
Concept explainers
(a)
Interpretation:
The mass of two samples of gas one contains
Concept introduction:
The ideal gas equation can be expressed as follows,
Here,
(b)
Interpretation:
The density of two samples of gas one is
Concept introduction:
The expression to calculate the density of the gas is as follows,
Here,
(c)
Interpretation:
The mean free path of two samples of gas one is
Concept introduction:
The mean free path can be defined as the average distance travelled by the gas molecule during a collision. There are many factors that affect the mean free path such as pressure, temperature, density and radius of the molecule.
(d)
Interpretation:
The average molecular kinetic energy of two samples of gas one is
Concept introduction:
The expression to calculate the kinetic energy is as follows:
Here,
The kinetic energy is directly proportional to the temperature.
(e)
Interpretation:
The average molecular speed of two samples of gas one is
Concept introduction:
The expression to calculate the root-mean-square velocity is as follows:
Here,
The kinetic energy is directly proportional to the temperature and inversely proportional to the molar mass.
(f)
Interpretation:
The time taken for the effusion of two samples of gas one is
Concept introduction:
The mathematical expression of Graham’s law of effusion is as follows:
Here,

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Chapter 5 Solutions
Student Solutions Manual For Silberberg Chemistry: The Molecular Nature Of Matter And Change With Advanced Topics
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