calls and stack overhead, the bottom-up version sorts iteratively by merging small subarrays first, reducing recursion depth and improving performance. Task 1. Implement Bottom-Up Iterative MergeSort о Start with single-element subarrays and iteratively merge them into larger sorted sections. Use a loop-based merging process instead of recursion. ○ Implement an efficient in-place merging strategy if possible. 2. Performance Analysis Compare execution time with recursive MergeSort on random, nearly sorted, and reversed datasets. ○ Measure and plot time complexity vs. input size. O Submission Explain why the iterative version reduces function call overhead and when it performs better. • Code implementation with comments. • A short report (1-2 pages) comparing performance. • Graph of execution time vs. input size for…
Given a shared data set, we allow multiple readers to read at the same time, and only one single writer can access the shared data at the same time. In the lecture slides, a solution is given. However, the problem is that the write cannot write forever, if there are always at least one reader. How to ensure that the writer can eventually write? Propose your solution by using semaphores and implemented in Python from threading import Thread, Semaphore from time import sleep from sys import stdout class Reader(Thread): def__init__(self, name): self.n=name; Thread.__init__(self) defrun(self): globalnr, nw, dr, dw whileTrue: # ⟨await nw == 0 then nr += 1⟩ e.acquire() ifnw>0: #if nw > 0 or dw > 0 : dr+=1; e.release(); r.acquire() nr+=1 ifdr>0: dr-=1; r.release() else: e.release() # read data stdout.write(self.n+' reading\n') sleep(1) # ⟨nr -= 1⟩ e.acquire() nr-=1 ifnr==0anddw>0: dw-=1 ; w.release() else: e.release() class Writer(Thread): def__init__(self, name):…
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