Methanol (CH 4 O), which is used as a fuel in high-performance racing cars, burns in the presence of O 2 to form CO 2 and H 2 O. The molar masses for all substances are given under the balanced equation. 2CH 4 O(l) + 3 O 2 ( g ) → 2 CO 2 (g), + 4H 2 O(g) 32 .04 g/mol 32 .00 g/mol 44 .01 g/mol 18 .02 g/mol What is the theoretical yield of CO 2 from 48.0 g of methanol? What is the percent yield of CO 2 if 48.0 g of CO 2 are formed?
Methanol (CH 4 O), which is used as a fuel in high-performance racing cars, burns in the presence of O 2 to form CO 2 and H 2 O. The molar masses for all substances are given under the balanced equation. 2CH 4 O(l) + 3 O 2 ( g ) → 2 CO 2 (g), + 4H 2 O(g) 32 .04 g/mol 32 .00 g/mol 44 .01 g/mol 18 .02 g/mol What is the theoretical yield of CO 2 from 48.0 g of methanol? What is the percent yield of CO 2 if 48.0 g of CO 2 are formed?
Solution Summary: The author explains how the theoretical yield of CO_2 from 48.0 g of methanol should be predicted.
Methanol
(CH
4
O),
which is used as a fuel in high-performance racing cars, burns in the presence of O2 to form CO2 and H2O. The molar masses for all substances are given under the balanced equation.
2CH
4
O(l)
+
3
O
2
(
g
)
→
2
CO
2
(g), + 4H
2
O(g)
Construct a molecular orbital diagram for carbon monoxide. Identify the relevant point group,include all of the appropriate symmetry labels and pictures, and fill in the electrons. Make sure toaccount for the difference in electronegativity between C and O. Hint: CO is substantiallyisoelectronic to N2. (PLEASE DRAW THE ENTIRE MO DIAGRAM!!!)
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