Chapter 5, Problem 5.83P

Interpretation Introduction

(a)

Interpretation:

The number of molecules present in 2.00 mol of butane $C_4{H}_{10}$ is to be determined.

Concept Introduction:

The total number of molecules is determined by the multiplication of the total number of moles with the number of a molecule present in a mole.

This relation is given as-

  $totalnumberofmoles\times \frac{6.02\times {10}^{23}atoms}{1mol}$

Answer to Problem 5.83P

The number of molecules present in 2.0 mol of butane is $1.20\times {10}^{24}molecule$.

Explanation of Solution

The number of atoms or molecules present in a mole = $6.02\times {10}^{23}$

The following steps will be used to calculate the number of atoms present in each number of moles

The conversion factor is to be chosen to cancel out the mol unit.

  $\frac{1mole}{6.02\times {10}^{23}atoms}$ or $\frac{6.02\times {10}^{23}atoms}{1mole}$

Solve the problem:

  $2.0mol\times \frac{6.02\times {10}^{23}molecule}{1mol}=12.0\times {10}^{23}molecule$

The number of molecules present in 2.0 mol of butane is $1.20\times {10}^{24}molecule$.

Interpretation Introduction

(b)

Interpretation:

The number of molecules present in 0.250mol of butane $C_4{H}_{10}$ is to be determined.

Concept Introduction:

The total number of molecules is determined by the multiplication of the total number of moles with the number of a molecule present in a mole.

This relation is given as-

  $totalnumberofmoles\times \frac{6.02\times {10}^{23}atoms}{1mol}$

Answer to Problem 5.83P

The number of molecules present in 0.250mol of butane is $1.51\times {10}^{23}molecule$.

Explanation of Solution

The number of atoms or molecules present in a mole = $6.02\times {10}^{23}$

The conversion factor is to be chosen to cancel out the mol unit.

  $\frac{1mole}{6.02\times {10}^{23}atoms}$ or $\frac{6.02\times {10}^{23}atoms}{1mole}$

Solve the problem −

  $0.25mol\times \frac{6.02\times {10}^{23}molecule}{1mol}=1.51\times {10}^{23}molecule$

The number of molecules present in 0.250 mol of butane is $1.51\times {10}^{23}molecule$.

Interpretation Introduction

(c)

Interpretation:

The number of molecules present in 26.5 mol of butane $C_4{H}_{10}$ is to be determined.

Concept Introduction:

The total number of molecules is determined by the multiplication of the total number of moles with the number of a molecule present in a mole.

This relation is given as-

  $totalnumberofmoles\times \frac{6.02\times {10}^{23}atoms}{1mol}$

Answer to Problem 5.83P

The number of molecules present in 26.5 mol of butane is $1.6\times {10}^{25}molecule$.

Explanation of Solution

The conversion factor is to be chosen to cancel out the mol unit.

  $\frac{1mole}{6.02\times {10}^{23}atoms}$ or $\frac{6.02\times {10}^{23}atoms}{1mole}$

Solve the problem −

  $26.5mol\times \frac{6.02\times {10}^{23}molecule}{1mol}=159.53\times {10}^{23}molecule=1.6\times {10}^{25}molecule$

The number of molecules present in 26.5 mol of butane is $1.6\times {10}^{25}molecule$.

Interpretation Introduction

(d)

Interpretation:

The number of molecules present in 222 mol of butane $C_4{H}_{10}$ is to be determined.

Concept Introduction:

The total number of molecules is determined by the multiplication of the total number of moles with the number of a molecule present in a mole.

This relation is given as-

  $totalnumberofmoles\times \frac{6.02\times {10}^{23}atoms}{1mol}$

Answer to Problem 5.83P

The number of molecules present in 222 mol of butane is $1.34\times {10}^{26}molecule$.

Explanation of Solution

The number of atoms or molecules present in a mole = $6.02\times {10}^{23}$

The conversion factor is to be chosen to cancel out the mol unit.

  $\frac{1mole}{6.02\times {10}^{23}atoms}$ or $\frac{6.02\times {10}^{23}atoms}{1mole}$

Solve the problem −

  $222mol\times \frac{6.02\times {10}^{23}molecule}{1mol}=1.34\times {10}^{26}molecule$

The number of molecules present in 222 mol of butane is $1.34\times {10}^{26}molecule$.

Interpretation Introduction

(d)

Interpretation:

The number of molecules present in $5.00\times {10}^{5}mol$ of butane $C_4{H}_{10}$ is to be determined.

Concept Introduction:

The total number of molecules is determined by the multiplication of the total number of moles with the number of a molecule present in a mole.

This relation is given as-

  $totalnumberofmoles\times \frac{6.02\times {10}^{23}atoms}{1mol}$

Answer to Problem 5.83P

The number of molecules present in $5.00\times {10}^{5}mol$ of butane is $3.01\times {10}^{29}molecule$.

Explanation of Solution

The number of atoms or molecules present in a mole = $6.02\times {10}^{23}$

The conversion factor is to be chosen to cancel out the mol unit.

  $\frac{1mole}{6.02\times {10}^{23}atoms}$ or $\frac{6.02\times {10}^{23}atoms}{1mole}$

Solve the problem −

  $5.00\times {10}^{5}mol\times \frac{6.02\times {10}^{23}molecule}{1mol}=3.01\times {10}^{29}molecule$

The number of molecules present in $5.00\times {10}^{5}mol$ of butane is $3.01\times {10}^{29}molecule$.