Bundle: Comptia A+ Guide To It Technical Support, 10th + Mindtap, 1 Term Printed Access Card
10th Edition
ISBN: 9780357012789
Author: Jean Andrews, Joy Dark, Jill West
Publisher: Cengage Learning
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Chapter 5, Problem 5TC
Explanation of Solution
Given: A RAID technique which strips data from multiple disks to increase disk space and provides fault tolerance
To find: The RAID technique which strips the data and provides fault tolerance...
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Chapter 5 Solutions
Bundle: Comptia A+ Guide To It Technical Support, 10th + Mindtap, 1 Term Printed Access Card
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- What happens to MAC addresses as frames travel from one node (device) to another? What happens to MAC addresses as frames travel from one network to another? What happens to IP addresses as packets travel from one node (device) to another? What happens to IP addresses as packets travel from one network to another?arrow_forwardCan you check if my explation is correct: Challenge: Assume that the assigned network addresses are correct. Can you deduce (guess) what the network subnet masks are? Explain while providing subnet mask bits for each subnet mask. [Hint: Look at the addresses in binary and consider the host ids] To assume that the network addresses are correct, we take a look at the network ID and IP addresses. Take 20.0.0.0/8, we have an /8 prefix which is Class A, that provide us with 255.0.0.0. This means that there are 24 host bits while the network bits are 8. When compared to the IP address 20.255.0.7, we can perform an additional operation with the subnet mask giving us 20.0.0.0. The same happened with 20.0.0.89, which we also got 20.0.0.0. Therefore, these two IP addresses fall within the respective /8 subnet. For 200.100.10.0/30, the /30 is Class C with a subnet mask of 255.255.255.252, meaning 30 network bits and only two host bits. When applying the subnet mask and the IP addresses…arrow_forwardIt is possible to sort an array of n values using pipeline of n filter processes.The first process inputs all the values one at a time, keep the minimum, and passes the others on to the next process. Each filter does the same thing; it receives a stream of values from the previous process, keep the smallest, and passes the others to the next process. Assume each process has local storage for only two values--- the next input value and the minimum it has seen so far. (a) Developcode for filter processes. Declare the channels and use asynchronous message passing. Hint:Define an array of channels value[n] (int), and a set of filter processes Filter[i = 0 ton-1]. Each process Filter[i] (where 0 <= i <= n-2) receives a stream of integers through channelvalue[i], keeps the smallest, and sends all other integers to channel value[i+1]. The last processFilter[n-1] receives only one integer through channel value[n-1] and does not need to send anyinteger further.arrow_forward
- It is possible to sort an array of n values using pipeline of n filter processes.The first process inputs all the values one at a time, keep the minimum, and passes the others on to the next process. Each filter does the same thing; it receives a stream of values from the previous process, keep the smallest, and passes the others to the next process. Assume each process has local storage for only two values--- the next input value and the minimum it has seen so far. (a) Developcode for filter processes. Declare the channels and use asynchronous message passing. Hint:Define an array of channels value[n] (int), and a set of filter processes Filter[i = 0 ton-1]. Each process Filter[i] (where 0 <= i <= n-2) receives a stream of integers through channelvalue[i], keeps the smallest, and sends all other integers to channel value[i+1]. The last processFilter[n-1] receives only one integer through channel value[n-1] and does not need to send anyinteger further.arrow_forwardIt is possible to sort an array of n values using pipeline of n filter processes.The first process inputs all the values one at a time, keep the minimum, and passes the others on to the next process. Each filter does the same thing; it receives a stream of values from the previous process, keep the smallest, and passes the others to the next process. Assume each process has local storage for only two values--- the next input value and the minimum it has seen so far. (a) Developcode for filter processes. Declare the channels and use asynchronous message passing. Hint:Define an array of channels value[n] (int), and a set of filter processes Filter[i = 0 ton-1]. Each process Filter[i] (where 0 <= i <= n-2) receives a stream of integers through channelvalue[i], keeps the smallest, and sends all other integers to channel value[i+1]. The last processFilter[n-1] receives only one integer through channel value[n-1] and does not need to send anyinteger further.arrow_forwardIt is possible to sort an array of n values using pipeline of n filter processes.The first process inputs all the values one at a time, keep the minimum, and passes the others on to the next process. Each filter does the same thing; it receives a stream of values from the previous process, keep the smallest, and passes the others to the next process. Assume each process has local storage for only two values--- the next input value and the minimum it has seen so far. (a) Developcode for filter processes. Declare the channels and use asynchronous message passing. Hint:Define an array of channels value[n] (int), and a set of filter processes Filter[i = 0 ton-1]. Each process Filter[i] (where 0 <= i <= n-2) receives a stream of integers through channelvalue[i], keeps the smallest, and sends all other integers to channel value[i+1]. The last processFilter[n-1] receives only one integer through channel value[n-1] and does not need to send anyinteger further.arrow_forward
- It is possible to sort an array of n values using pipeline of n filter processes.The first process inputs all the values one at a time, keep the minimum, and passes the others on to the next process. Each filter does the same thing; it receives a stream of values from the previous process, keep the smallest, and passes the others to the next process. Assume each process has local storage for only two values--- the next input value and the minimum it has seen so far. (a) Developcode for filter processes. Declare the channels and use asynchronous message passing. Hint:Define an array of channels value[n] (int), and a set of filter processes Filter[i = 0 ton-1]. Each process Filter[i] (where 0 <= i <= n-2) receives a stream of integers through channelvalue[i], keeps the smallest, and sends all other integers to channel value[i+1]. The last processFilter[n-1] receives only one integer through channel value[n-1] and does not need to send anyinteger further.arrow_forwardI need help: Challenge: Assume that the assigned network addresses are correct. Can you deduce (guess) what the network subnet masks are? Explain while providing subnet mask bits for each subnet mask. [Hint: Look at the addresses in binary and consider the host ids]arrow_forwardI would like to know if my answer statment is correct? My answer: The main difference is how routes are created and maintained across different networks. Static routing establishes router connections to different networks from the far left and far right. The Dynamic routing focus emphasizes immediate connection within the router while ignoring the other connections from different networks. Furthermore, the static routing uses the subnet mask to define networks such as 25.0.0.0/8, 129.60.0.0/16, and 200.100.10.0/30, which correspond to 255.0.0.0, 255.255.0.0, and 255.255.255.252. On the other hand, dynamic routing uses the wildcard mask to inverse the subnet mask, where network bits become 0 and host bits become 1, giving us 0.0.0.255, 0.0.255.255, and 0.0.0.3. Most importantly, the CLI commands used for Static and Dynamic routing are also different. For static routing, the “IP route” corresponds with the network, subnet mask, and next-hop IP address. In contrast, dynamic routing uses…arrow_forward
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