The molecular mass of the given substances has to be calculated. Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass . Some atomic weight of atoms are, C = 12 .0107 amu H = 1 .0079 amu Cl = 35 .453 amu N = 14 .0067 amu O = 15 .9994 amu S = 32 .065 amu To calculate: Molecular mass of CH 3 Cl

Question

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Answer 1

Question

Chapter 5, Problem 5.67QP

(a)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $CH3Cl$

(a)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $CH3Cl = 50.4874 amu$

Explanation of Solution

$Molecular mass of CH3Cl = 1(mass of C in amu) + 3(mass of H in amu) + 1(mass of Cl in amu) = 1(12.0107 amu) + 3(1.0079 amu) + 1(35.453 amu) = (12.0107 + 3.0237 + 35.453)amu = 50.4874 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $CH3Cl$ was found to be $50.4874 amu$ .

(b)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $N2O4$

(b)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $N2O4 = 92.02894 amu$

Explanation of Solution

Molecular formula is given as $N2O4$

$Molecular mass of N2O4 = 2(mass of N in amu) + 4(mass of O in amu) = 2(14.0067 amu) + 4(15.9994 amu) = (28.0134 + 63.9976)amu = 92.02894 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $N2O4$ was found to be $92.02894 amu$ .

(C)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $SO2$

(C)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $SO2 = 64.0638 amu$

Explanation of Solution

Molecular formula is given as $SO2$

$Molecular mass of SO2 =1(mass of S in amu) + 2(mass of O in amu) = 1(32.065 amu) + 2(15.9994 amu) = (32.065 + 31.9988)amu = 64.0638 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $SO2$ was found to be $64.0638 amu$ .

(d)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $C6H12$

(d)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $C6H12 = 84.159 amu$

Explanation of Solution

Molecular formula is given as $C6H12$

$Molecular mass of C6H12 = 6(mass of C in amu) + 12(mass of H in amu) = 6(12.0107 amu) + 12(1.0079 amu) = (72.0642 + 12.0948)amu = 84.159 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $C6H12$ was found to be $84.159 amu$

(e)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $H2O2$

(e)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $H2O2 = 34.0146 amu$

Explanation of Solution

Molecular formula is given as $H2O2$

$Molecular mass of H2O2 = 2(mass of H in amu) + 2(mass of O in amu) = 2(1.0079 amu) + 2(15.9994 amu) = (2.0158 + 31.9988)amu = 34.0146 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $H2O2$ was found to be $34.0146 amu$ .

(f)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

(f)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $C12H22O11 = 342.3 amu$

To calculate: Molecular mass of $C12H22O11$

Explanation of Solution

Molecular formula is given as $C12H22O11$

$Molecular mass of C12H22O11 = 12(mass of C in amu) + 22(mass of H in amu) + 11(mass of O in amu) = 12(12.0107 amu) + 22(1.0079) + 11(15.9994 amu) = (144.1284 + 22.1738 + 175.9934)amu = 342.3 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $C12H22O11$ was found to be $342.3 amu$ .

(g)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

(g)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $NH3 = 17.0304 amu$

To calculate: Molecular mass of $NH3$

Explanation of Solution

Molecular formula is given as $NH3$

$Molecular mass of NH3 = 1(mass of N in amu) + 3(mass of H in amu) = 1(14.0067 amu) + 3(1.0079 amu) = (14.0067 + 3.0237)amu = 17.0304 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $NH3$ was found to be $17.0304 amu$ .

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Answer 2

Question

Chapter 5, Problem 5.67QP

(a)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $CH3Cl$

(a)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $CH3Cl = 50.4874 amu$

Explanation of Solution

$Molecular mass of CH3Cl = 1(mass of C in amu) + 3(mass of H in amu) + 1(mass of Cl in amu) = 1(12.0107 amu) + 3(1.0079 amu) + 1(35.453 amu) = (12.0107 + 3.0237 + 35.453)amu = 50.4874 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $CH3Cl$ was found to be $50.4874 amu$ .

(b)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $N2O4$

(b)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $N2O4 = 92.02894 amu$

Explanation of Solution

Molecular formula is given as $N2O4$

$Molecular mass of N2O4 = 2(mass of N in amu) + 4(mass of O in amu) = 2(14.0067 amu) + 4(15.9994 amu) = (28.0134 + 63.9976)amu = 92.02894 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $N2O4$ was found to be $92.02894 amu$ .

(C)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $SO2$

(C)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $SO2 = 64.0638 amu$

Explanation of Solution

Molecular formula is given as $SO2$

$Molecular mass of SO2 =1(mass of S in amu) + 2(mass of O in amu) = 1(32.065 amu) + 2(15.9994 amu) = (32.065 + 31.9988)amu = 64.0638 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $SO2$ was found to be $64.0638 amu$ .

(d)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $C6H12$

(d)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $C6H12 = 84.159 amu$

Explanation of Solution

Molecular formula is given as $C6H12$

$Molecular mass of C6H12 = 6(mass of C in amu) + 12(mass of H in amu) = 6(12.0107 amu) + 12(1.0079 amu) = (72.0642 + 12.0948)amu = 84.159 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $C6H12$ was found to be $84.159 amu$

(e)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $H2O2$

(e)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $H2O2 = 34.0146 amu$

Explanation of Solution

Molecular formula is given as $H2O2$

$Molecular mass of H2O2 = 2(mass of H in amu) + 2(mass of O in amu) = 2(1.0079 amu) + 2(15.9994 amu) = (2.0158 + 31.9988)amu = 34.0146 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $H2O2$ was found to be $34.0146 amu$ .

(f)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

(f)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $C12H22O11 = 342.3 amu$

To calculate: Molecular mass of $C12H22O11$

Explanation of Solution

Molecular formula is given as $C12H22O11$

$Molecular mass of C12H22O11 = 12(mass of C in amu) + 22(mass of H in amu) + 11(mass of O in amu) = 12(12.0107 amu) + 22(1.0079) + 11(15.9994 amu) = (144.1284 + 22.1738 + 175.9934)amu = 342.3 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $C12H22O11$ was found to be $342.3 amu$ .

(g)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

(g)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $NH3 = 17.0304 amu$

To calculate: Molecular mass of $NH3$

Explanation of Solution

Molecular formula is given as $NH3$

$Molecular mass of NH3 = 1(mass of N in amu) + 3(mass of H in amu) = 1(14.0067 amu) + 3(1.0079 amu) = (14.0067 + 3.0237)amu = 17.0304 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $NH3$ was found to be $17.0304 amu$ .

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Answer 3

Question

Chapter 5, Problem 5.67QP

(a)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $CH3Cl$

(a)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $CH3Cl = 50.4874 amu$

Explanation of Solution

$Molecular mass of CH3Cl = 1(mass of C in amu) + 3(mass of H in amu) + 1(mass of Cl in amu) = 1(12.0107 amu) + 3(1.0079 amu) + 1(35.453 amu) = (12.0107 + 3.0237 + 35.453)amu = 50.4874 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $CH3Cl$ was found to be $50.4874 amu$ .

(b)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $N2O4$

(b)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $N2O4 = 92.02894 amu$

Explanation of Solution

Molecular formula is given as $N2O4$

$Molecular mass of N2O4 = 2(mass of N in amu) + 4(mass of O in amu) = 2(14.0067 amu) + 4(15.9994 amu) = (28.0134 + 63.9976)amu = 92.02894 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $N2O4$ was found to be $92.02894 amu$ .

(C)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $SO2$

(C)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $SO2 = 64.0638 amu$

Explanation of Solution

Molecular formula is given as $SO2$

$Molecular mass of SO2 =1(mass of S in amu) + 2(mass of O in amu) = 1(32.065 amu) + 2(15.9994 amu) = (32.065 + 31.9988)amu = 64.0638 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $SO2$ was found to be $64.0638 amu$ .

(d)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $C6H12$

(d)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $C6H12 = 84.159 amu$

Explanation of Solution

Molecular formula is given as $C6H12$

$Molecular mass of C6H12 = 6(mass of C in amu) + 12(mass of H in amu) = 6(12.0107 amu) + 12(1.0079 amu) = (72.0642 + 12.0948)amu = 84.159 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $C6H12$ was found to be $84.159 amu$

(e)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $H2O2$

(e)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $H2O2 = 34.0146 amu$

Explanation of Solution

Molecular formula is given as $H2O2$

$Molecular mass of H2O2 = 2(mass of H in amu) + 2(mass of O in amu) = 2(1.0079 amu) + 2(15.9994 amu) = (2.0158 + 31.9988)amu = 34.0146 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $H2O2$ was found to be $34.0146 amu$ .

(f)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

(f)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $C12H22O11 = 342.3 amu$

To calculate: Molecular mass of $C12H22O11$

Explanation of Solution

Molecular formula is given as $C12H22O11$

$Molecular mass of C12H22O11 = 12(mass of C in amu) + 22(mass of H in amu) + 11(mass of O in amu) = 12(12.0107 amu) + 22(1.0079) + 11(15.9994 amu) = (144.1284 + 22.1738 + 175.9934)amu = 342.3 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $C12H22O11$ was found to be $342.3 amu$ .

(g)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

(g)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $NH3 = 17.0304 amu$

To calculate: Molecular mass of $NH3$

Explanation of Solution

Molecular formula is given as $NH3$

$Molecular mass of NH3 = 1(mass of N in amu) + 3(mass of H in amu) = 1(14.0067 amu) + 3(1.0079 amu) = (14.0067 + 3.0237)amu = 17.0304 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $NH3$ was found to be $17.0304 amu$ .

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Answer 4

Question

Chapter 5, Problem 5.67QP

(a)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $CH3Cl$

(a)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $CH3Cl = 50.4874 amu$

Explanation of Solution

$Molecular mass of CH3Cl = 1(mass of C in amu) + 3(mass of H in amu) + 1(mass of Cl in amu) = 1(12.0107 amu) + 3(1.0079 amu) + 1(35.453 amu) = (12.0107 + 3.0237 + 35.453)amu = 50.4874 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $CH3Cl$ was found to be $50.4874 amu$ .

(b)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $N2O4$

(b)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $N2O4 = 92.02894 amu$

Explanation of Solution

Molecular formula is given as $N2O4$

$Molecular mass of N2O4 = 2(mass of N in amu) + 4(mass of O in amu) = 2(14.0067 amu) + 4(15.9994 amu) = (28.0134 + 63.9976)amu = 92.02894 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $N2O4$ was found to be $92.02894 amu$ .

(C)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $SO2$

(C)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $SO2 = 64.0638 amu$

Explanation of Solution

Molecular formula is given as $SO2$

$Molecular mass of SO2 =1(mass of S in amu) + 2(mass of O in amu) = 1(32.065 amu) + 2(15.9994 amu) = (32.065 + 31.9988)amu = 64.0638 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $SO2$ was found to be $64.0638 amu$ .

(d)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $C6H12$

(d)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $C6H12 = 84.159 amu$

Explanation of Solution

Molecular formula is given as $C6H12$

$Molecular mass of C6H12 = 6(mass of C in amu) + 12(mass of H in amu) = 6(12.0107 amu) + 12(1.0079 amu) = (72.0642 + 12.0948)amu = 84.159 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $C6H12$ was found to be $84.159 amu$

(e)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $H2O2$

(e)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $H2O2 = 34.0146 amu$

Explanation of Solution

Molecular formula is given as $H2O2$

$Molecular mass of H2O2 = 2(mass of H in amu) + 2(mass of O in amu) = 2(1.0079 amu) + 2(15.9994 amu) = (2.0158 + 31.9988)amu = 34.0146 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $H2O2$ was found to be $34.0146 amu$ .

(f)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

(f)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $C12H22O11 = 342.3 amu$

To calculate: Molecular mass of $C12H22O11$

Explanation of Solution

Molecular formula is given as $C12H22O11$

$Molecular mass of C12H22O11 = 12(mass of C in amu) + 22(mass of H in amu) + 11(mass of O in amu) = 12(12.0107 amu) + 22(1.0079) + 11(15.9994 amu) = (144.1284 + 22.1738 + 175.9934)amu = 342.3 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $C12H22O11$ was found to be $342.3 amu$ .

(g)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

(g)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $NH3 = 17.0304 amu$

To calculate: Molecular mass of $NH3$

Explanation of Solution

Molecular formula is given as $NH3$

$Molecular mass of NH3 = 1(mass of N in amu) + 3(mass of H in amu) = 1(14.0067 amu) + 3(1.0079 amu) = (14.0067 + 3.0237)amu = 17.0304 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $NH3$ was found to be $17.0304 amu$ .

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Answer 5

Chapter 5, Problem 5.67QP

(a)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $CH3Cl$

(a)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $CH3Cl = 50.4874 amu$

Explanation of Solution

$Molecular mass of CH3Cl = 1(mass of C in amu) + 3(mass of H in amu) + 1(mass of Cl in amu) = 1(12.0107 amu) + 3(1.0079 amu) + 1(35.453 amu) = (12.0107 + 3.0237 + 35.453)amu = 50.4874 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $CH3Cl$ was found to be $50.4874 amu$ .

(b)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $N2O4$

(b)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $N2O4 = 92.02894 amu$

Explanation of Solution

Molecular formula is given as $N2O4$

$Molecular mass of N2O4 = 2(mass of N in amu) + 4(mass of O in amu) = 2(14.0067 amu) + 4(15.9994 amu) = (28.0134 + 63.9976)amu = 92.02894 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $N2O4$ was found to be $92.02894 amu$ .

(C)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $SO2$

(C)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $SO2 = 64.0638 amu$

Explanation of Solution

Molecular formula is given as $SO2$

$Molecular mass of SO2 =1(mass of S in amu) + 2(mass of O in amu) = 1(32.065 amu) + 2(15.9994 amu) = (32.065 + 31.9988)amu = 64.0638 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $SO2$ was found to be $64.0638 amu$ .

(d)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $C6H12$

(d)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $C6H12 = 84.159 amu$

Explanation of Solution

Molecular formula is given as $C6H12$

$Molecular mass of C6H12 = 6(mass of C in amu) + 12(mass of H in amu) = 6(12.0107 amu) + 12(1.0079 amu) = (72.0642 + 12.0948)amu = 84.159 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $C6H12$ was found to be $84.159 amu$

(e)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $H2O2$

(e)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $H2O2 = 34.0146 amu$

Explanation of Solution

Molecular formula is given as $H2O2$

$Molecular mass of H2O2 = 2(mass of H in amu) + 2(mass of O in amu) = 2(1.0079 amu) + 2(15.9994 amu) = (2.0158 + 31.9988)amu = 34.0146 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $H2O2$ was found to be $34.0146 amu$ .

(f)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

(f)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $C12H22O11 = 342.3 amu$

To calculate: Molecular mass of $C12H22O11$

Explanation of Solution

Molecular formula is given as $C12H22O11$

$Molecular mass of C12H22O11 = 12(mass of C in amu) + 22(mass of H in amu) + 11(mass of O in amu) = 12(12.0107 amu) + 22(1.0079) + 11(15.9994 amu) = (144.1284 + 22.1738 + 175.9934)amu = 342.3 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $C12H22O11$ was found to be $342.3 amu$ .

(g)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

(g)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $NH3 = 17.0304 amu$

To calculate: Molecular mass of $NH3$

Explanation of Solution

Molecular formula is given as $NH3$

$Molecular mass of NH3 = 1(mass of N in amu) + 3(mass of H in amu) = 1(14.0067 amu) + 3(1.0079 amu) = (14.0067 + 3.0237)amu = 17.0304 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $NH3$ was found to be $17.0304 amu$ .

Answer 6

Chapter 5, Problem 5.67QP

(a)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $CH3Cl$

(a)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $CH3Cl = 50.4874 amu$

Explanation of Solution

$Molecular mass of CH3Cl = 1(mass of C in amu) + 3(mass of H in amu) + 1(mass of Cl in amu) = 1(12.0107 amu) + 3(1.0079 amu) + 1(35.453 amu) = (12.0107 + 3.0237 + 35.453)amu = 50.4874 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $CH3Cl$ was found to be $50.4874 amu$ .

Answer 7

Chapter 5, Problem 5.67QP

(a)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $CH3Cl$

Answer 8

(a)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $CH3Cl = 50.4874 amu$

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

$Molecular mass of CH3Cl = 1(mass of C in amu) + 3(mass of H in amu) + 1(mass of Cl in amu) = 1(12.0107 amu) + 3(1.0079 amu) + 1(35.453 amu) = (12.0107 + 3.0237 + 35.453)amu = 50.4874 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $CH3Cl$ was found to be $50.4874 amu$ .

Answer 13

(b)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $N2O4$

(b)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $N2O4 = 92.02894 amu$

Explanation of Solution

Molecular formula is given as $N2O4$

$Molecular mass of N2O4 = 2(mass of N in amu) + 4(mass of O in amu) = 2(14.0067 amu) + 4(15.9994 amu) = (28.0134 + 63.9976)amu = 92.02894 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $N2O4$ was found to be $92.02894 amu$ .

Answer 14

(b)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $N2O4$

Answer 15

(b)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $N2O4 = 92.02894 amu$

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Molecular formula is given as $N2O4$

$Molecular mass of N2O4 = 2(mass of N in amu) + 4(mass of O in amu) = 2(14.0067 amu) + 4(15.9994 amu) = (28.0134 + 63.9976)amu = 92.02894 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $N2O4$ was found to be $92.02894 amu$ .

Answer 20

(C)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $SO2$

(C)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $SO2 = 64.0638 amu$

Explanation of Solution

Molecular formula is given as $SO2$

$Molecular mass of SO2 =1(mass of S in amu) + 2(mass of O in amu) = 1(32.065 amu) + 2(15.9994 amu) = (32.065 + 31.9988)amu = 64.0638 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $SO2$ was found to be $64.0638 amu$ .

Answer 21

(C)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $SO2$

Answer 22

(C)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $SO2 = 64.0638 amu$

Answer 23

(C)

Expert Solution

Answer 24

(C)

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Molecular formula is given as $SO2$

$Molecular mass of SO2 =1(mass of S in amu) + 2(mass of O in amu) = 1(32.065 amu) + 2(15.9994 amu) = (32.065 + 31.9988)amu = 64.0638 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $SO2$ was found to be $64.0638 amu$ .

Answer 27

(d)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $C6H12$

(d)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $C6H12 = 84.159 amu$

Explanation of Solution

Molecular formula is given as $C6H12$

$Molecular mass of C6H12 = 6(mass of C in amu) + 12(mass of H in amu) = 6(12.0107 amu) + 12(1.0079 amu) = (72.0642 + 12.0948)amu = 84.159 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $C6H12$ was found to be $84.159 amu$

Answer 28

(d)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $C6H12$

Answer 29

(d)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $C6H12 = 84.159 amu$

Answer 30

(d)

Expert Solution

Answer 31

(d)

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

Molecular formula is given as $C6H12$

$Molecular mass of C6H12 = 6(mass of C in amu) + 12(mass of H in amu) = 6(12.0107 amu) + 12(1.0079 amu) = (72.0642 + 12.0948)amu = 84.159 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $C6H12$ was found to be $84.159 amu$

Answer 34

(e)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $H2O2$

(e)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $H2O2 = 34.0146 amu$

Explanation of Solution

Molecular formula is given as $H2O2$

$Molecular mass of H2O2 = 2(mass of H in amu) + 2(mass of O in amu) = 2(1.0079 amu) + 2(15.9994 amu) = (2.0158 + 31.9988)amu = 34.0146 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $H2O2$ was found to be $34.0146 amu$ .

Answer 35

(e)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

To calculate: Molecular mass of $H2O2$

Answer 36

(e)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $H2O2 = 34.0146 amu$

Answer 37

(e)

Expert Solution

Answer 38

(e)

Expert Solution

Answer 39

Expert Solution

Answer 40

Explanation of Solution

Molecular formula is given as $H2O2$

$Molecular mass of H2O2 = 2(mass of H in amu) + 2(mass of O in amu) = 2(1.0079 amu) + 2(15.9994 amu) = (2.0158 + 31.9988)amu = 34.0146 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $H2O2$ was found to be $34.0146 amu$ .

Answer 41

(f)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

(f)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $C12H22O11 = 342.3 amu$

To calculate: Molecular mass of $C12H22O11$

Explanation of Solution

Molecular formula is given as $C12H22O11$

$Molecular mass of C12H22O11 = 12(mass of C in amu) + 22(mass of H in amu) + 11(mass of O in amu) = 12(12.0107 amu) + 22(1.0079) + 11(15.9994 amu) = (144.1284 + 22.1738 + 175.9934)amu = 342.3 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $C12H22O11$ was found to be $342.3 amu$ .

Answer 42

(f)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

Answer 43

(f)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $C12H22O11 = 342.3 amu$

To calculate: Molecular mass of $C12H22O11$

Answer 44

(f)

Expert Solution

Answer 45

(f)

Expert Solution

Answer 46

Expert Solution

Answer 47

Explanation of Solution

Molecular formula is given as $C12H22O11$

$Molecular mass of C12H22O11 = 12(mass of C in amu) + 22(mass of H in amu) + 11(mass of O in amu) = 12(12.0107 amu) + 22(1.0079) + 11(15.9994 amu) = (144.1284 + 22.1738 + 175.9934)amu = 342.3 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $C12H22O11$ was found to be $342.3 amu$ .

Answer 48

(g)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

(g)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $NH3 = 17.0304 amu$

To calculate: Molecular mass of $NH3$

Explanation of Solution

Molecular formula is given as $NH3$

$Molecular mass of NH3 = 1(mass of N in amu) + 3(mass of H in amu) = 1(14.0067 amu) + 3(1.0079 amu) = (14.0067 + 3.0237)amu = 17.0304 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $NH3$ was found to be $17.0304 amu$ .

Answer 49

(g)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

$C = 12.0107 amuH = 1.0079 amuCl = 35.453 amuN = 14.0067 amuO = 15.9994 amuS = 32.065 amu$

Answer 50

(g)

Expert Solution

Answer to Problem 5.67QP

Molecular mass of $NH3 = 17.0304 amu$

To calculate: Molecular mass of $NH3$

Answer 51

(g)

Expert Solution

Answer 52

(g)

Expert Solution

Answer 53

Expert Solution

Answer 54

Explanation of Solution

Molecular formula is given as $NH3$

$Molecular mass of NH3 = 1(mass of N in amu) + 3(mass of H in amu) = 1(14.0067 amu) + 3(1.0079 amu) = (14.0067 + 3.0237)amu = 17.0304 amu$

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of $NH3$ was found to be $17.0304 amu$ .