Applied Statistics in Business and Economics
5th Edition
ISBN: 9780077837303
Author: David Doane, Lori Seward Senior Instructor of Operations Management
Publisher: McGraw-Hill Education
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Chapter 5, Problem 63CE
To determine
Identify the given
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Consider the time series X₁ and Y₁ = (I – B)² (I – B³)Xt. What transformations were
performed on Xt to obtain Yt?
seasonal difference of order 2
simple difference of order 5
seasonal difference of order 1
seasonal difference of order 5
simple difference of order 2
Calculate the 90% confidence interval for the population mean difference using the data in the attached image. I need to see where I went wrong.
Microsoft Excel snapshot for random sampling: Also note the formula used for the last
column
02
x✓ fx =INDEX(5852:58551, RANK(C2, $C$2:$C$51))
A
B
1
No.
States
2
1
ALABAMA
Rand No.
0.925957526
3
2
ALASKA
0.372999976
4
3
ARIZONA
0.941323044
5
4 ARKANSAS
0.071266381
Random Sample
CALIFORNIA
NORTH CAROLINA
ARKANSAS
WASHINGTON
G7
Microsoft Excel snapshot for systematic sampling:
xfx INDEX(SD52:50551, F7)
A
B
E
F
G
1
No.
States
Rand No. Random Sample
population
50
2
1 ALABAMA
0.5296685 NEW HAMPSHIRE
sample
10
3
2 ALASKA
0.4493186 OKLAHOMA
k
5
4
3 ARIZONA
0.707914 KANSAS
5
4 ARKANSAS 0.4831379 NORTH DAKOTA
6
5 CALIFORNIA 0.7277162 INDIANA
Random Sample
Sample Name
7
6 COLORADO 0.5865002 MISSISSIPPI
8
7:ONNECTICU 0.7640596 ILLINOIS
9
8 DELAWARE 0.5783029 MISSOURI
525
10
15
INDIANA
MARYLAND
COLORADO
Chapter 5 Solutions
Applied Statistics in Business and Economics
Ch. 5.1 - A credit card customer at Barnes and Noble can use...Ch. 5.1 - A survey asked tax accounting firms their business...Ch. 5.1 - A baseball player bats either left-handed (L) or...Ch. 5.1 - A die is thrown (1, 2, 3, 4, 5, 6) and a coin is...Ch. 5.2 - Prob. 5SECh. 5.2 - Prob. 6SECh. 5.2 - Prob. 7SECh. 5.2 - Prob. 8SECh. 5.2 - Prob. 9SECh. 5.2 - Prob. 10SE
Ch. 5.2 - Prob. 11SECh. 5.2 - Prob. 12SECh. 5.3 - Prob. 13SECh. 5.3 - Are these events collectively exhaustive or not?...Ch. 5.3 - Prob. 15SECh. 5.3 - Given P(A) = .70, P(B) = .30, and P(A B) = .00,...Ch. 5.3 - Prob. 17SECh. 5.3 - Prob. 18SECh. 5.3 - Prob. 19SECh. 5.3 - Prob. 20SECh. 5.3 - Prob. 21SECh. 5.3 - Prob. 22SECh. 5.4 - Given P(J) = .26, P(K) = .48. If A and B are...Ch. 5.4 - Given P(A) = .40, P(B) = .50. If A and B are...Ch. 5.4 - Prob. 25SECh. 5.4 - Prob. 26SECh. 5.4 - Prob. 27SECh. 5.4 - Prob. 28SECh. 5.4 - The probability that a student has a Visa card...Ch. 5.4 - Bob sets two alarm clocks (battery-powered) to be...Ch. 5.4 - A hospitals backup power system has three...Ch. 5.4 - Over 1,000 people try to climb Mt. Everest every...Ch. 5.4 - Suppose 50 percent of the customers at Pizza...Ch. 5.5 - Prob. 34SECh. 5.5 - The contingency table below summarizes a survey of...Ch. 5.5 - Prob. 36SECh. 5.5 - A survey of 156 introductory statistics students...Ch. 5.5 - This contingency table describes 200 business...Ch. 5.5 - Based on the previous problem, is major...Ch. 5.5 - The following contingency table shows average...Ch. 5.6 - Of grocery shoppers who have a shopping cart, 70...Ch. 5.6 - A study showed that 60 percent of The Wall Street...Ch. 5.7 - A drug test for athletes has a 5 percent false...Ch. 5.7 - Half of a set of the parts are manufactured by...Ch. 5.7 - An airport gamma ray luggage scanner coupled with...Ch. 5.8 - (a) Find 8! without a calculator. Show your work....Ch. 5.8 - Prob. 47SECh. 5.8 - In the Minnesota Northstar Cash Drawing, you pick...Ch. 5.8 - Prob. 49SECh. 5.8 - Prob. 50SECh. 5.8 - Until 2005, the UPC bar code had 12 digits (09)....Ch. 5.8 - Bob has to study for four final exams: accounting...Ch. 5.8 - Prob. 53SECh. 5.8 - Prob. 54SECh. 5.8 - Prob. 55SECh. 5.8 - Prob. 56SECh. 5 - Prob. 1CRCh. 5 - Prob. 2CRCh. 5 - Prob. 3CRCh. 5 - Prob. 4CRCh. 5 - Prob. 5CRCh. 5 - Prob. 6CRCh. 5 - Prob. 7CRCh. 5 - In a contingency table, explain the concepts of...Ch. 5 - Prob. 9CRCh. 5 - Prob. 10CRCh. 5 - Prob. 11CRCh. 5 - Prob. 60CECh. 5 - Prob. 61CECh. 5 - A judge concludes that there is a 20 percent...Ch. 5 - Prob. 63CECh. 5 - Prob. 64CECh. 5 - In the first year after its release, 83 percent of...Ch. 5 - Prob. 66CECh. 5 - Prob. 67CECh. 5 - If Punxsutawney Phil sees his shadow on February...Ch. 5 - Prob. 69CECh. 5 - Bob owns two stocks. There is an 80 percent...Ch. 5 - Prob. 71CECh. 5 - A study showed that trained police officers can...Ch. 5 - The probability that a 2011 Audi A8 will be stolen...Ch. 5 - The probability of being struck by lightning is...Ch. 5 - Prob. 75CECh. 5 - A certain model of remote-control Stanley garage...Ch. 5 - (a) In a certain state, license plates consist of...Ch. 5 - Prob. 78CECh. 5 - Prob. 79CECh. 5 - Prob. 80CECh. 5 - Prob. 81CECh. 5 - A certain airplane has two independent alternators...Ch. 5 - Prob. 83CECh. 5 - Prob. 84CECh. 5 - A turboprop aircraft has two attitude gyroscopes,...Ch. 5 - Which are likely to be independent events? For...Ch. 5 - In child-custody cases, about 70 percent of the...Ch. 5 - A web server hosting company advertises 99.999...Ch. 5 - Prob. 89CECh. 5 - The probability is 1 in 4,000,000 that a single...Ch. 5 - Prob. 91CECh. 5 - Prob. 92CECh. 5 - Four students divided the task of surveying the...Ch. 5 - Refer to the contingency table shown below. (a)...Ch. 5 - Prob. 95CECh. 5 - High levels of cockpit noise in an aircraft can...Ch. 5 - Prob. 97CECh. 5 - A biometric security device using fingerprints...Ch. 5 - Dolon Web Security Consultants requires all job...
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