Explanation 1. Concept: We use kinematic equations to find speed of the refrigerator for certain time and certain distance separately. Also we use angle in the direction of motion and then we can take ratio of speed of refrigerator in case 2 to speed in case 1. 2. Formulae: i. V f = V i + a t ii. V f 2 = V i 2 + 2 a ∆ d iii. F = m a 3. Given: Force applied in horizontal direction and force applied with an angle. 4. Calculations: When refrigerator starts from rest V i = 0 we get. V f = 0 + a t Rearranging for a, a = V f t Using this acceleration in equation of force we get, F x = m a = m V f t F c o s α = m V f t V f = F c o s α t m … … … … . ( 1 ) Similarly we can find a, V f 2 = 0 + 2 a ∆ x a = V f 2 2 ∆ x Using a in force equation, we get F x = m V f 2 2 ∆ x Rearranging it for Vf, V f 2 = F c o s α 2 ∆ x m V f = F c o s α 2 ∆ x m … … … .

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ISBN: 9781119500100

Author: Halliday

Publisher: MCGRAW-HILL HIGHER EDUCATION

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Chapter 5, Problem 84P

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To find:

(a) Ratio of refrigerator’s speed in case 2 to speed in case1 for t.

(b) Ratio of refrigerator’s speed in case 2 to speed in case 1 for d.

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Chapter 5, Problem 83P

Chapter 5, Problem 85P

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I. Pushing on a File Cabinet Bob has been asked to push a heavy file cabinet down the hall to another office. It's not on rollers, so there is a lot of friction. At time t = 0 seconds, he starts pushing it from rest with increasing force until it starts to move at t = 2 seconds. He pushes the file cabinet down the hall with varying amounts of force. The velocity versus time graph of the cabinet is shown below. A. On the graphs provided below, 1. draw the net force vs. time that would produce this velocity graph; 2. draw the friction force vs. time for this motion; 3. draw the applied force (Fon Cabinet by Bob) VS. time for this motion (the first two seconds of this graph have been drawn for you). Velocity (m/s) Applied Force (N) Friction Force (N) Net Force (N) A -m B -U time (s) D time (s) time (s) time (s)

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Chapter 5 Solutions

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(a) Ratio of refrigerator’s speed in case 2 to speed in case1 for t. (b) Ratio of refrigerator’s speed in case 2 to speed in case 1 for d.

Solution Summary: The author explains how they use kinematic equations to find speed of the refrigerator for certain time and certain distance separately.

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To find: (a) Ratio of refrigerator’s speed in case 2 to speed in case1 for t. (b) Ratio of refrigerator’s speed in case 2 to speed in case 1 for d.

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Chapter 5 Solutions

To find:

(a) Ratio of refrigerator’s speed in case 2 to speed in case1 for t.

(b) Ratio of refrigerator’s speed in case 2 to speed in case 1 for d.