The given inter halogen compounds have to be arranged in increasing order of percentage of fluorine by mass. Concept introduction: Percent composition by mass of each element present in a compound is known as the compound’s percent composition by mass . Percent by mass of an element = n ×atomic mass of element molecular or formula mass of compound ×100% Where n is the number of atoms of the element in a molecule or formula unit of the compound

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Answer 1

Question

Chapter 5, Problem 5.78QP

Interpretation Introduction

Interpretation:

The given inter halogen compounds have to be arranged in increasing order of percentage of fluorine by mass.

Concept introduction:

Percent composition by mass of each element present in a compound is known as the compound’s percent composition by mass.

$Percent by mass of an element = n ×atomic mass of elementmolecular or formula mass of compound×100%Where n is the number of atoms of the element in a molecule or formula unit of the compound$

Expert Solution & Answer

Answer to Problem 5.78QP

The percentage of fluorine by mass of given inter halogen compounds was arranged in the increasing order as,

$IF5<BrF5<ClF3<ClF5$

$IF5$ contains the smallest percentage of fluorine by mass.

Explanation of Solution

Percent composition by mass: Percent composition by mass of each element present in a compound is known as the compound’s percent composition by mass. The formula is expressed mathematically as follows:

$Percent by mass of an element = n ×atomic mass of elementmolecular or formula mass of compound×100%Where n is the number of atoms of the element in a molecule or formula unit of the compound$ By using the above formula, percentage fluorine by mass of interhalogen compounds is calculated as follows:

$Percent by mass of % F in ClF3 = 3×atomic mass F in amumolecular mass of ClF3 in amu× 100% = 3×18.9984 amu92.448 amu× 100% = 61.62 %$

$Percent by mass of % F in BrF5 = 5×atomic mass F in amumolecular mass of BrF5 in amu× 100% = 5×18.9984 amu174.894 amu× 100% =54.31%$

$Percent by mass of % F in IF5 = 5×atomic mass F in amumolecular mass of IF5 in amu× 100% = 5×18.9984 amu221.89 amu× 100% = 42.79%$

$Percent by mass of % F in ClF5 = 3×atomic mass F in amumolecular mass of ClF5 in amu× 100% = 5×18.9984 amu130.445 amu× 100% = 72.82%$

Conclusion

The percentage fluorine by mass of interhalogen compounds was arranged in the below order:

$IF5<BrF5<ClF3<ClF5$

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Answer 2

Question

Chapter 5, Problem 5.78QP

Interpretation Introduction

Interpretation:

The given inter halogen compounds have to be arranged in increasing order of percentage of fluorine by mass.

Concept introduction:

Percent composition by mass of each element present in a compound is known as the compound’s percent composition by mass.

$Percent by mass of an element = n ×atomic mass of elementmolecular or formula mass of compound×100%Where n is the number of atoms of the element in a molecule or formula unit of the compound$

Expert Solution & Answer

Answer to Problem 5.78QP

The percentage of fluorine by mass of given inter halogen compounds was arranged in the increasing order as,

$IF5<BrF5<ClF3<ClF5$

$IF5$ contains the smallest percentage of fluorine by mass.

Explanation of Solution

Percent composition by mass: Percent composition by mass of each element present in a compound is known as the compound’s percent composition by mass. The formula is expressed mathematically as follows:

$Percent by mass of an element = n ×atomic mass of elementmolecular or formula mass of compound×100%Where n is the number of atoms of the element in a molecule or formula unit of the compound$ By using the above formula, percentage fluorine by mass of interhalogen compounds is calculated as follows:

$Percent by mass of % F in ClF3 = 3×atomic mass F in amumolecular mass of ClF3 in amu× 100% = 3×18.9984 amu92.448 amu× 100% = 61.62 %$

$Percent by mass of % F in BrF5 = 5×atomic mass F in amumolecular mass of BrF5 in amu× 100% = 5×18.9984 amu174.894 amu× 100% =54.31%$

$Percent by mass of % F in IF5 = 5×atomic mass F in amumolecular mass of IF5 in amu× 100% = 5×18.9984 amu221.89 amu× 100% = 42.79%$

$Percent by mass of % F in ClF5 = 3×atomic mass F in amumolecular mass of ClF5 in amu× 100% = 5×18.9984 amu130.445 amu× 100% = 72.82%$

Conclusion

The percentage fluorine by mass of interhalogen compounds was arranged in the below order:

$IF5<BrF5<ClF3<ClF5$

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Answer 3

Question

Chapter 5, Problem 5.78QP

Interpretation Introduction

Interpretation:

The given inter halogen compounds have to be arranged in increasing order of percentage of fluorine by mass.

Concept introduction:

Percent composition by mass of each element present in a compound is known as the compound’s percent composition by mass.

$Percent by mass of an element = n ×atomic mass of elementmolecular or formula mass of compound×100%Where n is the number of atoms of the element in a molecule or formula unit of the compound$

Expert Solution & Answer

Answer to Problem 5.78QP

The percentage of fluorine by mass of given inter halogen compounds was arranged in the increasing order as,

$IF5<BrF5<ClF3<ClF5$

$IF5$ contains the smallest percentage of fluorine by mass.

Explanation of Solution

Percent composition by mass: Percent composition by mass of each element present in a compound is known as the compound’s percent composition by mass. The formula is expressed mathematically as follows:

$Percent by mass of an element = n ×atomic mass of elementmolecular or formula mass of compound×100%Where n is the number of atoms of the element in a molecule or formula unit of the compound$ By using the above formula, percentage fluorine by mass of interhalogen compounds is calculated as follows:

$Percent by mass of % F in ClF3 = 3×atomic mass F in amumolecular mass of ClF3 in amu× 100% = 3×18.9984 amu92.448 amu× 100% = 61.62 %$

$Percent by mass of % F in BrF5 = 5×atomic mass F in amumolecular mass of BrF5 in amu× 100% = 5×18.9984 amu174.894 amu× 100% =54.31%$

$Percent by mass of % F in IF5 = 5×atomic mass F in amumolecular mass of IF5 in amu× 100% = 5×18.9984 amu221.89 amu× 100% = 42.79%$

$Percent by mass of % F in ClF5 = 3×atomic mass F in amumolecular mass of ClF5 in amu× 100% = 5×18.9984 amu130.445 amu× 100% = 72.82%$

Conclusion

The percentage fluorine by mass of interhalogen compounds was arranged in the below order:

$IF5<BrF5<ClF3<ClF5$

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Answer 4

Question

Chapter 5, Problem 5.78QP

Interpretation Introduction

Interpretation:

The given inter halogen compounds have to be arranged in increasing order of percentage of fluorine by mass.

Concept introduction:

Percent composition by mass of each element present in a compound is known as the compound’s percent composition by mass.

$Percent by mass of an element = n ×atomic mass of elementmolecular or formula mass of compound×100%Where n is the number of atoms of the element in a molecule or formula unit of the compound$

Expert Solution & Answer

Answer to Problem 5.78QP

The percentage of fluorine by mass of given inter halogen compounds was arranged in the increasing order as,

$IF5<BrF5<ClF3<ClF5$

$IF5$ contains the smallest percentage of fluorine by mass.

Explanation of Solution

Percent composition by mass: Percent composition by mass of each element present in a compound is known as the compound’s percent composition by mass. The formula is expressed mathematically as follows:

$Percent by mass of an element = n ×atomic mass of elementmolecular or formula mass of compound×100%Where n is the number of atoms of the element in a molecule or formula unit of the compound$ By using the above formula, percentage fluorine by mass of interhalogen compounds is calculated as follows:

$Percent by mass of % F in ClF3 = 3×atomic mass F in amumolecular mass of ClF3 in amu× 100% = 3×18.9984 amu92.448 amu× 100% = 61.62 %$

$Percent by mass of % F in BrF5 = 5×atomic mass F in amumolecular mass of BrF5 in amu× 100% = 5×18.9984 amu174.894 amu× 100% =54.31%$

$Percent by mass of % F in IF5 = 5×atomic mass F in amumolecular mass of IF5 in amu× 100% = 5×18.9984 amu221.89 amu× 100% = 42.79%$

$Percent by mass of % F in ClF5 = 3×atomic mass F in amumolecular mass of ClF5 in amu× 100% = 5×18.9984 amu130.445 amu× 100% = 72.82%$

Conclusion

The percentage fluorine by mass of interhalogen compounds was arranged in the below order:

$IF5<BrF5<ClF3<ClF5$

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Answer 5

Chapter 5, Problem 5.78QP

Interpretation Introduction

Interpretation:

The given inter halogen compounds have to be arranged in increasing order of percentage of fluorine by mass.

Concept introduction:

Percent composition by mass of each element present in a compound is known as the compound’s percent composition by mass.

$Percent by mass of an element = n ×atomic mass of elementmolecular or formula mass of compound×100%Where n is the number of atoms of the element in a molecule or formula unit of the compound$

Expert Solution & Answer

Answer to Problem 5.78QP

The percentage of fluorine by mass of given inter halogen compounds was arranged in the increasing order as,

$IF5<BrF5<ClF3<ClF5$

$IF5$ contains the smallest percentage of fluorine by mass.

Explanation of Solution

Percent composition by mass: Percent composition by mass of each element present in a compound is known as the compound’s percent composition by mass. The formula is expressed mathematically as follows:

$Percent by mass of an element = n ×atomic mass of elementmolecular or formula mass of compound×100%Where n is the number of atoms of the element in a molecule or formula unit of the compound$ By using the above formula, percentage fluorine by mass of interhalogen compounds is calculated as follows:

$Percent by mass of % F in ClF3 = 3×atomic mass F in amumolecular mass of ClF3 in amu× 100% = 3×18.9984 amu92.448 amu× 100% = 61.62 %$

$Percent by mass of % F in BrF5 = 5×atomic mass F in amumolecular mass of BrF5 in amu× 100% = 5×18.9984 amu174.894 amu× 100% =54.31%$

$Percent by mass of % F in IF5 = 5×atomic mass F in amumolecular mass of IF5 in amu× 100% = 5×18.9984 amu221.89 amu× 100% = 42.79%$

$Percent by mass of % F in ClF5 = 3×atomic mass F in amumolecular mass of ClF5 in amu× 100% = 5×18.9984 amu130.445 amu× 100% = 72.82%$

Conclusion

The percentage fluorine by mass of interhalogen compounds was arranged in the below order:

$IF5<BrF5<ClF3<ClF5$

Answer 6

Chapter 5, Problem 5.78QP

Interpretation Introduction

Interpretation:

The given inter halogen compounds have to be arranged in increasing order of percentage of fluorine by mass.

Concept introduction:

Percent composition by mass of each element present in a compound is known as the compound’s percent composition by mass.

$Percent by mass of an element = n ×atomic mass of elementmolecular or formula mass of compound×100%Where n is the number of atoms of the element in a molecule or formula unit of the compound$

Expert Solution & Answer

Answer to Problem 5.78QP

The percentage of fluorine by mass of given inter halogen compounds was arranged in the increasing order as,

$IF5<BrF5<ClF3<ClF5$

$IF5$ contains the smallest percentage of fluorine by mass.

Explanation of Solution

Percent composition by mass: Percent composition by mass of each element present in a compound is known as the compound’s percent composition by mass. The formula is expressed mathematically as follows:

$Percent by mass of an element = n ×atomic mass of elementmolecular or formula mass of compound×100%Where n is the number of atoms of the element in a molecule or formula unit of the compound$ By using the above formula, percentage fluorine by mass of interhalogen compounds is calculated as follows:

$Percent by mass of % F in ClF3 = 3×atomic mass F in amumolecular mass of ClF3 in amu× 100% = 3×18.9984 amu92.448 amu× 100% = 61.62 %$

$Percent by mass of % F in BrF5 = 5×atomic mass F in amumolecular mass of BrF5 in amu× 100% = 5×18.9984 amu174.894 amu× 100% =54.31%$

$Percent by mass of % F in IF5 = 5×atomic mass F in amumolecular mass of IF5 in amu× 100% = 5×18.9984 amu221.89 amu× 100% = 42.79%$

$Percent by mass of % F in ClF5 = 3×atomic mass F in amumolecular mass of ClF5 in amu× 100% = 5×18.9984 amu130.445 amu× 100% = 72.82%$

Conclusion

The percentage fluorine by mass of interhalogen compounds was arranged in the below order:

$IF5<BrF5<ClF3<ClF5$

Answer 7

Chapter 5, Problem 5.78QP

Interpretation Introduction

Interpretation:

The given inter halogen compounds have to be arranged in increasing order of percentage of fluorine by mass.

Concept introduction:

Percent composition by mass of each element present in a compound is known as the compound’s percent composition by mass.

$Percent by mass of an element = n ×atomic mass of elementmolecular or formula mass of compound×100%Where n is the number of atoms of the element in a molecule or formula unit of the compound$

Answer 8

Expert Solution & Answer

Answer to Problem 5.78QP

The percentage of fluorine by mass of given inter halogen compounds was arranged in the increasing order as,

$IF5<BrF5<ClF3<ClF5$

$IF5$ contains the smallest percentage of fluorine by mass.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Percent composition by mass: Percent composition by mass of each element present in a compound is known as the compound’s percent composition by mass. The formula is expressed mathematically as follows:

$Percent by mass of an element = n ×atomic mass of elementmolecular or formula mass of compound×100%Where n is the number of atoms of the element in a molecule or formula unit of the compound$ By using the above formula, percentage fluorine by mass of interhalogen compounds is calculated as follows:

$Percent by mass of % F in ClF3 = 3×atomic mass F in amumolecular mass of ClF3 in amu× 100% = 3×18.9984 amu92.448 amu× 100% = 61.62 %$

$Percent by mass of % F in BrF5 = 5×atomic mass F in amumolecular mass of BrF5 in amu× 100% = 5×18.9984 amu174.894 amu× 100% =54.31%$

$Percent by mass of % F in IF5 = 5×atomic mass F in amumolecular mass of IF5 in amu× 100% = 5×18.9984 amu221.89 amu× 100% = 42.79%$

$Percent by mass of % F in ClF5 = 3×atomic mass F in amumolecular mass of ClF5 in amu× 100% = 5×18.9984 amu130.445 amu× 100% = 72.82%$

Answer 12

Conclusion

The percentage fluorine by mass of interhalogen compounds was arranged in the below order:

$IF5<BrF5<ClF3<ClF5$

Answer 13

Ch. 5.2 - Write Lewis dot symbols for (a) fluoride ion (F),...Ch. 5.2 - Write Lewis dot symbols for (a) Ca2+, (b) N3 and...Ch. 5.2 - Indicate the charge on each of the ions...Ch. 5.2 - Prob. 1PPC Ch. 5.2 - Prob. 5.2.1SR Ch. 5.2 - Prob. 5.2.2SR Ch. 5.2 - Prob. 5.2.3SR Ch. 5.2 - Prob. 5.2.4SR Ch. 5.3 - Arrange MgO, CaO, and SrO in order of increasing...Ch. 5.3 - Prob. 2PPA

Answer to Problem 5.78QP

Explanation of Solution

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Chapter 5 Solutions