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(a)
Interpretation:
The volume of ideal gas increases or decreases when the pressure is tripled is to be identified.
Concept introduction:
According to Boyle’s law, the volume occupied by the gas is inversely proportional to the pressure at the constant temperature.
The relationship between pressure and volume can be expressed as follows,
Here,
According to Charles's law, the volume occupied by the gas is directly proportional to the temperature at the constant pressure.
The relationship between pressure and temperature can be expressed as follows,
Here,
According to Avogadro’s law, the volume occupied by the gas is directly proportional to the mole of the gas at the constant pressure and temperature.
The relationship between volume and mole can be expressed as follows,
Here,
The ideal gas equation can be expressed as follows,
Here,
(b)
Interpretation:
The volume of ideal gas increases or decreases when the temperature is increased by factor 3 is to be identified.
Concept introduction:
According to Boyle’s law, the volume occupied by the gas is inversely proportional to the pressure at the constant temperature.
The relationship between pressure and volume can be expressed as follows,
Here,
According to Charles's law, the volume occupied by the gas is directly proportional to the temperature at the constant pressure.
The relationship between pressure and temperature can be expressed as follows,
Here,
According to Avogadro’s law, the volume occupied by the gas is directly proportional to the mole of the gas at the constant pressure and temperature.
The relationship between volume and mole can be expressed as follows,
Here,
The ideal gas equation can be expressed as follows,
Here,
(c)
Interpretation:
The volume of ideal gas increases or decreases when three moles of the gas is added is to be identified.
Concept introduction:
According to Boyle’s law, the volume occupied by the gas is inversely proportional to the pressure at the constant temperature.
The relationship between pressure and volume can be expressed as follows,
Here,
According to Charles's law, the volume occupied by the gas is directly proportional to the temperature at the constant pressure.
The relationship between pressure and temperature can be expressed as follows,
Here,
According to Avogadro’s law, the volume occupied by the gas is directly proportional to the mole of the gas at the constant pressure and temperature.
The relationship between volume and mole can be expressed as follows,
Here,
The ideal gas equation can be expressed as follows,
Here,
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Chapter 5 Solutions
Chemistry: The Molecular Nature of Matter and Change - Standalone book
- true or false The equilibrium constant for this reaction is 0.20. N2O4(g) ⇔ 2NO2(g) Based on the above, the equilibrium constant for the following reaction is 5. 4NO2(g) ⇔ 2N2O4(g)arrow_forwardtrue or false The equilibrium constant for this reaction is 0.20. N2O4(g) ⇔ 2NO2(g) Based on the above, the equilibrium constant for the following reaction is 0.4. 2N2O4(g) ⇔ 4NO2(g)arrow_forwardtrue or false Using the following equilibrium, if heat is added the equilibrium will shift toward the reactants. N2(g) + 3H2(g) ⇔ 2NH3(g) + heatarrow_forward
- True or False Using the following equilibrium, if heat is added the equilibrium will shift toward the products. N2O4(g) + heat ⇔ 2NO2(g)arrow_forwardtrue or false Using the following equilibrium, if solid carbon is added the equilibrium will shift toward the products. C(s) + CO2(g) ⇔ 2CO(g)arrow_forwardProvide the complete mechanism for the reaction below. You must include appropriate arrows,intermediates, and formal charges. Please also provide a reason to explain why the 1,4-adduct is preferred over the 1,3-adduct.arrow_forward
- Which of the following pairs are resonance structures of one another? I. III. || III IV + II. :0: n P !༠ IV. EN: Narrow_forwardPredict the major organic product(s) and byproducts (either organic or inorganic) for thefollowing reactions.arrow_forwardA 8.25 g sample of aluminum at 55°C released 2500 J of heat. The specific heat of aluminum is 0.900 J/g°C. The density of aluminum is 2.70 g/mL. Calculate the final temperature of the aluminum sample in °C.arrow_forward
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