Explanation Given: The volume of HBr is 15.0 mL , diffusion time of HBr is 1.0 min , volume of an unknown gas is 20 .3 mL , and diffusion time of an unknown gas is 1.0 min . Explanation: According to Graham’s law of diffusion, under similar conditions of temperature and pressure, the rate of diffusion of gases is inversely proportional to the square root of their molar mass as follows: rate A rate B = M B M A …… (1) Calculate rate of HBr as follows: rate A = V 1 t 1 Here, V 1 is volume of HBr gas and t 1 is the diffusion time of HBr gas. Substitute 15.0 mL for V 1 and 1.0 min for t 1 in above equation as follows: rate A = 15.0 mL 1.0 min = 15 mL/min Similarly, the rate of unknown gas will be as follows: rate B = V 2 t 2 Here, V 2 is volume of unknown gas and t 2 is the diffusion time of unknown gas

Chemistry: A Molecular Approach (4th Edition)

4th Edition

ISBN: 9780134112831

Author: Nivaldo J. Tro

Publisher: PEARSON

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Chapter 5, Problem 125E

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To determine: The molecular formula of the unknown gas.

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Chapter 5, Problem 124E

Chapter 5, Problem 126E

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Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. Select to Edit Arrows H H Select to Add Arrows > H CFCI: Select to Edit Arrows H Select to Edit Arrows

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Chemistry: A Molecular Approach (4th Edition)

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