EBK ELEMENTARY STATISTICS USING EXCEL
7th Edition
ISBN: 9780136937401
Author: Triola
Publisher: VST
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Chapter 5, Problem 8CRE
To determine
To check: If the provided table is representing the
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Question 2
Parts manufactured by an injection molding process are subjected to a compressive strength test. Twenty samples
of five parts each are collected, and the compressive strengths (in psi) are shown in Table 2.
Table 2: Strength Data for Question 2
Sample Number
x1
x2
23
x4
x5
R
1
83.0
2
88.6 78.3 78.8
3
85.7
75.8
84.3
81.2 78.7 75.7 77.0
71.0 84.2
81.0
79.1
7.3
80.2 17.6
75.2
80.4
10.4
4
80.8
74.4
82.5
74.1 75.7 77.5
8.4
5
83.4
78.4
82.6 78.2
78.9
80.3
5.2
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6
75.3
79.9
87.3 89.7
81.8
82.8
14.5
7
74.5
78.0 80.8
73.4
79.7
77.3
7.4
8
79.2
84.4 81.5 86.0
74.5
81.1
11.4
9
80.5
86.2
76.2 64.1
80.2
81.4
9.9
10
75.7
75.2
71.1 82.1
74.3
75.7
10.9
11
80.0 81.5
78.4 73.8
78.1
78.4
7.7
12
80.6
81.8
79.3
73.8
81.7 79.4
8.0
13
82.7
81.3
79.1
82.0 79.5 80.9
3.6
14
79.2
74.9
78.6 77.7
75.3
77.1
4.3
15
85.5 82.1
82.8 73.4
71.7
79.1
13.8
16
78.8 79.6
80.2 79.1
80.8 79.7
2.0
17
82.1
78.2
18
84.5
76.9
75.5
83.5 81.2
19
79.0 77.8
20
84.5
73.1
78.2 82.1
79.2 81.1 7.6
81.2 84.4 81.6 80.8…
Name:
Lab Time:
Quiz 7 & 8 (Take Home) - due Wednesday, Feb. 26
Contingency Analysis (Ch. 9)
In lab 5, part 3, you will create a mosaic plot and conducted a chi-square contingency test to
evaluate whether elderly patients who did not stop walking to talk (vs. those who did stop)
were more likely to suffer a fall in the next six months. I have tabulated the data below.
Answer the questions below. Please show your calculations on this or a separate sheet.
Did not stop walking to talk
Stopped walking to talk Totals
Suffered a fall
Did not suffer a fall
Totals
12
11
23
2
35
37
14
14
46
60
Quiz 7:
1. (2 pts) Compute the odds of falling for each group. Compute the odds ratio for those
who did not stop walking vs. those who did stop walking. Interpret your result verbally.
Solve please and thank you!
Chapter 5 Solutions
EBK ELEMENTARY STATISTICS USING EXCEL
Ch. 5.1 - Prob. 1BSCCh. 5.1 - 2. Discrete or Continuous? Is the random variable...Ch. 5.1 - 3. Probability Distribution For the accompanying...Ch. 5.1 - Prob. 4BSCCh. 5.1 - Prob. 5BSCCh. 5.1 - Prob. 6BSCCh. 5.1 - Prob. 7BSCCh. 5.1 - Prob. 8BSCCh. 5.1 - Prob. 9BSCCh. 5.1 - Prob. 10BSC
Ch. 5.1 - Prob. 11BSCCh. 5.1 - Prob. 12BSCCh. 5.1 - Prob. 13BSCCh. 5.1 - Prob. 14BSCCh. 5.1 - Prob. 15BSCCh. 5.1 - Prob. 16BSCCh. 5.1 - Prob. 17BSCCh. 5.1 - Prob. 18BSCCh. 5.1 - Prob. 19BSCCh. 5.1 - Prob. 20BSCCh. 5.1 - Prob. 21BSCCh. 5.1 - Prob. 22BSCCh. 5.1 - Prob. 23BSCCh. 5.1 - Prob. 24BSCCh. 5.1 - Prob. 25BSCCh. 5.1 - Prob. 26BSCCh. 5.1 - Prob. 27BSCCh. 5.1 - Prob. 28BSCCh. 5.1 - Prob. 29BBCh. 5.1 - Prob. 30BBCh. 5.1 - Prob. 31BBCh. 5.1 - Prob. 32BBCh. 5.2 - Prob. 1BSCCh. 5.2 - Prob. 2BSCCh. 5.2 - Prob. 3BSCCh. 5.2 - Prob. 4BSCCh. 5.2 - Prob. 5BSCCh. 5.2 - Prob. 6BSCCh. 5.2 - Prob. 7BSCCh. 5.2 - Prob. 8BSCCh. 5.2 - Prob. 9BSCCh. 5.2 - Prob. 10BSCCh. 5.2 - Prob. 11BSCCh. 5.2 - Prob. 12BSCCh. 5.2 - Prob. 13BSCCh. 5.2 - Prob. 14BSCCh. 5.2 - Prob. 15BSCCh. 5.2 - Prob. 16BSCCh. 5.2 - Prob. 17BSCCh. 5.2 - Prob. 18BSCCh. 5.2 - Prob. 19BSCCh. 5.2 - Prob. 20BSCCh. 5.2 - Prob. 21BSCCh. 5.2 - Prob. 22BSCCh. 5.2 - Prob. 23BSCCh. 5.2 - Prob. 24BSCCh. 5.2 - 25. Whitus v. Georgia In the classic legal case of...Ch. 5.2 - Prob. 26BSCCh. 5.2 - Prob. 27BSCCh. 5.2 - Prob. 28BSCCh. 5.2 - Prob. 29BSCCh. 5.2 - Prob. 30BSCCh. 5.2 - Prob. 31BSCCh. 5.2 - Prob. 32BSCCh. 5.2 - Prob. 33BSCCh. 5.2 - Prob. 34BSCCh. 5.2 - Prob. 35BSCCh. 5.2 - Prob. 36BSCCh. 5.2 - Prob. 38BSCCh. 5.2 - Prob. 39BSCCh. 5.2 - Prob. 40BSCCh. 5.2 - Prob. 41BBCh. 5.2 - Prob. 42BBCh. 5.2 - Prob. 43BBCh. 5.3 - Prob. 1BSCCh. 5.3 - Prob. 2BSCCh. 5.3 - Prob. 3BSCCh. 5.3 - Prob. 4BSCCh. 5.3 - Prob. 5BSCCh. 5.3 - Prob. 6BSCCh. 5.3 - Prob. 7BSCCh. 5.3 - Prob. 8BSCCh. 5.3 - Prob. 9BSCCh. 5.3 - Prob. 10BSCCh. 5.3 - 11. Radioactive Decay Radioactive atoms are...Ch. 5.3 - 12. Deaths from Horse Kicks A classical example of...Ch. 5.3 - 13. World War II Bombs In Exercise 1“Notation” we...Ch. 5.3 - Prob. 14BSCCh. 5.3 - Prob. 17BBCh. 5 - Prob. 1CQQCh. 5 - Prob. 2CQQCh. 5 - Prob. 3CQQCh. 5 - Prob. 4CQQCh. 5 - Prob. 5CQQCh. 5 - Prob. 6CQQCh. 5 - Prob. 7CQQCh. 5 - Prob. 8CQQCh. 5 - Prob. 9CQQCh. 5 - Prob. 10CQQCh. 5 - Prob. 1RECh. 5 - Prob. 2RECh. 5 - Prob. 3RECh. 5 - Prob. 4RECh. 5 - Prob. 5RECh. 5 - Prob. 6RECh. 5 - Prob. 7RECh. 5 - Prob. 8RECh. 5 - Prob. 9RECh. 5 - Prob. 10RECh. 5 - 1. Planets The planets of the solar system have...Ch. 5 - Prob. 2CRECh. 5 - Prob. 3CRECh. 5 - Prob. 4CRECh. 5 - Prob. 5CRECh. 5 - Prob. 6CRECh. 5 - Prob. 7CRECh. 5 - Prob. 8CRECh. 5 - Prob. 1EPCh. 5 - Prob. 1FDD
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- 7. In a 2011 article, M. Radelet and G. Pierce reported a logistic prediction equation for the death penalty verdicts in North Carolina. Let Y denote whether a subject convicted of murder received the death penalty (1=yes), for the defendant's race h (h1, black; h = 2, white), victim's race i (i = 1, black; i = 2, white), and number of additional factors j (j = 0, 1, 2). For the model logit[P(Y = 1)] = a + ß₁₂ + By + B²², they reported = -5.26, D â BD = 0, BD = 0.17, BY = 0, BY = 0.91, B = 0, B = 2.02, B = 3.98. (a) Estimate the probability of receiving the death penalty for the group most likely to receive it. [4 pts] (b) If, instead, parameters used constraints 3D = BY = 35 = 0, report the esti- mates. [3 pts] h (c) If, instead, parameters used constraints Σ₁ = Σ₁ BY = Σ; B = 0, report the estimates. [3 pts] Hint the probabilities, odds and odds ratios do not change with constraints.arrow_forwardSolve please and thank you!arrow_forwardSolve please and thank you!arrow_forward
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