Explanation The required reaction is given below. 2 B r C l ( g ) ⇌ B r 2 ( g ) + C l 2 ( g ) , K = 32 The expression for equilibrium constant for the above reaction can be written as shown below, K = ( P B r 2 ) ( P C l 2 ) ( P B r C l ) 2 Given that, the initial partial pressure of B r C l is 3.30 m b a r . An equilibrium table can be set up as given below. C o m p o s i t i o n ( m b a r ) B r C l B r 2 C l 2 I n i t i a l p r e s s u r e 3.30 0 0 C h a n g e i n p r e s s u r e − 2 x + x + x E q u i l i b r i u m p r e s s u r e 3.30 − 2 x x x Now, these values in the fourth row can be inserted in the equilibrium constant expression as shown below. K = ( x ) ( x ) ( 3

Chemical Principles: The Quest for Insight

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Author: Peter Atkins, Loretta Jones, Leroy Laverman

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Chapter 5, Problem 5I.4AST

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Interpretation:

The equilibrium partial pressure of BrCl in the reaction mixture has to be calculated. The reaction is given below.

2BrCl(g)⇌Br2(g)+Cl2(g), K=32

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Chapter 5, Problem 5I.3BST

Chapter 5, Problem 5I.4BST

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Chapter 5 Solutions

Chemical Principles: The Quest for Insight

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Chemical Equilibria and Reaction Quotients; Author: Professor Dave Explains;https://www.youtube.com/watch?v=1GiZzCzmO5Q;License: Standard YouTube License, CC-BY

The equilibrium partial pressure of B r C l in the reaction mixture has to be calculated. The reaction is given below. 2 B r C l ( g ) ⇌ B r 2 ( g ) + C l 2 ( g ) , K = 32

Solution Summary: The author explains how the equilibrium partial pressure of BrCl in the reaction mixture has to be calculated.

Videos

Interpretation:

The equilibrium partial pressure of BrCl in the reaction mixture has to be calculated. The reaction is given below.

2BrCl(g)⇌Br2(g)+Cl2(g), K=32

Want to see the full answer?

Chapter 5 Solutions

The equilibrium partial pressure of B r C l in the reaction mixture has to be calculated. The reaction is given below. 2 B r C l ( g ) ⇌ B r 2 ( g ) + C l 2 ( g ) , K = 32

Solution Summary: The author explains how the equilibrium partial pressure of BrCl in the reaction mixture has to be calculated.

Videos

Interpretation: The equilibrium partial pressure of BrCl in the reaction mixture has to be calculated. The reaction is given below. 2BrCl(g)⇌Br2(g)+Cl2(g), K=32

Want to see the full answer?

Chapter 5 Solutions

Interpretation:

The equilibrium partial pressure of BrCl in the reaction mixture has to be calculated. The reaction is given below.

2BrCl(g)⇌Br2(g)+Cl2(g), K=32