DeGarmo's Materials and Processes in Manufacturing
12th Edition
ISBN: 9781118987674
Author: J. T. Black, Ronald A. Kohser
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 5, Problem 76RQ
To determine
Ways through which ionitriding be more attractive as compare to carburizing and nitriding.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
M
× Your answer is incorrect.
(Manometer) Determine the angle 0 of the inclined tube shown in figure below if the pressure at A is 1 psi greater than that at B.
1ft
SG=0.61
十
A
Ꮎ
1ft
SG=1.0
8.8 ft
0 =
Hi
15.20
deg
Air
I don't know how to solve this
Chapter 5 Solutions
DeGarmo's Materials and Processes in Manufacturing
Ch. 5 - What is heat treatment?Ch. 5 - What types of properties can be altered through...Ch. 5 - Why should people performing hot forming or...Ch. 5 - What is the broad goal of the processing heat...Ch. 5 - Why might equilibrium phase diagrams be useful...Ch. 5 - What are the A1, A3, and Acm lines?Ch. 5 - What are some possible objectives of annealing...Ch. 5 - Why might it be important to include a preceding...Ch. 5 - Describe the cooling conditions of a full anneal.Ch. 5 - Why are the hypereutectoid steels not...
Ch. 5 - Although full anneals often produce the softest...Ch. 5 - What is the major process difference between full...Ch. 5 - Although normalizing is less expensive than a full...Ch. 5 - Prob. 14RQCh. 5 - What types of steel would be candidates for a...Ch. 5 - How might steel composition influence the...Ch. 5 - Other than increasing strength, for what three...Ch. 5 - What are the six major mechanisms that can be used...Ch. 5 - Prob. 19RQCh. 5 - What is required for a metal to be a candidate for...Ch. 5 - What are the three steps in an age�hardening...Ch. 5 - What is the difference between a coherent...Ch. 5 - What is overaging? Why does strength decrease?Ch. 5 - Describe the various aging responses (maximum...Ch. 5 - What is the difference between natural and...Ch. 5 - Why might naturally aging aluminum rivets be...Ch. 5 - Why is it important not to expose precipitation...Ch. 5 - Why is it more difficult to understand the...Ch. 5 - What types of heating and cooling conditions are...Ch. 5 - What are the stable equilibrium phases for steels...Ch. 5 - What are some nonequilibrium structures that...Ch. 5 - Prob. 32RQCh. 5 - What is the major factor that influences the...Ch. 5 - For a given steel, describe the relative strengths...Ch. 5 - Most structure changes proceed to completion over...Ch. 5 - What is retained austenite, and why is it an...Ch. 5 - What types of steels are more prone to retained...Ch. 5 - Why are martensitic structures usually tempered...Ch. 5 - Why does tempering offer a spectrum of possible...Ch. 5 - In what ways is the quench�and�temper heat...Ch. 5 - What is a C�C�T diagram? Why is it more useful...Ch. 5 - What is the critical cooling rate, and how is it...Ch. 5 - What two features combine to determine the...Ch. 5 - What conditions are used to standardize the quench...Ch. 5 - How do the various locations of a Jominy test...Ch. 5 - How do the data collected from a Jominy test...Ch. 5 - What is the assumption that allows the data from a...Ch. 5 - What is hardenability? How is it different from...Ch. 5 - What capabilities are provided by...Ch. 5 - When selecting a steel for an application, what...Ch. 5 - What are the three stages of liquid quenching?Ch. 5 - What are some of the major advantages and...Ch. 5 - Why does brine provide faster cooling than water?Ch. 5 - Why is an oil quench less likely to produce quench...Ch. 5 - What are some of the attractive qualities of a...Ch. 5 - Prob. 56RQCh. 5 - Prob. 57RQCh. 5 - Prob. 58RQCh. 5 - Prob. 59RQCh. 5 - How might the thermally induced residual stresses...Ch. 5 - Prob. 61RQCh. 5 - Prob. 62RQCh. 5 - Prob. 63RQCh. 5 - What is thermomechanical processing?Ch. 5 - Prob. 65RQCh. 5 - Prob. 66RQCh. 5 - Prob. 67RQCh. 5 - Prob. 68RQCh. 5 - Prob. 69RQCh. 5 - Prob. 70RQCh. 5 - Prob. 71RQCh. 5 - Prob. 72RQCh. 5 - Prob. 73RQCh. 5 - Why does a carburized part have to be further...Ch. 5 - Prob. 75RQCh. 5 - Prob. 76RQCh. 5 - Prob. 77RQCh. 5 - Describe the distinguishing features of a box...Ch. 5 - What are some possible functions of artificial...Ch. 5 - Prob. 80RQCh. 5 - Prob. 81RQCh. 5 - Prob. 82RQCh. 5 - What are some current goals of the heat treatment...Ch. 5 - Prob. 1PCh. 5 - Prob. 2PCh. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - Prob. 5PCh. 5 - Prob. 6PCh. 5 - What problems might be expected if the material on...Ch. 5 - Describe some heat treatment processes or...Ch. 5 - Prob. 3CSCh. 5 - Prob. 4CSCh. 5 - Prob. 5CSCh. 5 - Prob. 6CSCh. 5 - Prob. 7CSCh. 5 - Prob. 8CS
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- 1. The maximum and minimum stresses as well as the shear stress seen subjected the piece in plane A-A. Assume it is a cylinder with a diameter of 12.7mm 2. Draw the Mohr circle for the stress state using software. 3. Selection of the material for the prosthesis, which must be analyzed from the point of safety and cost view.arrow_forwardFirst, define the coordinate system XY with its origin at O2 and X-axis passing through O4 asshown above, then based on the provided steps Perform coordinate transformation from XY to xy to get the trajectory of point P. Show all the steps and calcualtionsarrow_forwardI don't know how to solve thisarrow_forward
- Question 2 (40 Points) Consider the following double pendulum-like system with links ₁ and 12. The angles 0 and & could have angular velocities ėêk and êk, respectively, where ②k is a unit vector that points out of the page and is perpendicular to x and y. They could also have angular accelerations Ök and êk. The angle is defined relative to the angle 0. The link 12 is a spring and can extend or compress at a rate of 12. It can also have a rate of extension or compression Ï2. li y êr1 êe 12 χ 3 еф er2 ده لج 1) Express the velocity of the mass in terms of the unit vectors ê0, êr1, êø, and êr2, and any extension/contraction of the links (e.g.,. i; and Ï¿) (12 Points) 2) Express the acceleration of the mass in terms of the unit vectors ê¤, ê×1, êp, and êÃ2, and any extension/contraction of the links (e.g.,. İ; and Ï¿) (12 Points) 3) Express the velocity of the mass in terms of unit vectors î and ĵ that point in the x and y directions, respectively. Also include the appropriate,…arrow_forwardprovide step by step solutions for angles teta 3 and teta 4 by the vector loopmethod. Show work in: vector loop, vector equations, solution procedure.arrow_forward(Manometer) A tank is constructed of a series of cylinders having diameters of 0.35, 0.30, and 0.20 m as shown in the figure below. The tank contains oil, water, and glycerin and a mercury manometer is attached to the bottom as illustrated. Calculate the manometer reading, h. 0.11 m + SAE 30 Oil 0.13 m + Water 0.10 m Glycerin + 0.10 m Mercury h = marrow_forward
- P = A piston having a cross-sectional area of 0.40 m² is located in a cylinder containing water as shown in the figure below. An open U-tube manometer is connected to the cylinder as shown. For h₁ = 83 mm and h = 111 mm what is the value of the applied force, P, acting on the piston? The weight of the piston is negligible. Hi 5597.97 N P Piston Water Mercuryarrow_forwardStudent Name: Student Id: College of Applied Engineering Al-Muzahmiyah Branch Statics (AGE 1330) Section-1483 Quiz-2 Time: 20 minutes Date: 16/02/2025 Q.1. A swinging door that weighs w=400.0N is supported by hinges A and B so that the door can swing about a vertical' axis passing through the hinges (as shown in below figure). The door has a width of b=1.00m and the door slab has a uniform mass density. The hinges are placed symmetrically at the door's edge in such a way that the door's weight is evenly distributed between them. The hinges are separated by distance a=2.00m. Find the forces on the hinges when the door rests half-open. Draw Free body diagram also. [5 marks] [CLO 1.2] Mool b ర a 2.0 m B 1.0 marrow_forwardFor the walking-beam mechanism shown in Figure 3, find and plot the x and y coordinates of the position of the coupler point P for one complete revolution of the crank O2A. Use the coordinate system shown in Figure 3. Hint: Calculate them first with respect to the ground link 0204 and then transform them into the global XY coordinate system. y -1.75 Ꮎ Ꮎ 4 = 2.33 0242.22 L4 x AP = 3.06 L2 = 1.0 W2 31° B 03 L3 = 2.06 P 1 8 5 .06 6 7 P'arrow_forward
- The link lengths, gear ratio (2), phase angle (Ø), and the value of 02 for some geared five bar linkages are defined in Table 2. The linkage configuration and terminology are shown in Figure 2. For the rows assigned, find all possible solutions for angles 03 and 04 by the vector loop method. Show your work in details: vector loop, vector equations, solution procedure. Table 2 Row Link 1 Link 2 Link 3 Link 4 Link 5 λ Φ Ө a 6 1 7 9 4 2 30° 60° P y 4 YA B b R4 R3 YA A Gear ratio: a 02 d 05 r5 R5 R2 Phase angle: = 0₂-202 R1 05 02 r2 Figure 2. 04 Xarrow_forwardProblem 4 A .025 lb bullet C is fired at end B of the 15-lb slender bar AB. The bar is initially at rest, and the initial velocity of the bullet is 1500 ft/s as shown. Assuming that the bullet becomes embedded in the bar, find (a) the angular velocity @2 of the bar immediately after impact, and (b) the percentage loss of kinetic energy as a result of the impact. (c) After the impact, does the bar swing up 90° and reach the horizontal? If it does, what is its angular velocity at this point? Answers: (a). @2=1.6 rad/s; (b). 99.6% loss = (c). Ah2 0.212 ft. The bar does not reach horizontal. y X 4 ft 15 lb V₁ 1500 ft/s 0.025 lb C 30°7 B Aarrow_forwardsubject: combustion please include complete solution, no rounding off, with diagram/explanation etc. In a joule cycle, intake of the compressor is 40,000 cfm at 0.3 psig and 90 deg F. The compression ratio is 6.0 and the inlet temperature at the turbine portion is 1900R while at the exit, it is 15 psi. Calculate for the back work ratio in percent.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Precision Machining Technology (MindTap Course Li...Mechanical EngineeringISBN:9781285444543Author:Peter J. Hoffman, Eric S. Hopewell, Brian JanesPublisher:Cengage Learning
Welding: Principles and Applications (MindTap Cou...Mechanical EngineeringISBN:9781305494695Author:Larry JeffusPublisher:Cengage Learning
Precision Machining Technology (MindTap Course Li...
Mechanical Engineering
ISBN:9781285444543
Author:Peter J. Hoffman, Eric S. Hopewell, Brian Janes
Publisher:Cengage Learning
Welding: Principles and Applications (MindTap Cou...
Mechanical Engineering
ISBN:9781305494695
Author:Larry Jeffus
Publisher:Cengage Learning
Principles of Lubrication | Automobile Engineering; Author: Magic Marks;https://www.youtube.com/watch?v=MGbbSxZTdCQ;License: Standard Youtube License