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(a)
Interpretation:
Three different flasks that contain
Concept introduction:
The ideal gas equation can be expressed as follows:
Here,
The expression to calculate the moles of gas is as follows:
(b)
Interpretation:
Three different flasks that contain
Concept introduction:
The expression to calculate the average kinetic energy of gases is as follows:
Here,
The expression to calculate the kinetic energy is as follows:
The kinetic energy is directly proportional to the temperature.
(c)
Interpretation:
Three different flasks that contain
Concept introduction:
Effusion is explained as the movement of the gas molecule through a pinhole.
Diffusion can be explained as the mixing of one gas molecule with another gas molecule by random motion.
According to Graham’s law of effusion, the rate of effusion of a gas is inversely proportional to the square root of its molar mass.
The mathematical expression of Graham’s law of effusion is as follows:
Here,
(d)
Interpretation:
Three different flasks that contain
Concept introduction:
The expression to calculate the root-mean-square speed is as follows:
Here,
The expression to calculate the average kinetic energy of gases is as follows:
Here,
The expression to calculate the kinetic energy is as follows:
The kinetic energy is directly proportional to the temperature.
(e)
Interpretation:
Three different flasks that contain
Concept introduction:
The expression to calculate the density of the air is as follows,
Here,
Rate of diffusion is inversely proportional to the square root of the density of the gas.
The expression to calculate the density of a gas is as follows:
(f)
Interpretation:
Three different flasks that contain
Concept introduction:
The mean free path can be defined as the average distance traveled by the gas molecule during a collision. There are many factors that affect the mean free path such as pressure, temperature, density and radius of the molecule.
The collision frequency is defined as the ratio of the most probable speed to the mean free path.
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Chapter 5 Solutions
Chemistry: The Molecular Nature of Matter and Change - Standalone book
- Redraw the flowchartarrow_forwardredraw the flowchart with boxes and molecules written in themarrow_forwardPart I. a) Elucidate the structure of compound A using the following information. • mass spectrum: m+ = 102, m/2=57 312=29 • IR spectrum: 1002.5 % TRANSMITTANCE Ngg 50 40 30 20 90 80 70 60 MICRONS 5 8 9 10 12 13 14 15 16 19 1740 cm M 10 0 4000 3600 3200 2800 2400 2000 1800 1600 13 • CNMR 'H -NMR Peak 8 ppm (H) Integration multiplicity a 1.5 (3H) triplet b 1.3 1.5 (3H) triplet C 2.3 1 (2H) quartet d 4.1 1 (2H) quartet & ppm (c) 10 15 28 60 177 (C=0) b) Elucidate the structure of compound B using the following information 13C/DEPT NMR 150.9 MHz IIL 1400 WAVENUMBERS (CM-1) DEPT-90 DEPT-135 85 80 75 70 65 60 55 50 45 40 35 30 25 20 ppm 1200 1000 800 600 400arrow_forward
- • Part II. a) Elucidate The structure of compound c w/ molecular formula C10 11202 and the following data below: • IR spectra % TRANSMITTANCE 1002.5 90 80 70 60 50 40 30 20 10 0 4000 3600 3200 2800 2400 2000 1800 1600 • Information from 'HAMR MICRONS 8 9 10 11 14 15 16 19 25 1400 WAVENUMBERS (CM-1) 1200 1000 800 600 400 peak 8 ppm Integration multiplicity a 2.1 1.5 (3H) Singlet b 3.6 1 (2H) singlet с 3.8 1.5 (3H) Singlet d 6.8 1(2H) doublet 7.1 1(2H) doublet Information from 13C-nmR Normal carbon 29ppm Dept 135 Dept -90 + NO peak NO peak 50 ppm 55 ppm + NO peak 114 ppm t 126 ppm No peak NO peak 130 ppm t + 159 ppm No peak NO peak 207 ppm по реак NO peakarrow_forwardCould you redraw these and also explain how to solve them for me pleasarrow_forwardNonearrow_forward
- Draw the curved-arrow mechanism with the drawings of the molecules, not just abbreviations. -NO₂ Sn, HCl (aq) E D H (CH3CO)₂O -NH2 CH3arrow_forwardWhat is/are the product(s) of the following reaction? Select all that apply. * HI A B C OD OH A B OH D Carrow_forwardIn the image, the light blue sphere represents a mole of hydrogen atoms, the purple or teal spheres represent a mole of a conjugate base. A light blue sphere by itself is H+. Assuming there is 2.00 L of solution, answer the following: The Ka of the left & right solution is? The pH of the left & right solution is? The acid on the left & right is what kind of acid?arrow_forward
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