Explanation Given: Mass of C H 3 O H = 25.8 g Temperature T = 86 o C = 86+273 .15 = 359 .15 K Pressure of H 2 ( g ) , P = 748 mmHg Explanation: To determine the volume of H 2 gas required for the formation of CH 3 OH , moles of H 2 are required that can be obtained on applying the stoichiometry of the given reaction. For this, the number of moles of CH 3 OH is calculated. The number of moles of CH 3 OH is given by Number of moles ( n CH 3 OH ) = Mass of CH 3 OH Molar mass of CH 3 OH The molar mass of CH 3 OH is calculated as Molar mass of C H 3 O H = 12 + 3 × 1 + 16 + 1 = 12 + 3 + 16 + 1 = 32 g / m o l [ ∵ a t o m i c m a s s o f C = 12 g / m o l , H = 1 g / m o l , a n d O = 16 g / m o l ] Substitute mass of CH 3 OH = 25.8 g and molar mass of CH 3 OH = 32.0 g / m o l in the above expression of number of moles to get Number of moles ( n CH 3 OH ) = 25 .8 g 32 .0 g /mol = 0 .80625 mol Therefore, n CH 3 OH is 0.80625 m o l . The given reaction is C O ( g ) + 2 H 2 ( g ) → C H 3 O H ( g ) As per the above reaction 1 mol of CH 3 OH is formed from the reaction of 2 mol H 2 with CO ∴ 0 .80625 mol of CH 3 OH is formed from the reaction of 2 mol H 2 with CO = 2 mol H 2 × 0 .80625 mol CH 3 OH 1 mol CH 3 OH ⇁ = 1

Chemistry: A Molecular Approach (4th Edition)

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ISBN: 9780134112831

Author: Nivaldo J. Tro

Publisher: PEARSON

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Chapter 5, Problem 73E

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To determine: Volume of hydrogen gas and carbon monoxide gas required for the formation of CH3OH.

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Chapter 5, Problem 72E

Chapter 5, Problem 74E

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Chemistry: A Molecular Approach (4th Edition)

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Volume of hydrogen gas and carbon monoxide gas required for the formation of CH 3 OH .

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To determine: Volume of hydrogen gas and carbon monoxide gas required for the formation of CH3OH.

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