(a) Explanation Given info: The mass of aluminum block is 2.00 kg , the mass of copper block is 6.00 kg . The angle of the incline is 30.0 ° The coefficient o friction of aluminum on steel is 0.61 and the coefficient of kinetic friction of copper on steel is 0.53 . The acceleration due gravity is 9.8 m / s 2 . The expression for the force to cause motion, F m = m c g sin θ Here, g is the acceleration due to gravity. m c is the mass of copper block. θ is the incline angle. Substitute 6.00 kg for m c , 9.8 m / s 2 for g and 30.0 ° for θ in the above equation. F m = ( 6.00 kg ) ( 9.8 m / s 2 ) sin ( 30.0 ° ) = 29.4 N The expression for the force of friction is, F = μ k n Here, μ k is the coefficient of friction. n is the force normal to block. For copper block: Substitute F c for F , μ kc for μ k , m c g cos θ for n in the above expression. F c = μ kc m c g cos θ For aluminum block: Substitute F a for F , μ ka for μ k , m a g for n in the above expression (b) To determine The acceleration of the block. (c) To determine The tension in the string. (d) To determine The sum of the magnitude of friction forces that act on the block.

9th Edition

ISBN: 8220100461262

Author: SERWAY

Publisher: Cengage Learning US

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Newton's Second Law

Newton’s laws of motion describe the relationship between the motion of an object and forces acting on it. Newton’s law of motion has two types as follows:

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Chapter 5, Problem 5.84AP

(a)

To determine

Whether the masses move or remain at rest.

(b)

To determine

The acceleration of the block.

(c)

To determine

The tension in the string.

(d)

To determine

The sum of the magnitude of friction forces that act on the block.

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Chapter 5, Problem 5.83AP

Chapter 5, Problem 5.85AP

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Whether the masses move or remain at rest.

Solution Summary: The author explains how the masses move or remain at rest.

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Whether the masses move or remain at rest.

The acceleration of the block.

The tension in the string.

The sum of the magnitude of friction forces that act on the block.

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Chapter 5 Solutions