Explanation Given data: Refer to the Figure P5.84 in the textbook for the blocks and pulley system. Mass of the right block ( M ) is 100 kg. When the right block is released from the rest, the right block takes 6 s to reach the floor. From the Figure, the right block is initially at the height of 1.0 m from the floor. Formula used: Write the expression for equilibrium equation of force for the y -component as follows. ∑ F y = 0 (1) Here, ∑ F y is the sum of the forces in the y -component. Write the expression for force due to the weight of the object as follows. w = m g (2) Here, m is the mass of the object, and g is the acceleration due to gravity, which is 9.8 m s 2 . Consider the initial position of the right block as reference position and write the expression of kinematic equation for the given system to find the acceleration of the block as follows. y f = y i + ( v y ) i ( t f − t i ) + 1 2 a M ( t f − t i ) 2 (3) Here, y i is the distance between reference position of the right block and initial position of the block, which is 0 m, y f is the distance between reference position of the right block and final position of the block, which is ( − 1 ) m (the negative sign is due to the movement of the right block towards the downward direction), ( v y ) i is the initial speed of right block, which is 0 m s , t i is the initial time, which is 0 s, t f is the final time (time taken by the block to reach the floor), which is 6 s, and a M is the acceleration of the right block. Explanation: Consider the rope as massless and the pulley as both massless and frictionless. Draw the free-body diagram for the given system as shown in Figure 1. In the free-body diagram, T R on m is the tension of the rope on the left block of the pulley ( m ) , T R on M is the tension of the rope on the right block of the pulley ( M ) , w → m is the weight of the left block, and w → M is the weight of the right block. Calculation of acceleration of right block: Modify the expression in equation (3) to find the acceleration of the right block as follows. a M = 2 { y f − y i − [ ( v y ) i ( t f − t i ) ] } ( t f − t i ) 2 Substitute 0 m for y i , ( − 1 ) m for y f , 0 m s for ( v y ) i , 0 s for t i , and 6 s for t f , a M = 2 { ( − 1 m ) − 0 m − [ ( 0 m s ) ( 6 s − 0 s ) ] } ( 6 s − 0 s ) 2 = 2 ( − 1 m − 0 m ) 36 s 2 = − 0.0555 m s 2 ≃ − 0.0556 m s 2 From the free-body diagram of the block m , write the expression for sum of the forces in the y -component by modifying the expression in equation (1) as follows. T R on m + ( − w m ) = m a m (4) From the given data, the acceleration of both the blocks is equal and opposite in the direction

College Physics: A Strategic Approach (4th Edition)

4th Edition

ISBN: 9780134609034

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

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Chapter 5, Problem 84GP

To determine

To find: The mass of the block on the left of the pulley.

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Chapter 5, Problem 83GP

Chapter 5, Problem 85MSPP

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Chapter 5 Solutions

College Physics: A Strategic Approach (4th Edition)

Ch. 5 - An object is subject to two forces that do not...Ch. 5 - Are the objects described here in static...Ch. 5 - Prob. 3CQ Ch. 5 - Prob. 4CQ Ch. 5 - An astronaut takes his bathroom scale to the moon...Ch. 5 - A light block of mass m and a heavy block of mass...Ch. 5 - a. Can the normal force on an object be directed...Ch. 5 - A ball is thrown straight up. Taking the drag...Ch. 5 - You are going sledding with your friends, sliding...Ch. 5 - Suppose you are holding a box in front of you and...

Ch. 5 - You are walking up an icy slope. Suddenly your...Ch. 5 - Three objects move through the air as shown in...Ch. 5 - Prob. 13CQ Ch. 5 - Raindrops can fall at different speeds; some fall...Ch. 5 - An airplane moves through the air at a constant...Ch. 5 - Is it possible for an object to travel in air...Ch. 5 - For Questions 17 through 20, determine the tension...Ch. 5 - For Questions 17 through 20, determine the tension...Ch. 5 - For Questions 17 through 20, determine the tension...Ch. 5 - For Questions 17 through 20, determine the tension...Ch. 5 - In Figure Q5.21, block 2 is moving to the right....Ch. 5 - The wood block in Figure Q5.22 is at rest on a...Ch. 5 - Prob. 23MCQ Ch. 5 - Prob. 24MCQ Ch. 5 - Prob. 25MCQ Ch. 5 - While standing in a low tunnel, you raise your...Ch. 5 - A 5.0 kg dog sits on the floor of an elevator that...Ch. 5 - A 3.0 kg puck slides due east on a horizontal...Ch. 5 - Eric has a mass of 60 kg. He is standing on a...Ch. 5 - Prob. 30MCQ Ch. 5 - A football player at practice pushes a 60 kg...Ch. 5 - Two football players are pushing a 60 kg blocking...Ch. 5 - Land Rover ads used to claim that their vehicles...Ch. 5 - A truck is traveling at 30 m/s on a slippery road....Ch. 5 - The three ropes in Figure P5.1 are tied to a...Ch. 5 - Prob. 2P Ch. 5 - Prob. 3P Ch. 5 - A construction crew would like to support a 1000...Ch. 5 - When you bend your knee, the quadriceps muscle is...Ch. 5 - An early submersible craft for deep-sea...Ch. 5 - Prob. 7P Ch. 5 - A 65 kg student is walking on a slackline, a...Ch. 5 - Prob. 9P Ch. 5 - The forces in Figure P5.10 are acting on a 2.0 kg...Ch. 5 - The forces in Figure P5.11 are acting on a 2.0 kg...Ch. 5 - A horizontal rope is tied to a 50 kg box on...Ch. 5 - Prob. 13P Ch. 5 - In a head-on collision, a car stops in 0.10 s from...Ch. 5 - An astronauts weight on earth is 800 N. What is...Ch. 5 - A woman has a mass of 55.0 kg. a. What is her...Ch. 5 - Prob. 17P Ch. 5 - a. How much force does an 80 kg astronaut exert on...Ch. 5 - It takes the elevator in a skyscraper 4.0 s to...Ch. 5 - Riders on the Power Tower are launched skyward...Ch. 5 - Zach, whose mass is 80 kg, is in an elevator...Ch. 5 - Prob. 22P Ch. 5 - Figure P5.23 shows the velocity graph of a 75 kg...Ch. 5 - Prob. 24P Ch. 5 - A 23 kg child goes down a straight slide inclined...Ch. 5 - Prob. 26P Ch. 5 - Two workers are sliding a 300 kg crate across the...Ch. 5 - A 4000 kg truck is parked on a 7.0 slope. How big...Ch. 5 - A 1000 kg car traveling at a speed of 40 m/s skids...Ch. 5 - It is friction that provides the force for a car...Ch. 5 - The rolling resistance for steel on steel is quite...Ch. 5 - Prob. 34P Ch. 5 - Prob. 35P Ch. 5 - Prob. 36P Ch. 5 - Prob. 38P Ch. 5 - Prob. 40P Ch. 5 - A 1000 kg car pushes a 2000 kg truck that has a...Ch. 5 - A 2200 kg truck has put its front bumper against...Ch. 5 - Blocks with masses of 1.0 kg, 2.0 kg, and 3.0 kg...Ch. 5 - Prob. 44P Ch. 5 - Prob. 45P Ch. 5 - Prob. 46P Ch. 5 - Each of 100 identical blocks sitting on a...Ch. 5 - A 500 kg piano is being lowered into position by a...Ch. 5 - Dana has a sports medal suspended by a long ribbon...Ch. 5 - Prob. 51GP Ch. 5 - Your forehead can withstand a force of about 6.0...Ch. 5 - A 50 kg box hangs from a rope. What is the tension...Ch. 5 - Prob. 54GP Ch. 5 - A 50 kg box hangs from a rope. What is the tension...Ch. 5 - A fisherman has caught a very large, 5.0 kg fish...Ch. 5 - Riders on the Tower of Doom, an amusement park...Ch. 5 - Prob. 58GP Ch. 5 - Seat belts and air bags save lives by reducing the...Ch. 5 - Prob. 60GP Ch. 5 - A 20,000 kg rocket has a rocket motor that...Ch. 5 - Youve always wondered about the acceleration of...Ch. 5 - Prob. 63GP Ch. 5 - An impala is an African antelope capable of a...Ch. 5 - Josh starts his sled at the top of a 3.0-m-high...Ch. 5 - Prob. 67GP Ch. 5 - Prob. 68GP Ch. 5 - Prob. 69GP Ch. 5 - Prob. 70GP Ch. 5 - Prob. 71GP Ch. 5 - Prob. 72GP Ch. 5 - Prob. 73GP Ch. 5 - Its possible for a determined group of people to...Ch. 5 - Prob. 75GP Ch. 5 - Prob. 77GP Ch. 5 - Prob. 79GP Ch. 5 - Prob. 80GP Ch. 5 - Prob. 82GP Ch. 5 - Prob. 83GP Ch. 5 - Prob. 84GP Ch. 5 - MCAT-Style Passage Problems Sliding on the Ice In...Ch. 5 - MCAT-Style Passage Problems Sliding on the Ice In...Ch. 5 - MCAT-Style Passage Problems Sliding on the Ice In...Ch. 5 - MCAT-Style Passage Problems Sliding on the Ice In...

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